SPM Trial 2009 Phy Ans (Pahang)

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Answer Scheme

Jabatan Pelajaran Negeri Pahang (JPNP) 2009

Trial Exam 2009 Physics Paper 1

1 C 11 B 21 A 31 D 41 C

2 A 12 D 22 D 32 C 42 D

3 D 13 A 23 C 33 A 43 A

4 A 14 D 24 A 34 B 44 C

5 D 15 B 25 B 35 B 45 A

6 C 16 D 26 C 36 A 46 A

7 C 17 C 27 B 37 B 47 C

8 A 18 D 28 B 38 D 48 C

9 B 19 C 29 B 39 C 49 D

10 C 20 C 30 D 40 D 50 D

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PHYSICS Paper 2 (MARKING SCHEME)- Trial Examination F5 2009 JPN Pahang.

Q1 Marking scheme Marks

(a) 5 kPa 1

(b)(i) Perpendicular to the scale of Bourdon Gauge 1

(ii) 165 kPa 1

(c) increase 1

TOTAL 4

QQ22 EEXXPPLLAANNAATTIIOONN MMAARRKKSS((aa)) Tendency of object to remain at rest or moving with

uniform velocity1

((bb)) Mass in 2.1(a)


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((bb)) D : Reading of rate meter increase 2

((cc))((ii))226Ra 222Rn = 4

88 86 2

He2

((cc))((iiii))Sodium: 45/3=15 hrs

Cobalt 60: 15.9/3 = 5.3 yrsRadium : 4860/3 = 1620 yrs

4

((dd)) Sodium 24 :short half lifeEmit beta, can penetrate soil 1

11

TOTAL 12

Q9 Marking scheme Marks

(a) deflected 1

(b) -in 9(a) incident angle equal reflected angle

-incident angle 9(a) < 9(b)

-reflected angle9(a)< 9(b)

Relate : incident angle increase, reflected angle increase

Physics concept : incident angle = reflected angle

Name : Law of reflection

1

1

1

1

1

(c) Bottom edge of mirror from floor = 150 cm /2

= 75 cm

Height of mirror =160 cm /2

= 80 cm

2

2

(d) modification explanation

Device : periscope Cheaper than CCTV

2 plane mirrors // 2 prisms Reflect light from object

Mirrors are arranged Parallel Light from first mirror will be

reflected into second mirror

Light from second mirror is

reflected into the observers

eyes

Tube or casing to hold mirror easier to handle periscope

Mirrors are at 45 angle

Diagram also accepted

10 (max)

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TOTAL 20

QQ1100 EEXXPPLLAANNAATTIIOONN MMAARRKKSS((aa)) Work done to transfer 1 C charges from one point to another 1

((bb)) o Electrical power is generated at high current and low voltage

o Before transmission, current passes through step up

transformer

o During transmission, electrical power is at low current and high

voltage to reduce power loss

o At reception point, current passes through step down

transformer

o At reception, electrical power is at low voltage and high current

5

((cc)) o Nonrenewable resources : natural gas, petroleum

o : will be depleted

o : pollute the environment

o Renewable resources : hidro, solar & wind

o Will not be depleted

o : does not pollute environment

4(Max)

((dd))((ii))

Characteristic Explaination

Material: steel alloy Strong, will not breakeeasily

U shape steel alloy Not too heavy

Trust and support join Can support bigger weight

Large diameter cable Less resistance

made from small diameterand laminated wire

Reduce eddy current

Cable made from lowdensity material

Cable is not heavy

*Accept any relevant answers

10(max)

TOTAL 20

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Q11 Marking Scheme Marks11 (a) Power is rate of work done 1

(b) -low mass-more agile

-high height-easy to shoot goal

-responding time fast easy to catch ball-power high(short time to move brick)-will not tire easily// more energy

-small time to complete 100m run- can run fast

Choose C: low mass, tall, respond fast, high power & can run fast

10

(c) -runner has Inertia

-to continue moving forward

-the legs stop, body continue moving forward

-Unstable and fall

1111

(d)

Student 1 : power = mgh/t

= 55 x 10 x 10/ 12

=458 W

Student 2: power = 60 x 10 x 10 / 14

=428 W

Student 1 has higher power

1

1

11

1

12(a) -intrinsic semiconductor such as silicon atom

-doped with pentavalent atom such as phosphorous

- each pentavalent atom contribute one free electron

11

(b)

(i) Bulb 12.2(ii)

- Electron from n-type drift to p-n junction- Holes from p-type drift to p-n junction- At the junction electrons and holes combines to ensure continuous

current flow. Bulb light up

1

1

1

1

(c) (i) Ratio Np: Ns =Vp:Vs

=240V:24V

=100 ( to get 24 V output)(ii)type of core :Laminated soft iron core (reduce power loss due to eddy

current in the core)

(iii)full wave rectification: (less power loss & continuous current)

2

2

2

(d)(i) Full wave rectification circuit diagram

2

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v

Input signal alternating current

v

Output signal full wave rectification

1

1

(ii) Why

- To smoothen the current

How

- When current increases in circuit capacitor stores charges- When current decreases in the circuit capacitor discharges (supply

charges to the circuit)

- Make the current flow more stable

1

111

TOTAL 20

t

t

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4531

PERSIDANGAN KEBANGSAAN PENGETUA-PENGETUA

SEKOLAH MENENGAH

NEGERI PAHANG

PEPERIKSAAN PERCUBAAN SPM 2009

PHYSICS

PERATURAN PEMARKAHAN

Peraturan pemarkahan ini mengandungi 17 halaman bercetak

4531

SULIT

4531

Fizik

September

2009

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2

PHYSICS

Paper 3

SECTION A

Question 1

1 1 (a) (i) 1 State the correct manipulated variable

Length /L

1 (ii) 1 State the correct responding variable

Resistance /R // Potential difference / V

1 (iii) 1 State one fixed variable correctly

Diameter of the wire // Cross-sectional area of the wire // Type of

wire //current

6 (c) 6 TabulateL, I, V andR correctly

Give a tick () based on the following:

A Columns L, I, V and R

B Correct units for I, V and R

C All values of L correct

D All values of I correct

E All values of V correct

F All values of V consistent to 1 or 2 d.p.

G All values of R correct

H All values of R consistent to 1, 2,3 or 4 d.p.

L / cm I/ A V/ V R /

20.0 0.2 0.5 2.5

30.0 0.2 0.7 3.5

40.0 0.2 0.9 4.5

50.0 0.2 1.1 5.5

60.0 0.2 1.3 6.5

Note forG : Accept e.c.f. from E

Marks awarded :

Number of Marks

8 6

6 - 7 5

4 - 5 4

3 3

2 2

1 1

Total marks : 6

Question 1 (continued)

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3

5 (d) 5 Draw correctly a graph ofR againstL

Give a tick () based on the following:

A R at they-axis,L at thex-axis

B Correct units at both axes

C Uniform scale at both axes

D 5 points plotted correctly

[Note : 3 or 4 points plotted correctly : ]

E Best straight line

F Minimum size of graph 5 x 4 big squares

(Big square : 2 cm x 2 cm)

(From the origin to the last point)

Marks awarded :Number of Marks

7 5

5-6 4

3-4 3

2 2

1 1

Total marks : 5

1 (e) 1 State the correct relationship based on the straight line drawn

For a straight line with positive gradient passing through the

origin,

Resistance is directly proportional to length /R directly proportional

toL / LR

For a straight line with positive gradient that does not pass

through the origin,

Resistance increases linearly with length

1 (f) 1 State one suitable precaution

Check the voltmeter for zero error and make zero adjustment //

Position of the eye such that the image of the pointer in the mirror isblocked by the pointer to avoid parallax error

16

Question 2

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Question 2

2 2 a(i) 1 Draw the extrapolation line fromt = 1 min to the y-axis

2 State the correct value of

25C

1 (ii) 1 State the correct relationship of and t increases linearly with t

3 (iii) 1 Construct a sufficiently large triangle (4x4)

2 Make the correct substitution

69-37

5-1

3 State the correct value with unit

8.0C min

-1

2 b(i) 1 Make correct substitution

E=P x t = 200 x 5 x 60

2 State correct answer with unit

60 000 J

3

1

(ii)

c

1

2

3

1

Make the correct substitution

C = 60 P =

mM 8 x 0.4

60 x 200

State the correct answer

3750

State the correct unit

J kg-1

C-1

State one suitable precaution

12

-Eye perpendicular to scale of thermometer to avoid parallax error

-Repeat experiment 4 times and calculate average

-Stir cooking oil before taking thermometer reading to get uniformtemperature

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Section B

Question 3

1 3(a) 1 Write a suitable inference

The object distance affects the size of the image1 (b) 1 Write a suitable hypothesis

The greater the object distance, the smaller the size of the image

10 (c) (i) 1 State the aim of the experiment

To investigate the relationship between the object distance and thesize of the image

(ii) 2 State the manipulated variable and responding variable

Manipulated variable : object distance, u

Responding variable : size of the image,H

3 State the fixed variable

Focal length of the lens / type of lens

(iii) 4 State the list of apparatus and materials

Convex lens with holder, light bulb with power supply, screen,metre rule

(iv) 5 Draw a functional arrangement of the apparatus

Light bulb in holder connected to power supply// Cross-wire as theobject in front of the bulb, convex lens in holder and screen allalign.

(v) 6 State how the manipulated variable is controlled

The convex lens is placed at distance of, u = 15 cm from the object

7 State how the responding variable is measured

The screen is adjusted until a sharp image is formed on it.The size of the image,His measured.

8 State how the procedure is repeated to obtain at least 5 sets ofresults

The procedure is repeated with values ofu = 20 cm, 25 cm, 30 cm,35 cm and 40 cm.

(vi) 9 State how the data is tabulated

u / cm H/ cm

15

20

2530

35

40

10 State how the data is analysed

A graph ofHagainst u is drawn

12

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6

Question 4

1 4(a) 1 Write a suitable inference

depth affects wavelength

1 (b) 1 Write a suitable hypothesis

Depth increases, wavelength increases10 (c) (i) 1 Write the aim of the experiment

To investigate the relationship between depth and wavelength

(ii) 2 State the manipulated variable and responding variable

Manipulated variable : depth, h

Responding variable : wavelength,

3 State the fixed variable

frequency

(iii) 4 State the complete list of apparatus and materials

D.c. power supply, ripple tank and accessories, lamp, metre rule,

white paper, 5 pieces of perspecs/glass, stroboscope(iv) 5 Draw a functional diagram of the apparatus

(v) 6 State how the manipulated variable is controlled

The current was switched on.

The put one piece of perspecs in the ripple tank

7 State how the responding variable is measured

Mark the position of wave on the white paper as seen through thestroboscope

Measure the wavelength

8 State how the procedure is repeated to obtain at least 5 sets of

resultsThe procedure was repeated for different depth by putting pieces of

perspecs on top of the previous perspecs in the ripple tank; 2,3,4 and5 number of perspecs.

(vi) 9 State how the data is tabulated

Depth/ number of

perspecs

Wavelength / cm

1

2

3

4

5

10 State how the data is analysed

A graph ofdepth against wavelength is drawn

12

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SPM Trial 2009 Phy Ans (Pahang)

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