SALAM………SEJAHTERA

KELEMAHAN CALON MATEMATIK UPSR

A. Tidak Menguasai Fakta Asas Matematik

Example 1:

1995 (No. 1)/Paper 2

37 + 865 =Mistakes of the candidates :

37

+ 865

892

37

+ 865

802

37

+ 865

992

Answer : 37

+ 865

902

B. Tidak Menguasai Kemahiran Matematik

Example 1 :1995 (No. 1)/Paper 2

37 + 865 =

Jawapan : 37

+ 865

902Mistakes of candidates :

37

+ 865

1235

37

+ 865

892

37 + 865 = 37865

Example 2 :2005 (No. 8)/Paper 2

43.5 – 2.76 =

Answer : 43.50

- 2.76

40.74

Mistakes of candidates :

a. 43.5

- 2.76

15.9

b. 4350

- 2760

1590

c. 43.5

- 2.76

40.86

Example 2:

1997 (No. 15)/Paper 2

Draw a isosceles triangle PQR in the diagram below. (2 marks)

Answer

Mistakes of candidates

Q

Q

P

R Q

P

R Q

P

R

Example 3:

1999 (No. 9)/Paper 2

120 + 15 ÷ 3 = (2 marks)

Answer : 15 ÷ 3 = 5 + 120

= 125

Mistakes of candidates : 120

+ 15

135 ÷ 3 = 45

Answer : 4 years 6 months

4 ) 18 years

-16

2 years = 24 months

24 months

Example 4:2003 (No. 15)/Paper 1

1 of 18 years = ___ years ___ months 4

4 yrs 2 mths

4 ) 18 years

16

2 years

4 years 5 months

4 ) 18 years

16

2 0

2 0

Mistakes of candidates

Example 5 :2002 (No. 4)/Paper 1

3432 x 6 ÷ 12 =

Mistakes of candidates : 12 ÷ 6 = 2

3432

x 2

6864

Answer (i)

3432

x 6

20592 ÷ 12

= 1716

Answer (ii)

3432 x 6

12

= 3432 ÷ 2

= 1716

C. Tidak Menguasai Rumusan MatematikExample 1 :1998 (No. 16)/Paper 2

Answer : (i) 4+4+4+4+4+4 = 24 cm (ii) 4 x 6 = 24 cm

2+2+2+2 = + 8 cm 2 x 4 = + 8 cm

32 cm 32 cm

Diagram beside is form from squares

of same size. Calculate the perimetre

of the shaded region. (3 marks)

2 cm

4 cm

Mistakes of candidates : 4 x 2 = 8 cm²

x 4

32 cm²

Contoh 2 :1999 (No. 40)/Paper 1In Diagram 14, PQS is a right angle triangle and PRS is isosceles, PR = RS. Calculate the area of triangle PRS, in cm²

S

4 cm 5 cm

3 cm

P

Q RRajah 14

Answer : Area = Base x Height ÷ 2

= RS x PQ ÷ 2

= 5 cm x 4 cm ÷ 2

= 20 cm² ÷ 2

= 10 cm²

(i) 3 cm x 4cm ÷ 2

= 12 cm² ÷ 2

= 6 cm² Mistakes of candidates

(ii) 5 cm x 5cm ÷ 2

= 25 cm² ÷ 2

= 12.5 cm²

(iii) 8 cm x 4cm ÷ 2

= 32 cm² ÷ 2

= 16 cm²

Example 3 :1996 (No. 5)/Paper 2Write a equivalent fraction of 3/5

Answer : (i) 3 x 2 = 6 (ii) 3 x 3 = 9 dll

5 x 2 10 5 x 3 15

Mistakes of candidates : (i) 3 x 3 = 9 dll

5 x 5 25

D.Tidak Memahami Maklumat/Kata kunci/Kehendak soalanExample 1 :1995 (No. 4)/Paper 2580 manggis shared same amount among Ang, Beng, Dol, Eng and Fan. How many manggis each one can get?

Answer : 580 ÷ 5 = 116

Mistakes of candidates : (i) 580 ÷ 4

(ii) 580 + 5

Example 2:2002 (No. 19)/Paper 2

A pail contains 2 liters 30 ml water. Azmi pours 450ml of water from another container to the pail. Calculate the amount of water, in ml, in the pail now?

Answer : 2030 ml

+ 450 ml

2480 ml

Mistakes of

candidates : 2030 ml

- 450 ml

1580 ml

Example 3:2002 (No. 15)/Paper 2

Azlan woke up and looked at the watch same as the watch below. Bus will takes him at 6.50 a.m. How many minutes did Azlan has before the bus arrived?

Answer : 6.50

- 6.10

0.40 = 40 minutes or

= 0 hour 40 minutes

Mistakes of candidates : 6.50

6.10 -

0.40 minutes

E. Lemah Dalam Membaca Rajah Pengukur/Penyukat/PenimbangExample 1:1994 (No. 42)/Paper 1WEIGHT MEASUREMENT

Example 2:1995 (No. 11)/Paper 2TimeWhat is the time ¼ hour after the time shown by watch beside?

Contoh 3:1997 (No. 32)/Paper 1 LENGTH MEASUREMENT

Diagram 12 shows the length of two pencils. The difference of length, in mm, between the two pencils is?

Example 4:2002 (No. 14)/Paper 1MASS

Between these measurement, which shows the right sum of 1.5kg + 250 g?

F. Tidak Cekap Dalam KBKKExample 1:1994 (No. 41)/Paper 1

Gaji Puan Tan ialah RM850. Gaji suaminya 20% lebih daripada gaji Puan Tan. Berapakah jumlah gaji mereka?

Kesilapan calon : (i) 20 x RM850 (ii) RM850

100 + 20

= 2 x RM85 RM870

= RM170

Jawapan :

(i) Pn. Tan = RM850

lebih = 20/100 x 850 = RM170

suami = 850 + 170 = 1020

JUMLAH = 850 + 1020 = RM1870

(ii) 120 x 850

100

=10200/100

= RM1020

J = 850+1020

= RM1870

(ii) 120 x 850

100

=12 x 85

= RM1020J = 850+1020 = RM1870

Contoh 2:1995 (No. 18)/Kertas 1

1800 biji manik dibahagi antara Karen dan Mona. Karen mendapat 200 biji manik lebih daripada Mona. Bilangan manik yang Mona dapat ialah

Jawapan : 1800

- 200

1600 ÷ 2 = 800

Kesilapan calon:(i)1800 ÷ 2 = 900

- 200

700

(ii) 1800 ÷ 2 = 900

+ 200

1100

Contoh 3:1996 (No. 14)/Kertas 1

Rajah 4 menunjukkan bekas X yang mengandungi 2.4 liter dan bekas Y yang mengandungi 600 ml air. Berapa mlkah air yang perlu dituang daripada bekas X ke dalam bekas Y supaya kandungan air dalam kedua-dua bekas itu sama banyak?

Jawapan : (i) 2400 ml

- 600 ml

1800 ml ÷ 2 = 900 ml

(i) 2400 ml

+ 600 ml

3000 ml ÷ 2 = 1500 – 600 = 900ml

Kesilapan calon : (i) 2400 ÷ 2 = 1200 (ii) 2400

- 600 - 600

600 ml 1800 ml

Example 4:2003 (No. 4)/Paper 1

2 x = 4805 Answer : (i) 2 = 480

5

1 = 480 ÷ 2

5

= 240 x 5 = 1200

(ii) 2 = 480

5

= 5 x 480

2

= 2400 ÷ 2

= 1200

(ii) 2 = 480

5

= 480 x 5

2

= 1200

G. Lemah Dalam Pertukaran Unit

Contoh 1:2008 (No. 8)/Kertas 2

Give the answer in cm.

Calculate 2m 7cm ÷ 9, Answer : 207cm ÷ 9

= 23cm

a.Wrong 27cm ÷ 9 Answer : = 3 cm

b.Wrong 2007 ÷ 9 Answer : = 223 cm

Example 2:2001 (No. 11)/Paper 2

Convert 1 3/5 hour to minutes.

Answer :

(i) 1 hour x 60 = 60 minutes

3/5 x 60 = 36 minutes

96 minutes

(ii) 8/5 x 60

= 480 ÷ 5

= 96 minutes

(ii) 8/5 x 60

= 8 x 12

= 96 minutes

Example 3:2003 (No. 8)/Paper 1

7.4 kg ÷ 20 = _______ gram

Answer :

7400 ÷ 20 = 370 gram

H. Terpengaruh Dengan Soalan Lain/Terdahulu

Contoh 1:1999 (No. 15)/Kertas 2

Rajah di atas menunjukkan sebuah piramid bertapak segiempat tepat. Nyatakan,(a) bilangan bucu(b) bentuk permukaan-permukaan condong bagi piramid itu.

Answer : (a) 5

(b) segitiga sama kaki

Mistakes of candidates : (a) 5

(b) 4

Example 2:2001 (No. 11)/Paper 2

Hour minute(x 60)

Contoh 3:2001 (No. 14)/Kertas 2

Day Hour(x 24)

Mistakes of candidates :

( x 60 )

I. Fobia Dengan Soalan Penyelesaian Masalah

1. Lemah 3M

2. Lemah imaginasi

Ingat a. Fahami kehendak soalan.

4 langkah : b. Tentukan operasi.

c. Kira dengan tepat.

d. Semak semula.

J. Bentuk Tulisan Mengelirukan

CONTOH

4 9 dan sebaliknya

0 6 dan sebaliknya

8 6 dan sebaliknya

K. Pengiraan Caca Marba

CONTOH

SOALAN……………………………………………

……………………………………………................

Langkah 1……………………………………………..

Langkah 2……………………………………………..

Langkah 3……………………………………………..

BUATLAH BEGINI

RM8 40 sen + RM3.24 =

Jawapan = RM10.84

Tidak diterima RM1084 @ 10.84 sen30 % of 150

30 × 150 100

Tidak diterima 45%

= 45

L. Jawapan Tidak Konsisten