STPM Math T Formulae 954(1)

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    *Kertas soalan ini SULIT sehingga peperiksaan kertas ini tamat.

    [Lihat sebelah

    SULIT*

    SULIT* 1

    MATHEMATICAL FORMULAE

    Trigonometrical identities

    sin(A B)=sin A cos B cos A sin B

    cos (A B)=cos A cos B sin A sin B

    tan (A B)=

    sin 2A = 2 sinA cosA

    cos 2A = cos2A sin2A = 2 cos2A 1 = 1 2sin

    2A

    tan 2A =

    Sums of series

    For an arithmetic series

    For a geometric series

    Binomial expansions

    (a + b)n

    = an

    + an1b + a

    n2b2

    + + anrb

    r + + bn, n

    Conics

    Parabola with vertex (h, k), focus (a + h, k) and directrixx=a + h(yk)

    2= 4a(xh)

    Ellipse with centre (h, k) and foci (c + h, k), (c + h, k), where c2 = a2 b2

    Hyperbola with centre (h, k) and foci (c + h, k), (c + h, k), where c2

    = a2

    + b2

    (x -h)2

    a2(y -k)2

    b2+ = 1

    (x -h)2

    a2(y -k)2

    b2 = 1

    ( )

    n

    1 ( )

    n

    2 ( )

    n

    r

    (1 +x)n = 1 + nx + x2 + + xr + , n , |x| < 1n(n -1)2!

    n(n -1)(n-r+ 1)

    r!

    +Z

    2 tan A

    1 - tan2 A

    tan A tan B1 tan A tan B

    Sn = , a 1a(1 -rn)1 -r

    Sn = n(a + l) = n[2a + (n - 1)d]12

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    CONFIDENTIAL*

    BLANK PAGERUMUS MATEMATIK

    Identiti trigonometri

    sin(A B)=sin A kos B kos A sin B

    kos (A B)=kos A kos B sin A sin B

    tan (A B)=

    sin 2A = 2 sinA kosA

    kos 2A = kos2A sin2A = 2 kos2A 1 = 1 2sin

    2A

    tan 2A =

    Siri hasil tambah

    Bagi siri arithmetik

    Bagi siri geometrik

    Kembangan binomial

    (a + b)n

    = an

    + an1b + a

    n2b2

    + + anrb

    r + + bn, n

    Keratan kon

    Parabola dengan bucu (h, k), fokus (a + h, k), dan direktriksx=a + h(yk)

    2= 4a(xh)

    Elips dengan pusat (h, k) dan fokus (c + h, k), (c + h, k), dengan c2 = a2 b2

    Hiperbola dengan pusat (h, k) dan fokus (c + h, k), (c + h, k), dengan c2

    = a2

    + b2

    (x -h)2

    a2(y -k)2

    b2+ = 1

    (x -h)2

    a2(y -k)2

    b2 = 1

    ( )

    n

    1 ( )

    n

    2 ( )

    n

    r

    (1 +x)n = 1 + nx + x2 + + xr + , n , |x| < 1n(n -1)2!

    n(n -1)(n-r + 1)

    r!

    +Z

    2 tan A

    1 - tan2 A

    tan A tan B1 tan A tan B

    Sn = , a 1a(1 -rn)1 -r

    Sn = n(a + l) = n[2a + (n - 1)d]12

    12