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dik:

fy 230 + 49 = 279 Mpa 27.9

fc' 28 + 9 = 37 Mpa

tebal plat = 10 cm = 100 mm

syarat-syarat tumpuan

tumpuan terjepit elastis, dengan jarak c.t.c di anggap sebagai bentang

- plat RK  Ly/L 4 : 4 =

- plat Koridor Ly/L 4 : 3 =

- plat Perpus Ly/L ! : 4 =

- plat Lab Ly/L ! : 4 =

- plat Gudang Ly/L ! : 4 =

hitungan beban-beban

- beban mati (Wd

a. be"at #e$di"i = 0.12 24 = 2.88

b. beba$ mati %pe$&t&p la$taid&cti$( )*

pipa-pipa = 200 = 2.00

,d = 4.88

- beban hidup (WL

a. (ed&$( &$t&k "&a$( k&lia = 20 = 2.0

b. pe"alata$ ka$t" = 10 = 1.0

,L = 4.00

- kombinasi beban (beban ultimit,Wu

& = 1.2 d + 1.! L

= 1.2 2.88 + 1.! 2.0

= 7.4!

pe"it&$(a$ mme$ %de$(a$ tabel 1971

pelat RK 

= 0.02 = 0.02 7.4!

M5y = 0.02 = 0.02 7.4!

Mt6 = -0.01 = -0.01 7.4!

Mty = -0.01 = -0.01 7.4!

pelat koridor

k

k(/m k

k

k(/m

k(/m

k/m

M56 &.L6

&.L6

&.L6

&.L6

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= 0.03!8 = 0.03!8 9.8!

M5y = 0.020! = 0.020! 9.8!

Mt6 = -0.0!!1 = -0.0!!1 9.8!

Mty = -0.043 = -0.043 9.8!

pelat perpus

= 0.04 = 0.04 9.8!M5y = 0.01! = 0.01! 9.8!

Mt6 = -0.07 = -0.07 9.8!

Mty = -0.04 = -0.04 9.8!

pelat Lab

= 0.04 = 0.04 9.8!

M5y = 0.01! = 0.01! 9.8!

Mt6 = -0.07 = -0.07 9.8!

Mty = -0.04 = -0.04 9.8!

pelat Gudang

= 0.04 = 0.04 9.8!

M5y = 0.01! = 0.01! 9.8!

Mt6 = -0.07 = -0.07 9.8!

Mty = -0.04 = -0.04 9.8!

kebutuhan tulangan lentur

a. pelat RK  

!ulangan Lapangan

- !inggi "#ekti# $eton

 ika dipakai e$&t&p bet$ b = 2 cm =

diamete" t&la$(a$ = 10 mm

 i$((i ;fektif et$ a"a d = 100 - 20 -

 i$((i ;fektif et$ a"a ydy = 100 - 20 -

% tulangan lapangan arah &

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fc'

0.9 p 279 p 279 + 0.!!3 = 0

37

4.449 p - 279 p + 0.!!3 = 0

maka di dapat p1 = !2.709

p2 = 0.00238

dipakai p = 0.00238

ceck te"adap pmi$ = 1.4=

1.4= 0.0002

fy 279

ka"e$a p = 0.00238 ? pmi$ 0.0002 maka dipakai p =

l&a# t&la$(a$ pe"l&

)# = p b d

= 0.0002 1000 7 = 37

dipakai t&la$(a$ diamete" 10 mm

maka a"ak t&la$(a$$ya:

# = = = 208.8! mm)# 37!.34

 adi &$t&k t&la$(a$ a"a pelat

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) tinggi e#ekti# beton

 ika dipakai pe$&t&p bet$pb = 2 cm = 20 mm

diamete" t&la$(a$ = 10 mm

 i$((i ;fektif et$ a"a tAtydt = 100 - 20 - 0.

"a#i t&la$(a$ bet$

M& = !.08 km (untuk penulangan tumpuan dipakai *t& +*ty,

k = M&=

!.08

0.8 1000 7

0.9 p fy + k = 0

fc'

0.9 p 279 p 279 + 1.31 = 0

37

4.449 p - 279 p + 1.31 = 0

maka di dapat p1 = !2.7070

p2 = 0.00484

dipakai p = 0.00484

ceck te"adap pmi$ = 1.4=

1.4= 0.0002

fy 279

ka"e$a p = 0.00484 ? pmi$ 0.0002 maka dipakai p =

)luas tulangan perlu

)# = p b d

= 0.0002 1000 7

= 37!.34

dipakai t&la$(a$ diamete" 10 mm

maka a"ak t&la$(a$$ya :

# = = = 208.8! mm)# 37!.34

 adi &$t&k t&la$(a$ t&mp&a$ a"a di pakai P%'-''ceck a"ak a$ta" t&la$(a$ 200 ? 3 = 300 mm A 00 mm

) luas tulangan susut

pelat RK 

)##&t

=0.2 b

=0.2 1000

100 100

= 20ata&

)# #&t 20F )# pkk 7 2!88

10

> b d

p fy

mm

1/4DEb 1/4.D.10.1000

mm

mm

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dipakai diamete" t&la$(a$ #&t = 8 mm

# = = = 37 mm)# 7.27

de$(a$ ca"a ya$( #ama pe"it&$(a$ pelat b ditabelka$

b. Pelat koridor

momen koe#.*u ilai k  

Pperlu P(km (*pa

ML 3!.8 3.2! 0.724 0.002!0 0.0

Mly 20.! 1.83 0.40! 0.00194 0.0

Mt !!.1 .87 1.3039 0.004!7 0.0

Mty 4.3 4.82 1.0713 0.00384 0.0

t&la$(a$ #&t

tty

b. Pelat perpus

momen koe#.*u ilai k  

Pperlu P(km (*pa

ML 4. 7.18 1.94 0.0072 0.0

Mly 1!. 2.!0 0.7!98 0.00207 0.0

Mt 7 11.83 2.!283 0.0124 0.0

Mty 4. 8.9 1.9099 0.00!8 0.0t&la$(a$ #&t

t

ty

b. Pelat Lab

momen koe#.*u ilai k  

Pperlu P(km (*pa

ML 4. 7.18 1.94 0.0072 0.0

Mly 1!. 2.!0 0.7!98 0.00207 0.0Mt 7 11.83 2.!283 0.0124 0.0

Mty 4. 8.9 1.9099 0.00!8 0.0

t&la$(a$ #&t

t

ty

b. Pelat Gudang

momen koe#.*u ilai k  

Pperlu P(km (*pa

ML 4. 7.18 1.94 0.0072 0.0

Mly 1! 2 !0 0 7!98 0 00207 0 0

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Mt 7 11.83 2.!283 0.0124 0.0

Mty 4. 8.9 1.9099 0.00!8 0.0

t&la$(a$ #&t

t

ty

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1

1.333

1.

1.

1.

4 = 2.98 km

4 = 2.98 km

4 = -!.08 km

4 = -!.08 km

m

m

m

k/m

k/m

k/m

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3 = 3.2! km

3 = 1.83 km

3 = -.87 km

3 = -4.82 km

4 = 7.18 km 4 = 2.!0 km

4 = -11.83 km

4 = -8.9 km

4 = 7.1717 km

4 = 2.!0198 km

4 = -11.827 km

4 = -8.944 km

4 = 7.1717 km

4 = 2.!0198 km

4 = -11.827 km

4 = -8.944 km

20 mm

0. 10 = 7 mm

10 - 0. 10 = ! mm

!2

= 0.!!3 Mpa

4.449 p - 279 p +

- 279 G 279 H2

%−GI H2(J /4 2

I

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2 4.4489

- 279 G 77841

8.898

- 279 G 77829.20!

8.8978

de$(a$ "&m )* = 279 G 279.0

8.90

0.0002

.34

$ d = ! mm

= 0.882 Mpa

4.449 p - 279 p

- 279 G 279

2

- 279 G 77

8.8978

- 279 G 7782

8.8978

de$(a$ "&m )* = 279 G 278.978.90

02

  = 0.0002

mm

I

I

I

I

I

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10 = 7 mm

karena momen tumpuan arah & + y sama maka penulangannya pun sa

= 1.31 Mpa

4.449 p - 279 p + 1.31

- 279 G 279 H2 -

2 4.449

- 279 G 77841 -

8.8978378

- 279 G 7781!.9!

8.898

de$(a$ "&m )* = 279 G 278.9!

8.90

0.00484

100

I

I

I

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 adi &$t&k t&la$(a$ t&mp&a$ a"a da$ y di pakai P-ceck a"ak a$ta" t&la$(a$ 3!0 ? = 00 mm A ? 00 mm

in

02 37!.344 10-200

02 32!.1! 10-240

02 30.0 10-220

02 249.!12 10-310

70.110 !-40049.922 !-00

in

02 37!.344 10-200

02 32!.1! 10-240

02 940.82! 10-83

02 13.4!3 10-10

188.1! 8-2!0

102.!93 8-480

in

02 37!.344 10-200

02 32!.1! 10-24002 940.82! 10-83

02 13.4!3 10-10

188.1! 8-2!0

102.!93 8-480

in

02 37!.344 10-200

02 32! 1! 10 240

0s (mm1dipakai

tulangan

0s (mm1dipakai

tulangan

0s (mm1dipakai

tulangan

0s (mm1dipakai

tulangan

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02 940.82! 10-83

02 13.4!3 10-10

188.1! 8-2!0

102.!93 8-480

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K1

= 0.8

= 0.7940

0.!!28 = 0

- 4 4 449 0 !!3

b

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- 11.794

+ 0.882 = 0

H2 - 4 4.449 0.8824

4.4

41 - 1.702

.298

maka

mi$

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  a

= 0

4 4.449 1.31

24.044

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/'

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- 0.008 % 37 - 30

 K1

= !00

fy !00 + fy

=0.8 37 0.7940

!00

279 !00 + 279=

24.9713

!00

279 879

08 fc' K1

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= 0.089 0.!8

= 0.0!11

= 0.7 b = 0.7 0.0!11

= 0.048

0.0002 ? 0.0482

 : mak#

 

mak#

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@N b d

10

> b d

1/4DEb 1/4.D.10.1000

I

I

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I

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I

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)# 37!.34.

# = = = 240.!78 mm #)# 32!.1!

# = = = 223.9338 mm)# 30.

# = = = 314.4877 mm)# 249.!1

ceck a"ak a$ta" t&la$(a$ 10 ? 3 = 300 mm A 00 mm

k = M&=

7.18 = 1.

0.8 1000 7

4.4 p - 279 p + 1.94 = 0

- 279 G 279 H2 - 4 4.4 1.94482

2 4.4

- 279 G 77841 - 28.37

8.9

- 279 G 77812.!2

8.9

= 279 G 278.9

8.90

k = M&=

2.!0 = 0.

0.8 1000 7

4.4 p - 279 p + 0.78 = 0

- 279 G 279 H2 - 4 4.4 0.78219

2 4.4

- 279 G 77841 - 10.290

8.9

- 279 G 77830.710

8.9

= 279 G 278.98

8.90

1/4DEb 1/4.D.10.1000

1/4DEb 1/4.D.10.1000

1/4DEb 1/4.D.10.1000

10

> b d

10

> b d

I

I

I

I

I

I

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# = = = 208.87 mm)# 37!.34

# = = = 240.!78 mm)# 32!.1!

# = = = 83.43734 mm)# 940.83

# = = = 12.883 mm)# 13.4!

1/4DEb 1/4.D.10.1000

1/4DEb 1/4.D.10.1000

1/4DEb 1/4.D.10.1000

1/4DEb 1/4.D.10.1000

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= 4.00

= 1.0

= .0

y

2 Mpak = M&

=1.83

0.8 1000

4.4 p - 279 p + 0.41 = 0

- 279 G 279 H2 - 4 4.4

2 4.448919

- 279 G 77841 - 9.!21

8.9

- 279 G 77831.379

8.9

= 279 G 278.98

8.90

04 Mpak = M&

=4.82

0.8 1000

4.4 p - 279 p + 1.071 = 0

- 279 G 279 H2 - 4 4.4

2 4.448919

- 279 G 77841 - 19.0!

8.9

- 279 G 77821.93

8.9

= 279 G 278.97

8.90

k/m

k/m

k/m

10

> b d

10

> b d

1/4DEb 1/4.D.10.1000

I

I

I

I

I

I

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)# 70.11.

= = = !!.0779 mm)# 49.92

94 Mpak = M&

=11.83

0.8 1000

4.4 p - 279 p + 3.499 = 0

- 279 G 279 H2 - 4 4.4

2 4.448919

- 279 G 77841 - !2.270

8.9

- 279 G 77778.730

8.9

= 279 G 278.89

8.90

78 Mpak = M&

=8.9

0.8 1000

4.4 p - 279 p + 1.910 = 0

- 279 G 279 H2 - 4 4.4

2 4.448919

- 279 G 77841 - 33.987

8.9

- 279 G 77807.013

8.9

= 279 G 278.94

8.90

1/4DEb 1/4.D.10.1000

10

> b d

10

> b d

I

I

I

I

I

I

I

I

I

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# = = = 2!7 mm)# 188.17

# = = = 489.2271 mm)# 102.!9

1/4DEb 1/4.D.10.1000

1/4DEb 1/4.D.10.1000

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= 0.41 Mpa!

0.4

= 1.071 Mpa7

1.07

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= 3.499 Mpa!

3.

= 1.910 Mpa7

1.91

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