paper 2
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![Page 1: paper 2](https://reader036.fdokumen.site/reader036/viewer/2022082414/55cf8f04550346703b9813ed/html5/thumbnails/1.jpg)
Section B
1. Diberikan g ; x→2x−3 dan h : x→x4+1
Carikan
(a) g−1 ( x )
(b) g−1h(x)
(c) f (x) sekiranya fh ( x )=2 x+18
Given g ; x→2x−3 and h : x→x4+1
Find
(a) g−1 ( x )
(b) g−1h(x)
(c) f (x) such that fh ( x )=2 x+18
2. (a) Fungsi f ditakrifkan oleh f ; x→2 x−1x+3
bagi semua nilai nyata x kecuali x=-3
I. Ungkapkan f−1 dan ff dan nyatakan nilai nilai x di mana fungsi-fungsi itu
tidak ditakrifkan
II. Ungkapkan f ( x )=x dalam bentuk ax2+bx+c=0 dan seterusnya tunjukan
bahawa tidak ada nilai nilai x yang boleh dipetakan ke atas dirinya di bawah
fungsi f.
(b) fungsi g ditakrifkan oleh
g ; x→px−4x+3
, x ≠−3
Cari nilai nilai p supaya persamaan g(x)=x mempunyai hanya satu penyelesaian
![Page 2: paper 2](https://reader036.fdokumen.site/reader036/viewer/2022082414/55cf8f04550346703b9813ed/html5/thumbnails/2.jpg)
(a) Function f is defined by f ; x→2 x−1x+3
for all the real value of x except x=-3
(i) Find f−1 dan ff and state the values of x for which the functions are not
defined
(ii) Find f ( x )=x in the form of ax2+bx+c=0, hence, show that there are no
values of x, which maps onto itself under the function f
(b) Function g is defined by
g ; x→px−4x+3
, x ≠−3
Find the values of p such that g(x)=x has only one solution.