Assisgment Sheet 2- Muhammad Afiq Bin Mohd Zimahdi
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Transcript of Assisgment Sheet 2- Muhammad Afiq Bin Mohd Zimahdi
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8/20/2019 Assisgment Sheet 2- Muhammad Afiq Bin Mohd Zimahdi
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Assisgment Sheet 2
Code / Course :-
KFC 2144 / Network Fundamental
Lecture :-
!"# S"$K%& '&N $"AA# "$S&N
(ro)lem 1
Host IP Address 172.30.1.33Subnet Mask 255.255.255.0Number of subnet bits 8 BitsNumber of subnets 28! 25" Subnet
Number of Host bits Per Subnet 25#Number of usab$e Hosts %er Subnet 28&2 ! 25"&2 ! 25# Host Per SubnetSubnet Address for t'is IP address 172.30.1.0IP address of (irst 'ost on t'is subnet 172.30.1.1IP Address of )ast Host on t'is subnet 172.30.1.25#Broad*ast Address for t'is subnet 172.30.1.255
Ste% 1 + ,rans$ate 'ost IP Address and subnet mask into Binar- natation
172 30 1 33
IP A/SS 10101100 00011110 0000000100100001
Subnet Mask 11111111 11111111 11111111
00000000
255 255 255 0
(irst )ist don t'ese a$ue of Numbers.
,ake t'e Host IP Address 172.30.1.30 and Start it' t'e (irst 4*tet * 1+2 ,
IP Address Ansers Binar-
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1+2 / 2 . . / 2 40 40 / 2 21 121 / 2 1 11 / 2
/ 2 2 12 / 2 1 1 / 2 1
So no e kno t'at a e*ima$ Number 172 is 1111 *onerted to Binar-
from.
2 4*tet * 0 ,
IP Address Ansers Binar-0 / 2 1
1 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1
Binar- Natation for t'e number 0 is 1111
3 4*tet 6 1
IP Address Ansers Binar-1 / 2 1 1
Binar- Natation (or t'e number 1 is 1
# 4*tet * 00 ,
IP Address Ansers Binar-00 1. 1
1. / 2 / 2 4 4 / 2 2 2 / 2 1 1 / 2 1
Binar- Natation for t'e number 00 is 11
So t'e IP Addressof 1+20100 'as its binar- form euia$ent of +
11111111111
Su)net ask
/e%eat t'e same %ro*edure used for t'e IP Address to *onert t'e subnet Mask
into Binar- notation.
1 4*tet * 2 ,
IP Address Ansers Binar-2 / 2 12+ 1
12+ / 2 .0 1.0 / 2 01 1
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01 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1
Binar- Notation for t'e number 2 is 11111111
2 4*tet * 2 ,
IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1
+ / 2 0 10 / 2 1 11 / 2 1
Binar- Notation for t'e number 2 is 11111111
3 4*tet * 2 ,
IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 1
1 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1
Binar- Notation for t'e number 2 is 11111111
# 4*tet * ,
IP Address Ansers Binar- / 2 / 2 / 2
/ 2 / 2 / 2 / 2 / 2
Binar- notation for t'e number is 6 sin*e t'ere is no number to
subtra*t for so automati*a$$- t'e anser is .
So the &( Addresso3 222 has its )inar 3orm e5ui6alent o3 :
111111111111111111111111
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Num)er o3 Su)net 'its :-
255.255.2998
111111111111111111111111111111
Num)er o3 "ost :-
28
Num)er o3 "ost 'its 7er su)net :-
289925"
Num)er o3 usa)le "osts 7er Su)net :-
28 : 2 ! 25" : 2 ! 25#
&( Address o3 8rst host on this su)net :-
172.30.1.33 10101100 00011110 00000001 11
172.30.1.1 10101100 00011110 00000001 1
&( Addresso3 Last "ost on this su)net :-
172.30.1.1 10101100 00011110 00000001 00000001
172.30.1.25# 10101100 00011110 00000001
1111111
'roadcast Address3or this su)net :-
;se 8 Number of )ast Host
172.30.1.0 10101100 00011110 00000001
172.30.1.255 10101100 00011110 00000001
11111111
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(ro)lem 2
Host IP Address 172.30.1.33Subnet Mask 255.255.255.252Number of subnet bits 1# BitsNumber of subnets 22! # Subnet
Number of Host bits Per Subnet #Number of usab$e Hosts %er Subnet 22&2 ! #&2 ! #Host Per SubnetSubnet Address for t'is IP address 172.30.1.32IP address of (irst 'ost on t'is subnet 172.30.1.33IP Address of )ast Host on t'is subnet 172.30.1.3#Broad*ast Address for t'is subnet 172.30.1.35
172 30 1 33
IP A/SS 10101100 00011110 00000001
00100001
Subnet Mask 11111111 11111111 11111111
11111100
255 255 255 252
(irst )ist don t'ese a$ue of Numbers.
,ake t'e Host IP Address 172.30.1.30 and Start it' t'e (irst 4*tet * 1+2 ,
IP Address Ansers Binar-1+2 / 2 .
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. / 2 40 40 / 2 21 121 / 2 1 11 / 2 / 2 2 1
2 / 2 1 1 / 2 1
So no e kno t'at a e*ima$ Number 172 is 1111 *onerted to Binar-
from.
2 4*tet * 0 ,
IP Address Ansers Binar-0 / 2 1 1 / 2 + 1
+ / 2 0 10 / 2 1 11 / 2 1
Binar- Natation for t'e number 0 is 1111
3 4*tet 6 1
IP Address Ansers Binar-1 / 2 1 1
Binar- Natation (or t'e number 1 is 1
# 4*tet * 00 ,
IP Address Ansers Binar-00 1. 1
1. / 2 / 2 4 4 / 2 2 2 / 2 1 1 / 2 1
Binar- Natation for t'e number 00 is 11
So t'e IP Addressof 1+20100 'as its binar- form euia$ent of +
11111111111
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Su)net ask /e%eat t'e same %ro*edure used for t'e IP Address to *onert t'e subnet Mask
into Binar- notation.
1 4*tet * 2 ,
IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 1
1 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1
Binar- Notation for t'e number 2 is 11111111
2 4*tet * 2 ,
IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1
Binar- Notation for t'e number 2 is 11111111
3 4*tet * 2 ,
IP Address Ansers Binar-
2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1
Binar- Notation for t'e number 2 is 11111111
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# 4*tet * 22 ,
IP Address Ansers Binar-22 / 2 12. 12. / 2 .0 .0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1
Binar- notation for t'e number 22 is 111111 6 sin*e t'ere is no number to
subtra*t for so automati*a$$- t'e anser is 111111 .
So the &( Addresso3 22222has its )inar 3orm e5ui6alent o3 :
111111111111111111111111111111
Num)er o3 Su)net 'its :-
255.255.2998
111111111111111111111111111111
Num)er o3 "ost :-
21#
Num)er o3 "ost 'its 7er su)net :-
21#991" 38#
Num)er o3 usa)le "osts 7er Su)net :-
22 : 2 ! # : 2 ! 2 Host subnet
&( Address o3 8rst host on this su)net :-
172.30.1.33 10101100 00011110 00000001 11
172.30.1.32 10101100 00011110 00000001 1
&( Addresso3 Last "ost on this su)net :-
172.30.1.32 10101100 00011110 00000001 0010000
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172.30.1.3# 10101100 00011110 00000001 0010001
'roadcast Address3or this su)net :-;se 8 Number of )ast Host
172.30.1.32 10101100 00011110 00000001 1
172.30.1.35 10101100 00011110 00000001 111
Su)net Address
Perform a bit&ise AN 6 $o
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1" > 8 > # > 2 ! 0
0rd !ctet
1
4
th
!ctet02
,'erefore t'e subnet Address is 1+20102
etermine 'i*' bits *ontain netork information and 'ost information
aor #i6ide * #, Su)net #i6ide
* S# ,
"ost &(
Address
10101100 00011110 00000001 00100001
Su)net
ask
11111111 11111111 11111111 11111110
Su)net
Address
10101100 00011110 00000001 00100000
ra t'ema?or iide 6 M. Asa a*- $ine 'ere t'e 1@s in t'e ma?or
netork mask 6 t'e 1" $eft&most Bits nd and t'e subnet diide 6 S. as
a Strai
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First "ost 11111111111
12 .4 02 1. 4 2 11 1 1 1 1 1 1 1 1 1 1
(or t'e 1st !ctet
IP Address Ansers Binar-1+2 / 2 . . / 2 40 40 / 2 21 121 / 2 1 11 / 2 / 2 2 12 / 2 1 1 / 2 1
2 4*tet * 0 , IP Address Ansers Binar-
0 / 2 1 1 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1
3 4*tet 6 1
IP Address Ansers Binar-1 / 2 1 1
Binar- Natation (or t'e number 1 is 1
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# 4*tet * 00 ,
IP Address Ansers Binar-00 1. 1
1. / 2 / 2 4 4 / 2 2 2 / 2 1 1 / 2 1
,'erefore t'e (irst Host Address is 1+20100
Last "ost 11111111111
12 .4 02 1. 4 2 11 1 1 1 1 1 1 1 1
1 1
(or t'e 1st !ctet
IP Address Ansers Binar-1+2 / 2 . . / 2 40 40 / 2 21 121 / 2 1 11 / 2 / 2 2 12 / 2 1 1 / 2 1
2 4*tet * 0 ,
IP Address Ansers Binar-0 / 2 1
1 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1
3 4*tet 6 1
IP Address Ansers Binar-1 / 2 1 1
Binar- Natation (or t'e number 1 is 1
# 4*tet * 04 ,IP Address Ansers Binar-
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04 / 2 1+ 1+ / 2 1 / 2 4 4 / 2 2 2 / 2 1
1 / 2 1 ,'erefore t'e $ast Host Address is 1+20104
Broadcast Address 10101100.00011110.00000001.00100011
(or t'e 1st !ctet
IP Address Ansers Binar-1+2 / 2 .
. / 2 40 40 / 2 21 121 / 2 1 11 / 2 / 2 2 12 / 2 1 1 / 2 1
2 4*tet * 0 ,
IP Address Ansers Binar-
0 / 2 1 1 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1
3 4*tet 6 1
IP Address Ansers Binar-1 / 2 1 1
Binar- Natation (or t'e number 1 is 1
# 4*tet * 0 ,
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IP Address Ansers Binar-0 / 2 1+ 11+ / 2 1 / 2 4 4 / 2 2
2 / 2 1 1 / 2 1
,'erefore t'e Broad*ast Address is 172.30.1.35
(ro)lem 0
Host IP Address 1F2.1F2.10.23#Subnet Mask 255.255.255.0Number of subnet bits 8 BitsNumber of subnets 28! 25" SubnetNumber of Host bits Per Subnet 25#Number of usab$e Hosts %er Subnet 28 & 2 ! 25" & 2 ! 25# Host Per SubnetSubnet Address for t'is IP address 1F2.1F2.10.0IP address of (irst 'ost on t'is subnet 1F2.1F2.10.1IP Address of )ast Host on t'is subnet 1F2.1F2.10.25#Broad*ast Address for t'is subnet 1F2.1F2.10.255
Ste% 1 + ,rans$ate 'ost IP Address and subnet mask into Binar- natation
1F2 1F2 10 23#
IP A/SS 11000000 11000000 00001010
00100001
Subnet Mask 11111111 11111111 11111111
00000000
255 255 255 0
(irst )ist don t'ese a$ue of Numbers.
,ake t'e Host IP Address 1F2.1F2.10.23
and Start it' t'e (irst 4*tet * 1;2 ,
IP Address Ansers Binar-1;2 / 2 ;. ;. / 2 4 4 / 2 24
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24 / 2 12 12 / 2 . . / 2 0 0 / 2 1 11 / 2 1
So no e kno t'at a e*ima$ Number 1;2 is 11 *onerted to Binar-from.
2 4*tet * 1;2 ,
IP Address Ansers Binar-1;2 / 2 ;. ;. / 2 4 4 / 2 24 24 / 2 12 12 / 2 . . / 2 0
0 / 2 1 11 / 2 1
So no e kno t'at a e*ima$ Number 1;2 is 11 *onerted to Binar-
from.
3 4*tet 6 1
IP Address Ansers Binar-1 / 2 / 2 2 12 / 2 1 1 / 2 1 1
Binar- Natation (or t'e number 1 is 11
# 4*tet * 204 ,
IP Address Ansers Binar-204 / 2 11+ 11+ / 2 1 / 2 2; 2; / 2 14 114 / 2 + + / 2 0 1
0 / 2 1 11 / 2 1 1
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Binar- Natation for t'e number 204 is 11111
So t'e IP Address of 1;21;21204 'as its binar- form euia$ent of +
11111111111
Su)net ask
/e%eat t'e same %ro*edure used for t'e IP Address to *onert t'e subnet Mask
into Binar- notation.
1 4*tet * 2 ,
IP Address Ansers Binar-2 / 2 12+ 1
12+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1
Binar- Notation for t'e number 2 is 11111111
2 4*tet * 2 ,
IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1
Binar- Notation for t'e number 2 is 11111111
3 4*tet * 2 ,
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IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 1
1 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1
Binar- Notation for t'e number 2 is 11111111
# 4*tet * ,
IP Address Ansers Binar- / 2 / 2 / 2 / 2 / 2 / 2
/ 2 / 2
Binar- notation for t'e number is 6 sin*e t'ere is no number to
subtra*t for so automati*a$$- t'e anser is .
So the &( Address o3 222 has its )inar 3orm e5ui6alent o3 :
111111111111111111111111
Num)er o3 Su)net 'its :-
255.255.2998
111111111111111111111111
Num)er o3 "ost :-
28
Num)er o3 "ost 'its 7er su)net :-
289925"
Num)er o3 usa)le "osts 7er Su)net :-
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28 : 2 ! 25" : 2 ! 25#
&( Address o3 8rst host on this su)net :-
1F2.1F2.10.23# 11000000 11000000 00001010
11111
1F2.1F2.10.1 11000000 11000000 00001010
1
&( Addresso3 Last "ost on this su)net :-
1F2.1F2.10.1 11000000 11000000 00001010
00000001
1F2.1F2.10.25# 11000000 11000000 00001010
1111111
'roadcast Address3or this su)net :-
;se 8 Number of )ast Host
1F2.1F2.10.0 11000000 11000000 00001010
1F2.1F2.10.255 11000000 11000000 0000101011111111
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(ro)lem 4
Host IP Address 172.17.FF.71Subnet Mask 255.255.0.0Number of subnet bits 1" BitsNumber of subnets 21" ! "553"
Number of Host bits Per Subnet "553"Number of usab$e Hosts %er Subnet 21" ! "553" : 2 ! "553# Hosts Per
SubnetsSubnet Address for t'is IP address 172.17.FF.0IP address of (irst 'ost on t'is subnet 172.17.FF.1IP Address of )ast Host on t'is subnet 172.17.FF."553#Broad*ast Address for t'is subnet 172.17.FF.255
Ste% 1 + ,rans$ate 'ost IP Address and subnet mask into Binar- natation
172 17 FF 71
IP A/SS 10101100 00010001 01100011
01001101
Subnet Mask 11111111 11111111 00000000
00000000
255 255 0 0
(irst )ist don t'ese a$ue of Numbers.
,ake t'e Host IP Address 172.30.1.30 and Start it' t'e (irst 4*tet * 1+2 ,
IP Address Ansers Binar-
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1+2 / 2 . . / 2 40 40 / 2 21 121 / 2 1 11 / 2
/ 2 2 12 / 2 1 1 / 2 1
So no e kno t'at a e*ima$ Number 172 is 1111 *onerted to Binar-
from.
2 4*tet * 1+ ,
IP Address Ansers Binar-1+ / 2 1
/ 2 4 4 / 2 2 2 / 2 1 1 / 2 1
Binar- Natation for t'e number 1+ is 11
3 4*tet 6 ;;
IP Address Ansers Binar-;; / 2 4; 14; / 2 24 124 / 2 12 12 / 2 . . / 2 0 0 / 2 1 11 / 2 1 1
Binar- Natation (or t'e number 1 is 1111
# 4*tet * +1 ,
IP Address Ansers Binar-+1 / 2 0 10 / 2 1+ 11+ / 2 1 / 2 4 4 / 2 2 2 / 2 1 1 / 2 1 1
Binar- Natation for t'e number +1 is 1111
So t'e IP Addressof 1 'as its binar- form euia$ent of +
11111111111111
Su)net ask
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/e%eat t'e same %ro*edure used for t'e IP Address to *onert t'e subnet Mask
into Binar- notation.
1 4*tet * 2 ,
IP Address Ansers Binar-
2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1
Binar- Notation for t'e number 2 is 11111111
2 4*tet * 2 ,
IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1
.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1
Binar- Notation for t'e number 2 is 11111111
3 4*tet * ,
IP Address Ansers Binar- / 2 / 2 / 2 / 2 / 2 / 2 / 2 / 2
Binar- notation for t'e number is 6 sin*e t'ere is no number to
subtra*t for so automati*a$$- t'e anser is .
# 4*tet * ,
IP Address Ansers Binar-
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/ 2 / 2 / 2 / 2 / 2
/ 2 / 2 / 2
Binar- notation for t'e number is 6 sin*e t'ere is no number to
subtra*t for so automati*a$$- t'e anser is .
So the &( Addresso3 222 has its )inar 3orm e5ui6alent o3 :
111111111111111111111111
Num)er o3 Su)net 'its :-
255.255.2998
111111111111111111111111
Num)er o3 "ost :-21"
Num)er o3 "ost 'its 7er su)net :-
21"99"553"
Num)er o3 usa)le "osts 7er Su)net :-
21F : 2 ! "553" : 2 ! "553"
&( Address o3 8rst host on this su)net :-172.17.FF.71 11000000 11000000 00001010
11
172.17.FF.1 11000000 11000000 00001010
1
&( Addresso3 Last "ost on this su)net :-
172.17.FF.1 11000000 11000000 00001010 1
172.17.FF.25# 11000000 11000000 00001010
1111111
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'roadcast Address3or this su)net :-
;se 8 Number of )ast Host
172.17.FF.0 11000000 11000000 00001010
172.17.FF.255 11000000 11000000 00001010 1
11111111111111
(ro)lem
Host IP Address 1F2.1"8.3.21FSubnet Mask 255.255.255.0Number of subnet bits 8 Bits
Number of subnets 28! 25" SubnetNumber of Host bits Per Subnet 25#Number of usab$e Hosts %er Subnet 28 & 2 ! 25" & 2 ! 25# Host Per SubnetSubnet Address for t'is IP address 1F2.1"8.3.0IP address of (irst 'ost on t'is subnet 1F2.1"8.3.1IP Address of )ast Host on t'is subnet 1F2.1"8.3.25#Broad*ast Address for t'is subnet 1F2.1F2.10.255
Ste% 1 + ,rans$ate 'ost IP Address and subnet mask into Binar- natation
1F2 1"8 3 21F
IP A/SS 11000000 10101000 00000011
11011011
Subnet Mask 11111111 11111111 11111111
00000000
255 255 255 0
(irst )ist don t'ese a$ue of Numbers.
,ake t'e Host IP Address 1F2.1"8.3.21F
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and Start it' t'e (irst 4*tet * 1;2 ,
IP Address Ansers Binar-1;2 / 2 ;. ;. / 2 4 4 / 2 24 24 / 2 12 12 / 2 . . / 2 0 0 / 2 1 11 / 2 1
So no e kno t'at a e*ima$ Number 1;2 is 11 *onerted to Binar-
from.
2 4*tet * 1. ,
IP Address Ansers Binar-
1. / 2 4 4 / 2 42 42 / 2 21 21 / 2 1 11 / 2 / 2 2 12 / 2 1 1 / 2 1
So no e kno t'at a e*ima$ Number 1. is 111 *onerted to Binar-
from.
3 4*tet 6 0
IP Address Ansers Binar-0 / 2 1 11 / 2 1 1
Binar- Natation (or t'e number 0 is 11
# 4*tet * 21; ,
IP Address Ansers Binar-21; / 2 1; 11; / 2 4 14 / 2 2+
2+ / 2 10 110 / 2 . 1
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. / 2 0 0 / 2 1 11 / 2 1 1
Binar- Natation for t'e number 21; is 111111
So t'e IP Address of 1;21.021; 'as its binar- form euia$ent of +
11 111 11 111111
Su)net ask
/e%eat t'e same %ro*edure used for t'e IP Address to *onert t'e subnet Mask
into Binar- notation.
1 4*tet * 2 ,
IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1
Binar- Notation for t'e number 2 is 11111111
2 4*tet * 2 ,
IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 1
0 / 2 1 11 / 2 1
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Binar- Notation for t'e number 2 is 11111111
3 4*tet * 2 ,
IP Address Ansers Binar-2 / 2 12+ 1
12+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1
Binar- Notation for t'e number is
# 4*tet * ,
IP Address Ansers Binar- / 2 / 2 / 2
/ 2 / 2 / 2 / 2 / 2
Binar- notation for t'e number is 6 sin*e t'ere is no number to
subtra*t for so automati*a$$- t'e anser is .
So the &( Address o3 22 has its )inar 3orm e5ui6alent o3 :
1111111111111111
Num)er o3 Su)net 'its :-
255.255.991"
1111111111111111
Num)er o3 "ost :-
28
Num)er o3 "ost 'its 7er su)net :-
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21"9925"
Num)er o3 usa)le "osts 7er Su)net :-
21" : 2 ! "553" : 2 ! "553#
&( Address o3 8rst host on this su)net :-
1F2.1"8.3.0 11000000 10101000 00000011
1F2.1"8.3.1 11000000 10101000 00000011
1
&( Addresso3 Last "ost on this su)net :-
1F2.1"8.3.1 11000000 10101000 00000011
000000011F2.1"8.3.25# 11000000 10101000 00000011
1111111
'roadcast Address3or this su)net :-
;se 1" Number of )ast Host
1F2.1"8.3.0 11000000 10101000 00000011
1F2.1"8.3.255 11000000 10101000 00000011
11111111
(ro)lem .
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Host IP Address 1F2.1"8.3.21FSubnet Mask 255.255.255.22#Number of subnet bits 5 BitsNumber of subnets 25! 32 SubnetNumber of Host bits Per Subnet 32
Number of usab$e Hosts %er Subnet 25
& 2 ! 32 & 2 ! 30 Host Per SubnetSubnet Address for t'is IP address 1F2.1"8.3.0IP address of (irst 'ost on t'is subnet 1F2.1"8.3.1IP Address of )ast Host on t'is subnet 1F2.1"8.3.25#Broad*ast Address for t'is subnet 1F2.1F2.10.255
Ste% 1 + ,rans$ate 'ost IP Address and subnet mask into Binar- natation
1F2 1"8 3 21F
IP A/SS 11000000 10101000 00000011
11011011
Subnet Mask 11111111 11111111 11111111
11100000
255 255 255 22#
(irst )ist don t'ese a$ue of Numbers.
,ake t'e Host IP Address 1F2.1"8.3.21F
and Start it' t'e (irst 4*tet * 1;2 ,
IP Address Ansers Binar-1;2 / 2 ;. ;. / 2 4 4 / 2 24 24 / 2 12 12 / 2 . . / 2 0 0 / 2 1 11 / 2 1
So no e kno t'at a e*ima$ Number 1;2 is 11 *onerted to Binar-
from.
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2 4*tet * 1. ,
IP Address Ansers Binar-1. / 2 4 4 / 2 42 42 / 2 21 21 / 2 1 11 / 2 / 2 2 12 / 2 1 1 / 2 1
So no e kno t'at a e*ima$ Number 1. is 111 *onerted to Binar-
from.
3 4*tet 6 0
IP Address Ansers Binar-
0 / 2 1 11 / 2 1 1Binar- Natation (or t'e number 0 is 11
# 4*tet * 21; ,
IP Address Ansers Binar-21; / 2 1; 11; / 2 4 14 / 2 2+ 2+ / 2 10 110 / 2 . 1
. / 2 0 0 / 2 1 11 / 2 1 1
Binar- Natation for t'e number 21; is 111111
So t'e IP Address of 1;21.021; 'as its binar- form euia$ent of +
11 111 11 111111
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Su)net ask
/e%eat t'e same %ro*edure used for t'e IP Address to *onert t'e subnet Mask
into Binar- notation.
1 4*tet * 2 ,
IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 10 / 2 1 11 / 2 1
Binar- Notation for t'e number 2 is 11111111
2 4*tet * 2 ,
IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1+ / 2 0 1
0 / 2 1 11 / 2 1
Binar- Notation for t'e number 2 is 11111111
3 4*tet * 2 ,
IP Address Ansers Binar-2 / 2 12+ 112+ / 2 .0 1.0 / 2 01 101 / 2 1 11 / 2 + 1
+ / 2 0 10 / 2 1 11 / 2 1
Binar- Notation for t'e number 2 is 11111111
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# 4*tet * ,
IP Address Ansers Binar-224 / 2 112 112 / 2 . . / 2 2 2 / 2 14 14 / 2 + + / 2 0 10 / 2 1 11 / 2 1 1
Binar- notation for t'e number is 6 sin*e t'ere is no number to
subtra*t for so automati*a$$- t'e anser is .
So the &( Address o3 222224 has its )inar 3orm e5ui6alent
o3 :
1111111111111111 11111111111
Num)er o3 Su)net 'its :-
255.255.2224995
111111111111111111111111111
Num)er o3 "ost :-
25
Num)er o3 "ost 'its 7er su)net :-
259932
Num)er o3 usa)le "osts 7er Su)net :-
25 : 2 ! 32 : 2 ! 30
&( Address o3 8rst host on this su)net :-
1F2.1"8.3.2 11000000 11000000 0000001111111
1F2.1"8.3.1 11000000 11000000 00000011
1
&( Addresso3 Last "ost on this su)net :-
1F2.1"8.3.1 11000000 11000000 00000011
00000001
1F2.1"8.3.255 11000000 11000000 00000011
11111111
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'roadcast Address3or this su)net :-
;se 8 Number of )ast Host
1F2.1"8.3.0 11000000 11000000 00000011
1F2.1"8.3.255 11000000 11000000 00000011
11111111