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JABATAN PENDIDIKAN NEGERI PERAK
MOCK TEST 1SIJIL PELAJARAN MALAYSIA (SPM)
KIMIATINGKATAN 5
MARKING SCHEME
SKEMA PEMARKAHAN
SULIT 2 4541
No Explanation Mark ∑ mark1 (a) (i) Able to state the energy conversion
AnswerChemical Electrical 1 1
(ii) Able to state the negative terminal & reasonAnswer(1) Magnesium / Mg (2) Magnesium / Mg is more electropositive // higher
position in Electrochemical Series // higher tendency to release electron
1 1 2
(iii) Able to write the half equationAnswerMg Mg2 + + 2e 1 1
(iv) Able to state the observationSample answerBrown solid deposited // copper electrode becomes thicker
1 1
(b) (i) Able to state the ions presentAnswerCl -, OH – // chloride ion, hydroxide ion 1 1
(ii) Able to name gas Y collectedAnswerChlorine 1 1
(iii) Able to calculate the mass of gas collected
1. No. of mole of gas = 12 / 24 000 // 0.0005 2. Mass of gas = 0.0005 x 71 g // 0.0355 g
11 2
Total 9
Skema-Mock Test 1 – Kimia SPM
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SULIT 3 4541
No Explanation Mark ∑ mark2 (a) (i) C4H8 1 1
(ii)
Choose : 2 structural formula
without name
1
1
1
Maks 2
(b) (1) Butene is an unsaturated hydrocarbon/ has double bond between carbon atoms(2) Butane is a saturated hydrocarbon/ has single bond
1
1 2
(c) C4H8 + H2 C4H10
- correct reactants and products1 1
(d)
- Functional diagram- Labelled diagram 1
1 2
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Glass wool soaked in butanol
SULIT 4 4541
(e) Percentage of carbon by mass in hexane, C6H14
= 6(12) x 100% 6(12) + 14(1)
= 83.72%
Percentage of carbon by mass in hexene, C6H12
= 6(12) x 100% 6(12) + 12(1)
= 85.71%
Hexene contains higher percentage of carbon by mass than hexane//Hexene burnt in air produces more soot compared to hexane.
1
1
1 3
Total 11
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SULIT 5 4541
No Explanation Mark ∑ mark
3 (a) (i) Soluble salts – sodium chlorideInsoluble salt – lead (II) sulphate*Note – accept any correct soluble and insoluble salt.
11
4
(ii) Pb(NO3)2 + Na2SO4 PbSO4 + 2NaNO3
- correct reactants and products-balanced equation
11
(b) 1. Add 10 cm3 of distilled water into the beaker containing 1 spatula of magnesium nitrate crystal and stir.
2. Pour 2cm3 of magnesium nitrate solution into a test tube
3. Add 2cm3 of sulphuric acid 1.0 moldm-3 into the test tube
4. Add 2cm3 of freshly prepared of iron(II) sulphate solution 1.0moldm-3 into the test tube
5. Add a few drop of concentrated sulphuric acid into the slanted test tube.
6. Brown ring is observed.
1
1
1
1
1
1 6(c) Procedures:
1. Measure and pour 50cm3 of zinc sulphate solution 1.0 moldm-3 into a beaker
2. Measure and add 50cm3 of sodium carbonate solution 1.0 moldm-3 into the beaker
3. Stir the mixture, filter and wash the residue4. Measure 50cm3 of nitric acid 2.0 moldm-3 into
another beaker (and warm the acid)5. Add zinc carbonate formed (from Pt 1 – 3) bit by
bit into the acid until in excess.6. Stir the mixture and filter 7. Heat up the filtrate in an evaporating dish until
one-third of original volume left and cool the solution
8. Dry the zinc nitrate salt formed between two filter papers.
Chemical equtions:9. ZnSO4 + Na2CO3 ZnCO3 + Na2SO4
10. ZnCO3 + 2HNO3 Zn(NO3)2 + CO2 + H2O
1
1
11
1
11
1
11 10Total 20
~END OF MARKING SCHEME~
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