STPM Trial 2009 Phy Q&A Terengganu

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    CONFIDENTIAL*

    960/1

    *This question paper is CONFIDENTIAL until the examination is over CONFIDENTIAL

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    Instructions to candidates :

    DO NOT OPEN THIS BOOKLET UNTIL YOU ARE TOLD TO DO SO.

    There are fifty questions in this paper. For each question four suggested answers are given.Choose one correct answer and indicate it on the multiple choice answer sheet provided.

    Read the instructions on the multiple choices answer sheet very carefully.

    Answerall questions. Marks will not be deducted for wrong answers. The total score for this

    paper is the number of correctly answered questions.

    This question paper consists of 18 printed pages .

    PHYSICS

    PAPER 1

    14

    3 hours

    JABATAN PELAJARAN

    NEGERI TERENGGANU

    960/1 TRIAL

    2009

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    2

    Physics 960

    Constants value

    speed of light in vacuumpermeability of vacuum

    permittivity of vacuum

    magnitude of electron charge

    Planck constant

    atomic mass unit constant

    electron rest mass

    proton rest mass

    molar gas constant

    Avogadro constant

    Boltzmann constant

    gravitational constant

    free fall acceleration

    co

    o

    e

    h

    u

    me

    mp

    R

    L, NA

    k

    G

    g

    ==

    =

    =

    =

    =

    =

    =

    =

    =

    =

    =

    =

    =

    3.00 x 10

    8

    m s

    -1

    4 x 10-7 H m-1

    8.85 x 10-12 F m-1

    [1/(36 )] x 10-9 F m-1

    1.60 x 10-19 C

    6.63 x 10-34 J s

    1.66 x 10-27 kg

    9.11 x 10-31 kg

    1.67 x 10-27

    kg

    8.31 J K-1 mol-1

    6.02 x 1023

    mol-1

    1.38 x 10-23 J K-1

    6.67 x 10-11

    N m2

    kg-2

    9.81 m s-2

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    3 Two block,Xand Yof masses m and 2m respevticely are accelerated along a smooth horizontal

    surface by a force Fapplied to blockXas shown in the diagram

    What is the magnitude of the force exerted by block Y on block X during this acceleration?

    A3

    F B

    3

    2F C

    2

    F D 0

    4 A small mass metal sphere of mass m is moving trough a viscous liquid. When it reaches a constant

    downward velocity , which of the following describes the change with time in the kinetic energy andgravitational potential energy of the sphere?

    Kinetic energy Gravitational potential energy

    A Constant and equal to2

    2

    1mv Decrease at a rate of ( 2

    2

    1mvmgv )

    B Constant and equal to2

    2

    1mv Decrease at a rate of mgv

    C Increases at a rate of mgv Decrease at a rate of mgv

    D Increases at a rate of mgv Decrease at a rate of ( mgvmv 2

    2

    1 )

    5 A particle moves with constant speed in a horizontal circle. Which of the following quantities is

    zero?

    A Resultant force

    B Angular acceleration

    C Angular velocity

    D Centripetal acceleration

    YX

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    5

    6 A mass of 0.05 kg is attached to one end of a piece of elastic of unstreched length 0.50 m. The

    force constant of the elastic is1

    40

    Nm . The mass is rotated steadily on a smooth table in a horizontalcircle of radius 0.70 m as shown below

    What is the approximate speed of the mass?

    A1

    20

    ms 2 B1

    24

    ms C1

    11

    ms D1

    15

    ms

    7 A small ball of weight W is suspended by a light thread. When a strong wind blows horizontally,

    exerting a constant force F on the ball, the thread makes an angle to the vertical as shown

    F

    W

    Which equation correctly relates , Fand W?

    AW

    F=cos

    BW

    F=sin

    CWF=tan

    DF

    W=tan

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    8 The diagram below shows a piece of inextensible string which passes trough a pulley. The pulley

    has a radius of 0.05 m and moments of inertia24

    100.6 kgm

    . The end Q is held such that an object P

    of mass 0.2 kg is stationary at a height of 0.2 m from the floor.

    P Q

    0.2 m

    If end Q is released and the pulley is rough enough to prevent the string from slipping, find the speed ofP when it touches the floor.

    A1

    35.1ms B 123.1

    ms C 101.1ms D 148.1

    ms

    9 The gravitational potential energy PE of a body varies with its distance r from the centre of a planet

    as shown in the diagram below

    PE

    0 r

    What does the gradient at any point on the curve present?

    A the gravitational potential at that value ofr

    B the gravitational field strength at that value ofrC the acceleration of the body towards the planet

    D the force pulling the body towards the planet

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    7

    10 On the ground, the gravitational force on a satellite is W. What is the gravitational force on thesatellite when at a height R/50, where R is the radius of the earth A

    A 1.02 W B 1.04 W C 0.96 W D 0.98 W

    11 A particle of mass m performs simple harmonic motion with an amplitude a and a frequency f. Thetotal energy of this simple harmonic motion is

    A222

    2 fma B 222 fma C 22

    2

    1fma D 222 fma

    12 Which of the following statements is true for a damped system of oscillation ?

    A The oscillating amplitude is maximum when forced frequency is almost the same as the natural

    frequency

    B The system does not oscillate at its natural frequency

    C When resonance takes place, the system does not lose energy

    D Damping causes the oscillating frequency to become gradually smaller

    13 Which of the following correctly summarizes what happens when light waves of frequency f and

    wavelength move from air to glass ?

    f

    A increases decreases

    B remains the same remains the same

    C remains the same decreases

    D decreases remains the same

    14 To recieve FM waves of frequency 100 MHz, the total length of a bipolar half-wave aerial most

    suitable for use is

    A 0.75 m B 1.00 m C 1.50 m D 2.25 m

    15 The fact that light waves are transverse wave can be shown by

    A diffraction

    B polarization

    C interference

    D Doppler effect

    E photoelectric effect

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    8

    16 A wire under increasing tension, undergoes extension as shown in the graph.

    How much work is done on the wire to cause an extension of 9 mm ?

    A 0.72 J B 0.43 J C 0.36 J D 0.29 J

    17 A steel wire has an original length of l , cross-sectional area of A, and Young modulus of E. The

    force constant can be expressed as

    Al

    AE B

    E

    Al C

    Al

    E D

    AE

    l

    18 Equation W = p (V2 V1) represents the work done by a gas during

    A free expansionB isothermal expansion

    C adiabatic expansion

    D expansion at constant pressure

    19 Find the work done when 3 moles of an ideal gas is expanded from 4 dm3

    to 6 dm3

    at 400 K

    A 8 kJ B -4kJ C 4kJ D 6kJ

    20 The specific heat capacity at constant volume for an ideal gas is 2.4 x 102 J kg-1 K-1. The change in

    the internal energy of 5.0 x 10-3

    kg of the gas when the temperature of the gas is increase from 27o

    C to327oC is

    A 32 J B 49 J C 180 J D 360 J

    0

    20 -

    40 -

    60 -

    20 -

    80 -

    Tension/ N

    Extension / mm105

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    9

    21 A ln p (pressure) against ln V (volume) graph is sketched as shown.

    What is the quantity represented by the gradient of the straight line ?

    A - B

    C Change in internal energy

    D Change in heat energy

    22 An ideal gas is expanded at constant pressure, then cooled at constant volume, and finally

    compressed adiabatically until it is returned to its original state. Which graph shows the changes which

    occur to the gas?

    A B

    C D

    ln p

    ln V0

    P

    V

    V

    P

    P

    V

    V

    P

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    23 A composite rod consists of a rod P and a rod Q where P is a better thermal conductor. The ends Mand N are maintained at constant temperatures TM and TN respectively where TM > TN. If the composite

    rod is well insulated, which of the following graphs shows the variation of temperature, along thecomposite rod?

    A B

    C D

    24 Which of the following statements is true about electrically equipotentials surfaces?

    A The charge density is uniform

    B No work is done to move a charge along an equipotential surface

    C The electric field at any point on the equipotentials surface is zero

    D There is no electric potential difference between 2 nearby electrically equipotential surfaces.

    P Q

    M

    T N

    T NM

    TN

    TM

    T NM

    TN

    TM

    T NM

    TN

    TM

    T NM

    TN

    TM

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    11

    C1

    C2

    + -

    + -

    Drift velocity

    Potential difference

    Drift velocity

    Potential difference

    Drift velocity

    Potential difference

    Drift velocity

    Potential difference

    A B

    DC

    25 Figure shows two capacitors are connected as shown. A capacitor 1C with a capacitance of F4 is

    charged to C200 and another capacitor 2C with a capacitance of F3 is charged to .300 C The total

    energy lost in the two capacitor are

    A 0 B J3100.2 C J2108.1 D J2100.2

    26 Which graph best represent the variation in the drift velocity of the electrons in a uniform copper

    wire as the potential difference across the wire changed? (Assume temperature of the wire remains

    constant)

    27 The resistance of a piece of pure silicon decreases rapidly with increasing temperature because

    A the charge carriers move rapidly

    B the number of charge carriers increases

    C the ratio of negative charge carriers to positive charge carriers increases

    D the ratio of positive charge carriers to negative charge carriers increases

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    12

    28 Kirchhoffs two laws for electric circuits can be derived by using certain conservation laws. Onwhich conservation laws do Kirchhoffs law depend?

    Kirchhoffs first law Kirchhoffs second law

    A charge current

    B charge energy

    C current mass

    D energy current

    29 The diagram below shows a model of an atom in which two electrons move around a nucleus in a

    circular orbit. The electrons complete one full orbit in s15100.1

    .

    What is the current caused by the motion of the electrons in the orbit?

    A A34

    106.1

    B A34

    102.3

    C A4

    106.1

    D A4

    102.3

    30 An electron moving with uniform velocity enters a magnetic field which is perpendicular to its

    direction. The electron will then move

    A in a straight line as before

    B in a straight line parallel to the magnetic field

    C in a circle at a plane normal to the magnetic field

    D in a parabola at a plane normal to the magnetic field

    31 Three straight conductors X, Y and Z are carrying currents of the same magnitude as shown. Which

    of the following represents the resultants force acting on the conductor X?

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    13

    reactance

    frequency

    P

    Q

    32 The e.m.f induced in a coil of wire, which is rotating in a magnetic field, does not depend on

    A the area of the coil

    B the resistance of the coil

    C the angular speed of rotation

    D the number of turns on the coil

    33 When the speed of an electric motor is increased due to a decreasing load, the current flowing

    through it decreases. Which of the following is the best explanation of this?

    A The induced back e.m.f increases

    B The resistance of the coil changes

    C Frictional forces increased as the speed increases

    D At high speeds it is more difficult to feed current into the motor

    34 Graph shows the variation of reactance and frequency of an alternating current flowing through two

    electrical components P and Q. What are the components P and Q ?

    Component P Component Q

    A capacitor resistor

    B inductor resistor

    C inductor capacitor

    D resistor capacitor

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    14

    iV

    time

    0V

    time

    0V

    time

    A

    0V

    time

    0V

    time

    B

    C D

    35 Figure shows an op-amp acting as an integrator with negative feedback. Choose 0V for the shown

    iV .

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    15

    36 Which of the following is true about the difference between an electromagnetic wave and amechanical wave?

    Electromagnetic wave Mechanical wave

    A Cannot produce stationary waves Can produce stationary waves

    B Longitudinal waves only Longitudinal or transverse waves

    C Cannot propagate in vacuum Propagates in vacuumD Travel with a speed almost the same Travel with a speed less than that

    or the same as speed of light of light

    37 An object is placed 5 cm from a convex mirror with a radius of curvature of 20 cm. The image

    formed is

    A 3.3 cm in front of the mirror and is diminished

    B 3.3 cm behind the mirror and is enlarged

    C 4 cm in front of the mirror and is diminished

    D 4 cm behind the mirror and is enlarged

    38 Two waves are said to be coherent if both the waves have

    A the same phase

    B the same amplitude

    C the same frequency

    D the same wavelength

    39 In a Youngs double slit experiment, when the distance between the slits and screen is increased

    A the fringe separation decreases the maximum intensity of bridge fringes decreasesB the fringe separation decreases the maximum intensity of bridge fringes increases

    C the fringe separation increases the maximum intensity of bridge fringes decreases

    D the fringe separation increases the maximum intensity of bridge fringes increases

    40 Which of the following is true based on the photoelectric effect?

    A The emission of electrons will not occur for very low light intensity.

    B The number of electrons produced per second does not depend on the intensity of light.

    C The maximum velocity of the electrons increases when the wavelength of light decreases.

    D The average kinetic energy of the electrons decreases when the frequency of light increases.

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    41 When light of wavelength 350 nm is incidented on a metal surface, photoelectrons with maximumkinetic energy 2.0 eV are emitted from the surface. What is the maximum wavelength of light that can

    emit photoelectrons from the metal?

    A 200 nm B 580 nm C 620 nm D 802 nm

    42 What is the maximum possible number of emission spectral lines produced by an atom which has

    five distinct energy levels only?

    A 4 B 6 C 10 D 12

    43 From Bohrs theory for hydrogen atom, the n-th energy level in eV is given by

    ...,3,2,1,6.13

    2== n

    nEn

    What is the wavelength of a photon which is absorbed to excite an electron from ground state to the level

    n = 4?

    A 1.36 x 10-9 m

    B 9.15 x 10-8

    m

    C 9.54 x 10-8

    m

    D 1.46 x 10-6

    m

    44 When the potential difference of an X-ray tube increases, the intensity of the K characteristic line

    increases because

    A more electrons cause the transition which produces the K characteristic line

    B the frequency corresponding to the K characteristic line has increasedC the number of electrons escapes from the filament has increased

    D anode temperature in the X-ray tube has increased

    45 Which of the following is not true of the charge of an electron ?

    A It is measured in Coulombs

    B Its has the same magnitude as the charge of a proton

    C It has the same magnitude as the charge of a beta particle

    D It can only be determined by experiment when its mass is given

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    17

    46 In the mass spectrometer shown in the figure above, the ions which follow paths P1 and P2 always

    have

    A the same charge

    B the same speed

    C the same mass

    D the same acceleration

    47 The table below shows the count rate of a radioactive source at different times at a location.

    Time(hours)Count rate (count per second )

    With source Without source

    10 60 20

    20 30 20

    30 20 20

    Determine the half-life of the source based on the data given in the table.

    A 5 hours B 10 hours

    C 12 hours D 18 hours

    48 At time t = 0 minute, 16 mg of a radioactive element X of half life 4.0 minutes is inserted into a

    closed container. At time t = 8.0 minute, 8 mg of the radioactive element X is added into the container.What is the mass of the radioactive element X left in the container at time t = 12.0 minutes ?

    A 2 mg B 3 mg

    C 6 mg D 8 mg

    49 The energy of the sun is acquired through

    A the liberation of energy from unstable nuclei

    B the liberation of helium nuclei to form hydrogen nuclei

    C the fission of uranium nuclei by neutrons

    D the fusion of hydrogen nuclei to form helium nuclei

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    18

    50 A strong nuclear force

    A abides by the inverse square law

    B is short range

    C is repulsive if the charge of the particles are of the same type

    D is an electrostatic force

    END OF QUESTION PAPER.

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    Name : NRIC :

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    Instructions to candidates :

    This question paper consists of 15 printed pages

    Answerallthe questions in Section A in thespaces provided.Answer any four questions from section B.

    For this section, write your answers on theanswer s heets pr ovided. B egin eachanswer on a f resh sheet of paper. Answers

    should be i llustrated by l arge, c learly

    labeled diagrams wherever suitable.

    Answers may be written in either Malay orEnglish.

    Arrange y our ans wer i n num erical or der

    and tie the answer sheets to this booklet.

    For examiners use

    Section Marks Marks

    Obtained

    A

    1 5

    2 5

    3 54 5

    5 5

    6 5

    7 5

    8 5

    B

    9 15

    10 15

    11 15

    12 15

    13 15

    14 15

    TOTAL 100

    TRIAL

    2009

    JABATAN PELAJARAN

    NEGERI TERENGGANU

    960/2

    PHYSICS

    PAPER 2

    2 hours

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    2

    Physics 960

    Constants value

    speed of light in vacuumpermeability of vacuum

    permittivity of vacuum

    magnitude of electron charge

    Planck constant

    atomic mass unit constant

    electron rest mass

    proton rest mass

    molar gas constant

    Avogadro constant

    Boltzmann constant

    gravitational constant

    free fall acceleration

    co

    o

    e

    h

    u

    me

    mp

    R

    L, NA

    k

    G

    g

    ==

    =

    =

    =

    =

    =

    =

    =

    =

    =

    =

    =

    =

    3.00 x 10

    8

    m s

    -1

    4 x 10-7 H m-1

    8.85 x 10-12 F m-1

    [1/(36 )] x 10-9 F m-1

    1.60 x 10-19 C

    6.63 x 10-34 J s

    1.66 x 10-27 kg

    9.11 x 10-31 kg

    1.67 x 10-27

    kg

    8.31 J K-1 mol-1

    6.02 x 1023

    mol-1

    1.38 x 10-23 J K-1

    6.67 x 10-11

    N m2

    kg-2

    9.81 m s-2

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    3

    1. A water wheel has eight bucket equally spaced around its circumference as shown in diagrambelow.

    045

    1.8 m

    The wheel makes six revolution per minute. Calculate

    (a) the total change in potential energy of the water in the buckets in one revolution of the wheel.

    [2]

    (b) the average input power to the wheel

    [2]

    (c) Suggest why a larger number of small bucket is preferred to a smaller number of large bucketcontaining the same total mass of water

    [1]

    Water

    46

    2

    1

    8

    73

    Water

    Full bucketEm t bucket

    Direction of rotation

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    4

    2. The figure below illustrates a mass which can be made to vibrate vertically between two springs.

    The vibrator itself has constant amplitude. As the frequency is varied, the amplitude of vibration of

    the mass is seen to change as shown in Fig 3A

    Fig 3A

    (a) Name the phenomenon which is illustrated in Fig 3A.

    [1](b) For the mass vibrating at maximum amplitude, calculate the angular frequency.

    [2]

    (c) A light piece of card is fixed to the mass with its plane horizontal. On Fig 3A, draw a curve toshow the new variation with frequency of the amplitude of vibration of the mass.

    [1](d) State one situation in which the phenomenon illustrated in Fig 3A is used to advantage.

    [1]

    variable frequency

    vibrator

    mass

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    5

    3 A uniform copper rod with thermal conductivity 380 W m-1 K-1 which is perfectly insulated has a

    cross-sectional area of 2.50 cm2 and length 20.0 cm. Heat is conducted by the copper rod. When the

    steady state is achieved, the temperatures at the ends of the rod are 130 oC and 20 oC.

    Calculate

    (a) the rate of heat flow in the rod.

    [3]

    (b) the temperature 15.0 cm from the hot end.

    [2]

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    6

    4 (a) Electrical conduction in a metal can be explained in terms of motion of free electrons. State the

    estimated values at room temperature for mean random velocity of the free electrons.

    [1]

    (b) A 5.0 A current flows through a wire of length 1.50 m and crass sectional area of 1.2 mm2

    where the potential difference across the wire is 0.24 V.

    (i) Calculate the power dissipated from the wire

    [2]

    (ii) Explain what will happen to the drift velocity of the free electrons if the power produced in

    the wire is increased.

    [2]

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    7

    V2

    V1

    330 k

    33 k

    10 k

    +15 V

    -15 V

    V0

    +

    5.

    (a) State the name of the amplifier circuit which is connected to various input as shown in the

    diagram above.

    [1]

    (b) Calculate the output voltage V0 if V1 is 0.50 V and V2 is 0.20 V.

    [3]

    (c) What happen to the output voltage if the supply 15 is replaced with V9 ?.

    [1]

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    9

    7 Monochromatic light with wavelength 365 nm illuminates a metallic surface with work function 2.30

    eV.

    (a) Calculate the maximum speed of the photoelectrons emitted.

    [3]

    (b) Estimate the de Broglie wavelength of the photoelectrons.

    [2]

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    10

    8

    The graph above represents the decay of a sample of a specific radioactive element. Find the half-life

    of the element.

    Hint :

    [5]

    t

    t

    eNrateCount

    eNN

    =

    =

    0

    0

    dt

    dN

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    11

    Section B [60 marks]

    Answer any four questions in this section

    9 (a) Define the terms moment of a force and draw a sketch to illustrate the meaning. [2]

    (b) State the condition for a body to be in equilibrium [1]

    (c) During the construction of many modern bridges, section are added from both banks until thetwo halves meet at the centre. Figure 1 below shows a new section S, of weight N5100.3 ,after it has been attached to an existing part B of a bridge

    The support cable which keeps section S in equilibrium is at an angle of0

    25 to the horizontal.

    The existing part B of the bridge provides a horizontal force on S.

    (i) Draw a labeled vector diagram and show the three forces on S [2]

    (ii) Use your diagram to determine the tension in the cable and the horizontal force which B

    exerts on S [2]

    (d) In the sport of clay pigeon shooting, a clay disc is launched into the air by a spring, and thecontestant fires a shot at the moving disc. A launching device has been modified to project the

    disc vertically upwards. The spring in the launching device has a spring constant of1

    2000Nm

    and the clay disc has mass 80g. In use the spring obeys Hookes law and the extension decreases

    from 13 cm to 7.0 cm.

    (i) Sketch a graph of force against extension for the spring and shade the area which represent

    the loss of energy stored by the spring when launching the clay disc. [2]

    (ii) Calculate

    (a) the loss of elastic potential energy of the spring [2](b) the initial speed of the clay disc, assuming all the energy lost by the spring becomes

    kinetic energy of the disc [2]

    (c) the height to which the disc will rise, assuming that air resistance is negligible. [2]

    S B

    Support cable

    N5100.3

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    12

    10 (a) State three differences between a progressive wave and a stationary wave. [3]

    (b) In large auditoriums, the walls are covered with thick curtains. State the effect of thick curtains

    on the sound waves and hence explain the advantage of this practice. [2]

    (c) Two sound waves have frequencies 890 Hz and 894 Hz respectively. The intensity of the sound

    waves at a given point is 6.3 x 10-9 W m-2.

    (i) What are the conditions required for beats to be heard from two separate sound

    sources? [2]

    (ii) What is the frequency of the resultant wave and what is the beat frequency? [2]

    (iii) Determine the maximum intensity level of the beats heard at the point concerned.

    [The minimum intensity of audible sound is 1.0 x 10-12

    W m-2

    ] [2]

    (iv) Another sound sources with intensity level 98.0 dB is located at the point. What is the ratio

    of the intensity of the first sound to that of the second sound? [2]

    (d) A high-speed train is travelling at a speed of 47.4 m s-1

    when the engineer sounds the 418 Hz

    warning horn. The speed of the sound is 343 m s-1

    . What is the frequency of the sound as

    perceived by a person standing at a crossing when the train is approaching? [2]

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    13

    11 (a) StateHookes Law [2]

    (b) Explain the main difference between elastic deformation andplastic deformation [3]

    (c) The graph shows a simplified version of the variation of the load applied against

    the extension of the material. The original length of the wire is 1.0 m and itsdiameter is 1.5 mm.

    (i) The material is brittle or ductile ? [1]

    (ii) What is the Youngs Modulus of the material ? [3]

    (iii) If the wire snaps when the load reaches the value atP, how much energy is

    required to snap the wire ? [3]

    (iv) Assume that the cross-section of the wire remains constant throughout the

    extension. What is the stress in the wire when the load reaches the value at P?

    [3]

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    1

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN ERENGGANUJABATANPELAJARAN TERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJARJABATAN PELAJARAN TERENGGANUJABATANPELAJARANTERENGGANU JABATANPELAJAR

    JABATAN PELAJARAN ERENGGANUJABATANPELAJARAN TERENGGANU JABATANPELAJAR

    MARK SCHEME

    PAPER 1 AND 2

    PHYSICS

    960

    JABATAN PELAJARAN

    TERENGGANU

    960/1/2 TRIAL

    2009

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    2

    ANSWER PAPER 1

    Question Answer Explanation

    1 AStrain=

    0/le is dimensionless

    [stress] = F/A= [pressure]

    2 B

    During the time from 0 to T, the body slides along the horizontal surface with

    zero resultant vertical force since its weight is balanced by the reaction force

    from the surface. After time T, the resultant force acting on the ball is its own

    weight W under free fall situation.

    3 B

    m

    F

    mm

    Fa

    32=

    +=

    To block X alone, )3

    )(2(m

    FmmaFF Y ==

    Hence, YF = force exerted by block Y on block X= 3

    2F

    4 B

    Kinetic energy of sphere =2

    2

    1mv = constant since v is constant.

    Potential energy of sphere = mgvdt

    dxmg =

    v x

    5 Br

    vw = is constant because v and r are constant. Hence angular acceleration = 0

    6 C

    The force constant of the elastic string is140

    Nm . Hence, the force exerted bythe string on the mass to keep it in circular motion is

    NkxF 8)50.070.0(40 === If v is the linear velocity of the mass, it is related to this centripetal force by

    r

    vmF

    2

    =

    7.0)05.0(8

    2v

    = 1

    1158.10

    == msv

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    3

    7 C

    T

    F

    W

    If T is the tension in the light thread, then

    FT =sin

    WT =cos W

    F=tan

    8 A

    22

    2

    1

    2

    1Imvmgh += rwv =

    2

    22

    += rvImvmgh

    =21 v

    rm

    +

    2

    2

    4

    05.0

    100.62.0)2.0)(10)(2.0(2 v

    +=

    135.1

    = msv

    9 D

    From

    r

    MmGUEP ==

    PE is the gravitational potential energy of a body of mass m at distance rfrom

    the centre of a planet of mass M

    Force of attraction =2r

    MmG

    dr

    dU+=

    Thus, the gradient at any point on the gravitational potential energy curve

    represent the force pulling the body towards the planet.

    10 C

    22

    1

    RW

    R

    GMmW =

    Gravitational force on the satellite when at the highest R/50

    50

    RR + from the centre of the earth = W

    RR

    R2

    2

    50

    +

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    4

    = W

    R

    R2

    2

    2

    50

    11

    +

    = 0.96 W

    11 A 2222222 2)2(2

    1

    2

    1fmafmamaE ===

    12 D

    13 C

    The frequencyis determined by the source and not the medium through which it

    flows. In a denser medium, the velocity will decrease and as a result the

    wavelength will decrease.

    14 CV = f

    (100 x 106) = 3 x 108

    = 3 m

    l= / 2 = 2/3= 1.5 m

    15 B

    16 B

    Work = area under the graph

    =310)]59)(8060(

    2

    1)560(

    2

    1[ ++

    = [(150) + (704) x310 ]

    = 430 x310

    = 0.43 J

    17 A

    k =e

    F

    E = eA

    Fl

    k =l

    EA

    18 D

    19 C =2

    1

    V

    VW Vp

    l

    Dipole aerial

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    5

    = 2

    1

    V

    VV

    V

    nRT )( nRTpV =

    = nRT1

    2lnV

    V

    =4

    6ln)400)(31.8(3 = 4043.30 J = 4kJ

    20 D

    Since V = 0,W = p V = 0,

    Q = U + W

    U = Q = mcvV= 5.0 x 10-3 x 2.4 x 102 x (600 300) J

    = 360 J

    21 A

    pV = k

    p = kV

    ln p = ln k ln V

    = - lnV + ln k

    (gradient = - )

    22 C

    23 A

    24 BVqw =

    since 00 == wV

    25 B

    Initial energy

    ( ) ( )J

    CQ

    CQ

    02.0103

    10300

    104

    10200

    2

    1

    21

    21

    6

    26

    6

    26

    2

    2

    2

    1

    2

    1

    =

    +

    =

    +

    Equivalent capacitance

    ( ) ( ) FCCC

    666

    21

    107103104 =+=

    +=

    Final energy

    JC

    Q018.0

    107

    10500

    2

    1

    2

    16

    62

    =

    =

    Energy lost,

    J3100.2018.002.0 =

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    6

    26 B

    The resistance of a copper wire remains unchanged at constant temperature and

    is given byA

    lR =

    Potential difference, V

    ( ) venvAeAl

    IRV ln =

    ==

    Since I is directly proportional to drift velocity of electrons in the wire, thus

    directly proportional to potential difference.

    27 AWhen temperature increases, electrons are freed from covalent bonds. Hence the

    number of electron-holes increases.

    28 B

    Kirchhoffs first law is related to current and depends on the conservation of

    charge

    Kirchhoffs second law is related to electric potentials and depends on the

    conservation of energy.

    29 D( )( )

    A

    t

    QI

    ItQ

    4

    15

    19

    102.3

    100.1

    106.12

    =

    ==

    =

    30 C

    31 A

    32 B

    Induced e.m.f is given by BAN= where

    N number of turns

    A area

    B flux density

    angular velocity

    33 A

    34 BP is inductor, wLXL =

    Q is resistor

    35 A

    36D

    37B r = 20cm, f = -10 cm, u = +5 cm

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    7

    cmv

    v

    vuf

    3.3

    5

    1

    10

    11

    111

    =

    =

    +=

    38 A

    39C From the formula of fringe separation

    a

    Dy

    = , Dy

    40

    C

    From Einsteins equation,

    cf

    WhfmvK

    =

    == 2maxmax2

    1

    Iffincreases or decreases,Kmax or vmax increases

    41

    D

    mf

    c

    h

    Kcf

    hfKhf

    oo

    o

    o

    7

    15

    34

    19

    9

    8max

    max

    1002.8

    10374.01063.6

    106.10.2

    10350

    100.3

    ==

    =

    ==

    +=

    42

    C

    43

    D

    mE

    hc

    hcE

    JEEE

    6

    19

    834

    1919

    2214

    1046.11036.1

    100.31063.6

    1036.1)106.1(1

    1

    4

    1)6.13(

    =

    ==

    =

    =

    ==

    44

    A

    The K characteristic line is produced by electronic transition in the target atom.

    The intensity is determined by the number of electrons hitting the target and the

    number of collisions determines the number of electronic transition.

    45 D The charge of an electron can still be determined if its mass is not given

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    8

    46 BM.massandqcharge

    ondependnotdoesitbecauseconstantB

    Ev,

    1

    1

    alwaysspeed

    qEqvB

    =

    =

    47 B

    hours

    e

    eNN t

    100693.0

    2ln2lnlifehalf

    0693.0

    204ln

    4010)1030(

    0

    ===

    =

    =

    =

    =

    48 C

    0 min 4.0 min 8.0 min 12.0 min

    16 mg 8 mg 4 mg+ 8 mg6 mg

    49 DNuclear fission :

    nHeHH 103

    2

    2

    1

    2

    1 ++

    50 BA strong nuclear force is experienced by nucleons such as protons and neutrons

    in the nucleus and are of very short range such as 1.7 x 10-15

    m

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    9

    Paper 2

    Question Answer Mark

    Structure 1

    (a)

    Total change in potential energy of water in the buckets in one revolution of the wheel

    = hmg8 = )26.1(81.9408

    = J4100.1

    1

    1

    (b)

    Average input power to wheel = number of revolutions made per unit time X change inpotential energy of the water in the buckets per revolution of the wheel

    =4

    100.160

    6

    = W3100.1

    =1kW

    1

    1

    (c)A large number of a small buckets is preferred because the rotation of the wheel would

    be smoother than the case would be when a smaller number of large buckets is used. 1

    Structure 2

    2(a) resonance 1

    2(b) From graph, fresonance = 12.5Hz

    = 2f= 2 (12.5)

    =78.5 rads-1

    1

    1

    2(c)

    1

    2(d) Microwave oven/

    radio signal receiver1

    Structure 3

    (a) dx

    dkA

    dt

    dQ =

    1

    1

    mass

    with card

    mass without

    card

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    10

    = (380)(2.5 x10-4)2

    1020

    )20130(

    = 52.25 W

    1

    (b)

    The temperature at 15.0 cm = ( )1020

    20130)(1015

    2

    2

    = 82.5 oC

    The temperature 15.0 cm from the hot end = 130 oC 82.5 oC

    = 47.5 oC

    1

    1

    Structure 4

    (a)velocity is a vector quantity. The velocities cancel out each other in any directions,

    since the number of free electrons is very large. So mean random velocity is zero.1

    (b-i)

    Power,P

    W

    IVP

    2.1

    )0.5)(24.0(

    =

    ==

    1

    1

    (b-ii)Power,

    22

    IPRIP =

    Since, nevI= , therefore 2vP

    Hence, when power increases drift velocity increases.

    1

    1

    Structure 5

    (a) Adder operational amplifier 1

    (b)

    V

    VR

    RV

    R

    RV

    f

    i

    f

    60.11

    2.010

    3305.0

    33

    330

    22

    10

    =

    +

    =

    +

    =

    1+1

    1

    (c) Output voltage will become V9 only as saturation occurs. 1

    Structure 6

    (a)( )

    =

    21

    111

    1

    rrn

    f

    where

    f = focal length,

    n = refractive index of the material of the lens,r1 = radius of curvature of the front surface receiving the incoming rays,

    r2 = radius of curvature of the hind surface where the outgoing rays emerges.

    [Rubric: Formula 1 mark; Defining symbols 1 mark]

    1

    1

    (b)In water applying the formula

    =

    211

    2 1111

    rrn

    n

    f

    mf

    cmf

    f

    25.1

    125

    20

    1

    60

    11

    33.1

    65.11

    =

    =

    +

    +

    =

    1(formula)

    1(sign of

    r)

    1(answer)

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    11

    Structure 7

    (a) Using Einsteins equation, maximum kinetic energy is

    15

    31

    19

    max

    19

    199

    834

    2max

    1023.6

    1011.9

    )1077.1(2

    1077.1

    )106.1(30.210365

    )1000.3)(1063.6(

    2

    1

    =

    =

    =

    =

    =

    sm

    v

    J

    Whc

    mv

    1

    1

    1

    (b)Momentum of the photoelectrons,

    hmv =

    m

    mv

    h

    9

    531

    34

    1017.1

    )1023.6)(1011.9(

    1063.6

    =

    =

    =

    1

    1

    Structure 8

    8

    min4.240.0284

    2ln2lnTlifeHalf

    0.0284

    182810-3

    5ln

    e

    e

    12000

    20000:

    )........(12000).......(20000

    dt

    dN

    21

    28-

    10-

    )28(

    0

    )10(

    0

    0

    0

    ===

    =

    =+=

    =

    ==

    =

    =

    ii

    i

    iieNieN

    eNrateCount

    eNN

    t

    t

    11

    1

    1

    1

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    12

    Essay

    Essay 9

    (a) The moment of a force, F is the force multiplied by the perpendicular distance, d from

    the point about which the moment is being measured example the axis of rotation

    d

    F

    1

    1

    (b) For a body to be in a equilibrium, there must be no resultant force and no resultanttorque

    1

    (c)(i)

    S

    F

    BF 0

    25

    Weight of section S, W= N5100.3

    All

    correct2

    or

    Two

    correct1

    (c)(ii) Resolving forces vertically

    =0

    25sinSF W for equilibrium

    NW

    Fs5

    0

    5

    01010.7

    25sin

    100.3

    25sin=

    ==

    Resolving forces horizontally,050

    25cos1010.725cos == SB FF

    = N51043.6

    1

    1

    (d)(i)F/N

    e/cm

    7 13

    Draw

    graphcorrect

    1

    Area

    shaded

    1

    (d)(ii)(a)Loss of elastic potential energy of the spring =

    2

    1

    2

    22

    1

    2

    1kxkx

    1

    Axis of rotation

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    13

    = )07.013.0(20002

    1 22

    = 12 J

    1

    (d)(ii)(b) Kinetic energy of the disc = Energy lost by the spring

    1221 2 =mv

    080.0

    212=v

    Initial speed =1

    3.17ms

    1

    1

    (d)(iii)(c) Gain in gravitational potential energy of the disc = lose in kinetic energy

    2

    2

    1mvmgh =

    81.9080.0

    12

    =h

    =15.3 m

    1

    1

    Essay 10

    (a)

    Progressive wave Stationary wave

    1. Wave profile moves

    2. Adjacent particles of amedium vibrate in a different

    phases

    3. The amplitude in constant forall particles of the medium

    - Wave profiles does not move

    - Particles between two adjacentnodes of a medium vibrate in the

    same phase

    - Particles between two adjacentnodes vibrate with different

    amplitudes

    1

    1

    1

    (b)Thick curtains will absorb the sound.This will reduce echo and interference of sound waves in the hall and hence the

    audience will be able to hear a performance clearly.

    1

    1

    c(i)

    Conditions:

    - the frequency of the two sound must be almost the same

    - the amplitudes from the two sound sources must be the same or almost thesame

    - waves from the two sound sources must be propagated in the same direction

    1

    1

    or 1

    c(ii)Frequency of beats = 894 890 = 2 Hz

    Frequency of resultant wave = (894 + 890) 2 = 892 Hz1

    1

    c(iii)Intensity level = log10

    10

    0

    I

    I= 10 log10

    12

    9

    100.1

    103.6

    = 38.0 dB

    1

    1

    c(iv)

    =

    2

    1

    21 log10I

    I 1

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    14

    =

    2

    1log100.980.38I

    I

    6log2

    1 =

    I

    I

    6

    2

    1 10=

    I

    I

    1

    d

    =

    =

    4.47343

    343418'

    svv

    vff

    = 485 Hz

    1

    1

    Essay 11

    (a) Hookes Law : States that the extension is directly proportional to the stress

    (force) applied in an object,if the elastic limit is not exceeded.

    2

    (b) Elastic Deformation Plastic Deformation

    Wire can return to original shape &size when the stress has been

    removed

    Wire does not return to its originalshape and size when the stress has

    been removed.

    (Permanent deformation occurs)

    3

    (c) (i) Brittle

    1

    (ii) from graph : m10x1.0x -3= for N250F= ( )( )

    ( ) ( )Pa10x1.41

    10x0.110x75.0

    0.1250

    Ax

    FLE

    11

    323===

    3

    (iii) Energy = area under the curve

    J26=

    3

    (iv) at P :( )

    Pa10x1.9810x0.75

    350

    A

    Fstress 8

    23-===

    3

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    15

    Essay 12

    (a)

    When charge, q is moving, there will be a current,Iwill produce. By using Fleming lefthand rule for charge, q moving in a uniform magnetic field, B a force, F will be exerted

    on the charge, q.

    B, I and F must perpendicular to each others. Thus q will move in a circular path.

    An expression for the force,Fexerted on the charged particle is given by,).(sinBqvF=

    where

    F is the force exerted on the charge

    B is the magnetic field

    q for charge

    v for velocity

    angle between v and B

    1

    1

    1

    1

    (b-i)

    Centripetal force = Magnetic force

    m

    Bew

    m

    Berrwv

    m

    Berv

    Bevr

    mv

    =

    ==

    =

    =2

    1

    1

    (b-ii)

    mBe

    Tw == 2

    The period,

    s

    meBe

    m

    BBe

    mT

    9

    112

    1078.1

    1076.1

    1

    100.2

    2

    1222

    =

    =

    =

    ==

    1

    1

    (b-iii)

    From equationBe

    mT

    2= , the period is independent of the velocity and thus independent

    of the kinetic energy of the electron.

    So the period is still same// equal to s91078.1

    1

    1

    (c-i)

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    16

    2

    (c-ii)

    Electrostatic force = magnetic force

    16

    4

    105.7

    008.0

    106

    =

    ==

    =

    ms

    B

    Ev

    BeveE

    1

    1

    1

    Essay 1313(a) - An electromagnetic radiation is given out when an electron makes a transition from

    one state of higher energy level to another of lower energy level.

    - The energy of a photon of the electromagnetic radiation is given by E = hf

    1

    1

    13(b)(i) - The electron in the ground state gains energy that is exactly equal to the energy

    difference between the initial energy level of the electron and the final energy level.

    - Electron move up to the higher energy level than the ground state 1

    1

    13(b)(ii) Energy absorbed

    eV

    EE

    8.12

    )1

    6.13(

    4

    6.1322

    14

    =

    =

    =

    1

    1

    13(b)(iii) Photon energy

    m

    hcE

    8

    83419

    1071.9

    1000.31063.6)106.1(8.12

    =

    =

    =

    1

    1

    1

    13(c)(i) Continuous X-rays:

    - When an electron strikes a metal, it can lose any portion of its energy. This energy

    loss of the incident electron is converted into energy of a X-ray photon. Hence, the

    energies of X-ray photons are different. Since the wavelength of a photon is inversely

    proportional to its energy, the wavelengths of the photons emitted are different.- If all the energy of the incident electron is lost as energy of a photon, X-ray photon

    with the minimum wavelength is produced.

    Line X-rays:

    - The incident electrons may penetrate deep into the inner-most shell of the target

    atoms, causing the electron from the inner K or L shells to be excited to higher energy

    levels.

    - When an electron from a higher energy level falls to fill up these vacancies, the

    1

    1

    1

    FE

    FB

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    17

    difference in energy is emitted as energy of line X-rays

    1

    13c(ii) When all the energy of the incident electron is converted into energy of an X-ray

    photon,

    m

    hceV

    10min

    min

    834319

    min

    1049.2

    )1000.3()1063.6()100.5()106.1(

    =

    =

    =

    1

    1

    Essay 14

    14 a

    (i)

    (ii)

    (iii)

    Nuclides which have the same number of proton but different number of neutrons

    The disintegration of a heavy nucleus to lighter nuclei with the release of a lot of

    energy

    The combination of lighter nuclei at very a high temperature to produce a heavy

    nucleus with release a lot of energy

    1

    1

    1

    14b

    (i)

    (ii)

    Mass number, AAtomic number , Z

    Mass- energy

    HCHeB 1113

    6

    4

    2

    10

    5 ++

    HeLi 427

    3

    1

    1 2H +

    HeLinB 427

    3

    1

    0

    10

    5 ++

    1

    1

    1

    1

    1

    1

    14c

    (i)

    (ii)

    Energy released E

    J

    mcE

    13-

    827-

    2

    107.44103.00101.6627.97693]-[27.98191

    =

    =

    =

    The energy of -ray photon ,

    hcE=

    hcE=

    1

    1

    1

    1

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