JABATAN PELAJARAN PERAK

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PEPERIKSAAN PERCUBAANSIJIL PELAJARAN MALAYSIA 2007

FIZIK (4531)

SKEMA PEMARKAHAN

Kertas soalan ini mengandungi 14 halaman bercetak

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PHYSICS PAPER 1 (4531/1)

PHYSICS PAPER 1 (4531/1)

1 D 26 D2 A 27 C3 C 28 C4 C 29 A5 C 30 B6 D 31 B7 B 32 B8 B 33 C9 C 34 A10 C 35 C11 D 36 A12 C 37 D13 C 38 B14 C 39 B15 B 40 A16 A 41 C17 B 42 D18 A 43 A19 A 44 C20 C 45 A21 D 46 C22 D 47 D23 C 48 B24 A 49 B25 C 50 A

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PHYSICS PAPER 2 (4531/2)

SECTION A

1. (a) (i) To measure the the potential difference across the wire/conductor 1 mark

(ii) Ammeter 1 mark(b) (i) Error due to the instrument which has a reading when it is not in

used 1 mark

(ii) 1 μA 1 mark(4 marks)

2. (a) (i) More responsive to heat 1 mark(ii) The fine and uniform tube allows a movement of the liquid to be

observed Easily / higher sensitivity 1 mark

(b) (i) 15 mm/1.5 cm 1 mark(ii) θº = 150 - 15 x 100

190 - 15

= 77.20

1 mark

1 mark

(5 marks)

3. (a) electromagnetic waves / transverse waves 1 mark (b) Constructive interference takes place and bright fringes are observed.

Destructive interference takes place and dark fringes are observed.2 marks

(c) Lights with one colour or one wavelength 1 mark(d) 2 marks

(6 marks)

4. (a) Total internal reflection 1 mark(b) (i) Light ray as follow

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3 marks

(c) Inverted / virtual 1 mark(d)

2 marks

(7 marks)

5. (a) Distance/time 1 mark(b) 1 Before: water levels are the same and the roof stay intact 1mark

2 After : water levels are not the same and the roof rise up 1 mark(ii) Pressure above the roof is higher compare to pressure

below1 mark

(iii) Speed increases pressure decreases or vice versa 1 mark(c) Bernoulli 1 mark(d) Q is slower and R is faster 1 mark

Q is higher and R is lower 1 mark(8 marks)

6. (a) (i) Farthest in Diagram 6.2 compare to Diagram 6.1 1 mark(ii) Decreases 1 mark

(b) streamline 1 mark(c) (i) W = 10 x 70

= 700 J1 mark1 mark

(c) (i) Kinetic energy to potential energy to kinetic energy 2 marks(d) (ii) Sound/ heat 1 mark

(8 marks)

7. (a) (i) It has a high resistance and so little or no current flows through R2. Hence the potential at B is close to 0V

1 mark

(ii) When it is dark, very little light falls on the LDR and so its resistance is high. The potential at A is close to 0V.

When it is bright, a lot of light falls on the LDR. The potential difference across the LDR drops to 0V and so the

1 mark

1 mark

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1 mark

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potential at A is close to +6V.(b) Input A Input B Output Q All correct- 2m

At least 1 wrong – 1m

All wrong- 0m

2 marks0 0 10 1 01 0 01 1 0

(c) (i) Input A: 0Input B: 0Output Q: 1

3 marks

(ii) Light level : darkSoil condition: dry

2 marks

(10 marks)

8. (a) (i) A resultant force is a single force which is a vector sum of all the forces that act on the object.

1 mark

(ii) The resultant force is equal to zero 1 mark(b) (i)

Cos θ =

θ = 360 52’

2 marks

(ii) T Sin θ + T sin θ = 202 T Sin θ = 20T = 16.67 N

3 marks

(c) (i) Tension of the string in diagram 8.3 is the maximum because the angle θ is the smallest

2 marks

(ii) Tension of the string in diagram 8.2 is the minimum because the angle θ is the largest

2 marks

(iii) Diagram 8.2 1 mark(12 marks)

SECTION B

9. (a) (i) Refraction / Total Internal Reflection 1 mark(ii) Block 1 (Rectangle) Block 2 (Prism) 2 marks

Refracted ray smaller then the incidence ray

The incidence ray is perpendicular and there is no refracted rays

Angles of incidence in the prism = Angles of reflection in the prism

1 mark

Refractive index = 1 C= Critical angle Sin C

1 mark

The ray of light comes from a dense to a less dense medium or The angle of incidence in the dense medium is greater than the critical Angle

1 mark

(b) (i) Draw a diagram to show the rays of light Total internal reflection. 180 0 fish eye view Obstacle

1 mark1 mark1 mark1 mark

(c) (i) Draw a correct ray diagram with at least 2 rays 1 mark

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Box Using two right-angled prisms Arrangement of prism Total internal reflection

1 mark2 mark1 mark 1 mark

(ii) Draw a diagram to show arrangement Right angle prism which cause the the rays to bent through 180 0 4 prism 2 eye piece 2 objective lens

1 mark1 mark1 mark1 mark

(20 marks)

10. (a) It is a coil carrying a current field 1(b) number of turns in solenoid in Diagram 10.1 is more

the magnitude of current flowing in Diagram 10.1 is bigger the number of paper clips attracted to solenoid in Diagram 10.1 is

more

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(c) (i) the strength of the magnetic field increases when the magnitude of current increases

1

(ii) the strength of the magnetic field increases when the number of turns in solenoid increases

1

(d) When the switch is on, the soft iron core becomes electromagnet. 4

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End A becomes north pole. End B becomes south pole Magnet P repels from end A Magnet Q attracts to end B

(e) (i) when the switch is on, current flows in the solenoid, soft iron core becomes electromagnet

electromagnet attracts the iron armature, the hammer hits the gong and bell rings

when the hammer moves towards the gong, the contacts open, current stops flowing

The iron core loses its magnetic

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(ii) increase the number of turns of wire the magnetic field produced by each turn overlap to produce a

resultant field which is much stronger. Increase the magnitude of the current / dry cells To increase the strength of the resultant magnetic field Replace the straight iron core with a U-shaped iron core Produce stronger magnetic field strength

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(20 marks)SECTION C

11. (a) (i) Force per unit area 1 mark(ii) High altitude low density of air

Less collision of molecules with surfaceLow altitude high density of airMore collision of molecules with surface

1 mark1 mark1 mark1 mark

(b) (i) hρg = 0.76 x 13 600 x 10 =103360 Pa

1 mark1 mark

(ii) hρg = 0.1 x 13 600 x 10 = 13600 Pa

1 mark1 mark

(iii) 0 Pa 1 mark(c) Large tyre – better stability

Liquid in hydraulic system – liquid cannot be compressedLarge mass – big inertiaLarge base area – better stabilityLow centre of gravity – better stability

Choose – MLarge tyre, liquid in hydraulic system, large mass, large base area or low centre of gravity/better stability, liquid cannot be compressed and big inertia

2 marks2 marks2 marks2 marks2 marks

(maximum 8 marks)

1 mark1 mark

(20 marks)

12 (a) (i) Half-life is the time required for the activity of a sample of the radioisotope to become halved.

1 mark

(ii) emits β – particles, 2 marks

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can penetrate the soil and emerge from the ground sufficiently long half-life after a period of 2 days the activity of the source will be

weak enough to not pose any danger

2 marks

A Geiger- muller Very sensitive detector/ it can be carried about from

place to place

2 marks

A ratemeter It gives the count rate directly

2 marks

R is suitable Emits β – particles, have sufficiently long half-life

2 marks

(b) (i) Arrangement of apparatus:

Observed the reading on the scaler without an absorber Put a piece of paper, aluminium and lead between the

source and the detector in turns. For each kind of absorber, record the reading on the

ratemeter. Carry out the same procedure for the three substances. α radiation will be stopped by all three kinds of absorber β radiation will be stopped by aluminium and lead γ will be stopped by lead only

1 mark

1 mark

1 mark

1 mark

1 mark1 mark1 mark

(c) wear a photographic badge to measure the intensity of radiation in the surroundings

store radioactive substances in a lead container use a pair of forceps or tweezers to hold a radioactive substance.

2 marks(any two)

(20 marks)

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PHYSICS PAPER 3 (4531/3)

SECTION A

NO MARKING SCHEME MARKSUB TOTAL

1 (a)(i)

(ii)

(iii)

(b)(i)

(ii)

- Base current / IB

- Collector current / IC

-Length of the connection wire

-C

- IB and IC

- Correct column of manipulated variable and responding variable

- State the units of IB and IC correctly- All the values of IC are correct- [4 or 3 values of IC are correct…..1 mark]- The values of IC are consistently to one

decimal pointIB / µA IC / mA

1

1

1

1

11

12

1

1

1

1

1

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(c )

(d)

(e)

10.0 0.520.0 1.030.0 1.540.0 2.050.0 2.5

Draw a complete graph of IC against IB

Tick √ based on the following aspects :- A. Show IB on Y-axis and IC on X-axis- B. State the units of the variables correctly- C. Both axes are marked with uniform scale- D. All five points are plotted correctly- E. Best straight line is drawn- F. Show the minimum size of graph at least 5 x 4 ( 2 cm x 2 cm ) square ( counted from the origin until the furthest point )

ScoreNumber of ticks Score

75-63-421

54321

- IC is directly proportional to IB

-Ensure all connections in the circuit are tight-No short circuit( any relevant response )

√√√

√√√√

5

1

1

5

1

1

NO MARKING SCHEME MARKSUB TOTAL

2 ( a )

(b)

( c)

(d)

-Show the method to determine the value of P by showing the corresponding horizontal line with T = 60 o C-State the value of P correctly : 120.0 kPa ± 0.1

-Show the method to determine the value of the temperature by showing the extrapolated line -State the value within acceptable range: -312 OC ± 1

-P increases linearly with T

-Draw a sufficiently large triangle( 6 cm x 3 cm )-Correct substitution

1

1

1

1

1

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2

2

1

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(e)

(f)

=

State the value / answer with correct unit =0.238 kPa oC-1

T = ( 227 + 273 )-Correction substitution P = 0.238( 227 + 273 )

-State the value of P with correct unit kPa

-the mixture of water is stirred continuously until the temperature of the water is steady

1

1

1

1

1

3

3

1

Graph of IC against IB

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1.0

IC / mA

2.0

2.5

0.5

1.5

IB / µA0 10 20 30 40 50

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100

120

80

60

40

20

0

P / kPa

40 80 120

T / o C

Graf P melawan T

-40 -80 -120 -160 -200 -240 -280 -320

120 o C

-312 o C

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Section BQuestion number 3(a) 1 If the mass increased so the acceleration decreased.(b) 1 The acceleration of an object decreases when its mass increases.(c) 1. To investigate the relationship between mass and acceleration.

2. Manipulated variable : Mass of trolleyResponding variable : Acceleration

3. Constant variable : Force 4. Ticker tape, cellophane tape, ticker timer, power supply, trolley, friction

compensated runway and rubber band.

5. Diagram and label.

6. A trolley is pulled by rubber band which provides a constant unit of force.

7. Cut into 5- tick strips and a tape chart for the motion of the trolley is made. The acceleration of the trolley, a is calculated and recorded in table.

8. Repeated with two and then three identical trolleys stacked up.

9. The result is recorded in the table.Mass, m/Number of

trolleys1/m Acceleration, a/cms-2

123

10. A graph of a against 1/m is plotted.

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Question 4.

(a) 1. The brightness of the bulb increased when the length of the wire decreased. (b) 1. The length of wire increase, the resistance of a conducting wire also increases(c) 1. To investigate the relationship between length of wire and resistance.

2. Manipulated variable : Length of wireResponding variable : Resistance, R

3. Constant Variable : Thickness of wire, type of wire, temperature of wire.4. Ammeter, Voltmeter, battery, rheostat, switch, 100 cm constantant (s.w.q 24),

connecting wires.5. Firgure.

6. Measure the initial length, l = 20 cm.7. Fix the ammeter, I = 0.5 A. The reading of the voltmeter, V is recorded in

table. The value for resistance R = , is calculated.

8. Repeated for l = 40 cm, 60 cm, 80 cm and 100 cm. Calculated the resistance for each of the length of wire.

9. Tabulation of the data.

10. Plot a graph of R against l.

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l/cm I/A V/V R=V/I Ω20.040.060.080.0100.0

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