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    TOWARDS EXCELLENCE

    IN CHEMISTRY

    BY

    NORIZAN ISMAILSMKMS

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    Pendahuluan

    Tidak semua pelajar yang cemerlang akan memperolehi keputusangred A1 atau A2 dalam subjek kimia. Begitu juga tidak semua pelajaryang tidak cemerlang tidak akan memperolehi gred A1 atau A2. Biasa

    berlaku, pelajar begitu yakin boleh menjawab soalan dengan betul,tetapi apabila keputusan dikeluarkan, jauh dari yang diharapkan.Kenapa begitu ?

    Panduan ini bukan menjamin calon akan memperolehi gred A1 atau A2.

    Calon mestilah mempunyai pengetahuan kimia sedia ada atau asas yanglengkap, matang dan terkini. Dengan pengetahuan tersebut dankemahiran penggunaan teknik-teknik bagaimana hendak menjawab

    soalan, keputusan cemerlang amat mudah dicapai.

    Jawapan yang diterima oleh Lembaga Peperiksaan KementerianPendidikan tidak semestinya yang paling tepat, tetapi kemahiran teknikmenjawab yang calon perolehi sekurang-kurangnya dapat membantumereka menjawab ke tahap terbaik yang diharapkan dalam skema SPM.Oleh itu pendedahan teknik bagaimana hendak menjawab soalan amatpenting sebelum calon mengambil peperiksaan Kimia kertas 4541.

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    Beberapa kesilapan yang sering dibuat oleh calonsemasa menjawab kertas ini.

    1. Menggunakan simbol atau formula bagi nama bahan kimia dalamhuraian.

    2. Dalam huraian eksperimen tidak memberi keadaan bahan tindak balasdengan lengkap seperti kepekatan larutan, pemanasan kuat atauperlahan dan senarai radas tidak lengkap.

    3. Melukis gambar rajah bagi eksperimen dengan seluruh gabusdalam mulut bekas dan hujung salur penghantar lebih tinggi daripermukaan air semasa mengutip gas.

    4. Menggunakan kependekan (abbreviations) untuk istilah-istilah yang

    penting, umpamanya j.a.r. s.e.k dan sebagainya. Amalan ini tidakdigalakkan langsung.

    5. Tidak teliti. Umpamanya bacaan awal termometer dan bacaanakhir tidak dicatatkan.

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    A. Tujuan Kertas Peperiksaan Kimia SPM4541 ialahuntuk menguji:-

    a) pengetahuan prinsip dan konsep kimia

    b) kebolehan memahami fakta-fakta kimia

    c) kebolehan menggunakan pengetahuan danprinsip kimia

    d) kebolehan menggunakan alat serta kemahiran

    membuat pemerhatian

    e) kebolehan menyelesaikan masalah

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    Exam Formatte

    4 papers

    Paper 1

    Paper 2 Paper 3

    Science Practical Work Assesment

    SPWA (PEKA)

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    PAPER 1

    50 objective questions

    knowledge (no 1 20)

    understanding (no 21 35) application (no 36 50)

    25 easy

    15 intermediate 10 advance

    @ ratio 5 : 3 : 2

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    PAPER 2

    SECTION A STRUCTURE 6-8 QUESTONS, ANSWER ALL

    SECTION B LIMITED RESPOND 2 QUESTIONS, CHOOSE ONE

    SECTION C OPENED RESPOND

    2 QUESTIONS, CHOOSE ONE

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    Paper 2

    Item construction No 1 more knowledge (6k, 3u)

    No 2 more understanding (4k, 5u)

    No 3- more aplication (3k, 3u, 3a)

    No 4, 5,6 sintesis and analysis

    Essei Section B knowledge, aplication,

    analysis

    _ Section C Aplication, analysis,

    syntesis

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    ANSWERING STRUCTURE QUESTIONS

    READ THE QUESTION STUDY THE FIGURE/TABLE GIVEN UNDERLINE FACT/ DATA ANSWER

    DONT REWRITE THE QUESTION

    ONLY WRITE WHAT NEEDED

    POINT- REFER TO MARKS GIVEN

    FOLLOW THE TIPS

    DONT EXAGGERATE

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    HOW TO ANSWER ESSAY QUESTIONS

    SPEND NOT MORE THAN ONE AND A HALF HOURFOR THIS SECTION

    READ ALL QUESTIONS CHOOSE 2 QUESTIONS

    - One in each section B and C SCETCH THE POINTS

    - Points refers to marks

    - Read Questions WRITE THE ANSWER

    - Simple sentence- One sentence for each point- Follow the tips

    . FIGURE

    . CALCULATION

    . GRAPH

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    BASIC KNOWLEDGE

    INLEARNING CHEMISTRY

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    KNOWING PARTICLES

    Sulfur Dioxide

    Zinc

    Iodine

    Oxygen

    Water

    Iron(II) chloride

    Chromium

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    Chemical Formulae

    Sodium chloride

    Argentum Nitrate

    Sulfur trioxideAluminium carbonate

    Potassium oxide

    Ammonium sulphateIron(II) oxide

    Lead(IV)sulphate

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    Memorise the Oxidation Number

    H

    Li

    Na

    K Ag

    NH4 ---------------+1

    Al ------ +3

    Others +2

    Cl

    Br

    I

    F NO3 OH ..-1

    SO4 CO3 O -2

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    Types of Equation

    Chemical Equation

    Ionic Equation

    Half Equation

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    MOLE CONCEPT

    Calculate the mass of I molecule ofoxygen.

    1 mol molecule-------------- 32 g

    6 x 1023

    molecule----------- 32 g 1 molecule ---------- (32/ (6 x 10 23 )g

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    Solubility of Salts in Water

    - All nitrates soluble - All K+, Na+, NH4

    +soluble

    - All carbonates insoluble exceptK, Na, NH4

    - All chlorides soluble except

    Pb, Ag, Hg - All sulphates soluble except

    Pb, Ba, Ca

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    Series

    ELECTROCHEMICALTopic : Electrochemistry,

    Oxidation and Reduction

    REACTIVITYTopic : Empirical Formulae

    Involving reaction withoxygen

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    Series

    Electrochemical Series K Na Ca Mg

    Al Zn Fe Sn Pb H

    Cu Hg Ag Au ..For all reactions excluding

    metal oxides

    Reactivity series K Na Ca Mg

    Al C Zn H Fe Sn

    Pb Cu Hg Ag Au

    . For metal oxides only

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    KATA TUGAS IN QUESTIONS

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    NAME

    Write the full name/ notsymbol or formula

    Magnesium (/)Mg (x)

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    state

    State without giving reason

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    What

    State what needed without

    reason

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    State the differences

    List the differences betweenthe two given

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    Explain

    Give the answer completely

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    Give reason

    Write the reasons why

    something happen

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    Compare and contrast

    List all the similarities and thedifferences about two given

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    Deduct

    Give logically deduction

    whether from the questionor knowledge

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    Define

    Give meaning precisely

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    CALCULATE

    Show all step by step

    calculations

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    10 TIPS

    10 things to remember

    when

    answering Paper 2 and 3

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    TIPS 1

    NAME

    - Full name

    - Physical state- Types of particle- Not a symbol

    Example: 1. Name one example of electrolyte 2. Name one oxidation agent

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    TIPS 2

    WRITING FORMULAE alphabet

    not equationExample :1. Write the formula of

    magnesium oxide

    Mg2++ O2- MgO (x)

    MgO (/)

    2 P t b A 9 B 12 W it th

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    2. Proton number A,9 B,12. Write thechemical formula for the compound of A

    and B

    BA2 (/)

    B2+ + 2A- BA2 (x)

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    TIPS 3

    EQUATION Balanced

    Types ArrowFractionMultiplication Physical state

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    TIPS 4

    COLOURExample :

    Water : Colourless,not white

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    TIPS 5

    TERMS

    Correct SpellingEg : Saponification

    Capital LetterEg: Haber Process

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    Anode and cathode

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    DEFINITION OF ANODE

    AND CATHODE

    ANODE Where electrondonated/released

    CATHODE Where electronaccepted

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    Anode Cathode

    Electrolysis positive negative

    Chemicalcell /Voltaic cell

    negativepositive

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    TIPS 6

    FIGURE Stopcock

    Shade Heating

    Delivery tube

    Apparatus

    Clamp Functioned

    Label

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    4 Gambar rajah

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    a) Jika no. atom untuk X = 11 dan Y = 17,lukiskan susunan elektron bagi sebatian XY yangterbentuk.

    Skema Jawapan:

    Bilangan elektron pada semua petala X dan semua

    petala Y betul ...... 1Label Cas X + , Y- 1

    4. Gambar rajah

    0 + 1

    4 Gambar rajah

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    a) Jika no. atom untuk X = 11 dan Y = 17,lukiskan susunan elektron bagi sebatian XYyang terbentuk.Skema Jawapan:

    Bilangan elektron pada semua petala X dan semuapetala Y betul ...... 1

    Cas X+

    , Y-

    ...... 1

    4. Gambar rajah

    1 + 1

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    ENERGY LEVEL DIAGRAM

    Exotermic Reaction

    ENergy HCl + NaOH

    NaCl + H2O

    H = -57kJmol-1

    - X axis, not needed

    - Do not upside down

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    asid sulfurik

    natriumhidroksida

    susunan radas = 0radas salah

    label = 0/1

    asid sulfurik

    natriumhidroksida

    susunan radas = 0 tidak lorek

    label = 0/1

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    asid sulfurik

    natriumhidroksida

    natriumhidroksida

    asid sulfurik

    susunan radas = 0- tidak lorek

    label = 0/1

    susunan radas = 1

    label = 0

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    larutan asid sulfurik

    larutan natrium hidroksida

    susunan radas = 1

    label = 1

    JAWAPAN TERBAIK

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    TIPS 7

    OBSERVATION

    What you see

    Hear

    Smell

    Touch

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    Examples of Observation

    Equation

    Cu2+ +2e Cu

    Cu Cu2+ + 2e

    2H+ + 2e H2

    2I- I2 + 2e

    Fe2+ Fe3+ + e

    Observation

    Shiny Brown solid deposited

    Copper rod thinner

    Effervescent / Bubbles ofgas

    Brown gas released

    Green solution turns brown.

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    TIPS 8

    CHEMICAL TEST

    PROCEDUREOBSERVATION

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    Hydrogen Test

    Collect the gas in a test tube

    Put the burning splinter to the mouth oftest tube.

    Pop sound heard.

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    Oxygen Test

    Collect the gas into a test tube

    Put the glowing splinter into the testtube

    The glowing splinter burning.

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    Carbon dioxide Test

    Flow the gas through the lime water

    Lime water becomes cloudy/ chalky.

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    Fe3+ ion Test

    Put a few drop of Sodium hydroxidesolution into the test tube containingthe ion.

    Brown precipitate is formed.

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    TIPS 9

    CALCULATION

    Show every step

    Unit, if mentioned, must becorrect

    Variables

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    TIPS 10

    GRAPH

    -Size of the graph: 75 % of the

    graph paper-Label the Axis with unit

    -Correct coordinates-Smooth

    5 Lakarkan graf

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    5. Lakarkan graf.

    isipadu / cm 3

    masa / s

    5

    10

    15

    20

    25

    10 20 30 40 50 60 70

    x

    x

    xx

    x x x

    P aksi

    S kala

    T itik

    L icin

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    EXAMPLES OF INCOMPLETESTATEMENT

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    Sodium donates electron

    Each Sodium atom donates oneelectron

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    Electron structure is stable

    Electronarrangementofatom is stable

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    Nuclei attraction to the

    outermost shell

    Nuclei attraction to the electronin the outermost shell

    Enough electron in the

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    Enough electron in theoutermost shell

    Attain/ achieve the stableelectron arrangement

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    Sodium atom has 3 shells

    Sodium atom has 3 shellsoccupied with electrons

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    Element size increase

    Size of atomincrease

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    Ionic compound can conduct

    electricity

    Ionic compound can conductelectricity in aqueous andmolten state

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    Relative atomic mass of an

    element is how many times theatom is heavier compared to

    hydrogen

    Relative atomic mass of an element ishow many times the atom is heaviercompared to a hydrogen

    atom

    .

    Ionic compound forces is

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    Ionic compound forces isstronger

    Attraction forces betweenthe ions (electrostaticforces) is stronger

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    Hydrocarbon is a compound

    which consists of carbonand hydrogen

    Hydrocarbon is a compound which isonly consists of carbonand hydrogen atoms.

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    Fe2+ Fe3+

    Oxidation number of ironchange

    Oxidation number of ironincrease

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    Zinc decreases

    Total surface areaofZinc decreases /

    Massof zinc decreases

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    Hydrochloric acid decreases

    Concentrationofhydrochloric acid decreases

    Attraction forces in the

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    Attraction forces in themolecule weaker

    Attraction forces betweenthemolecules (intermolecular)weaker

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    Boiling point is the state when

    the solid becomes a liquid

    Boiling point is the temperaturewhen the solid becomes a liquid

    Polystyrene case will prevent

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    the leakage/loss of the heat

    energy

    Polystyrene case willreducethe loss of heatenergy

    Hydrochloric acid is

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    Hydrochloric acid isstronger than the ethanoic

    acid

    Hydrochloric acid is a strong

    acid whereas ethanoic acid isa weak acid.

    P l i b hi h

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    Polymer is a substance whichconsist of monomers.

    Polymer is a long chained

    compoundwhich consists ofrepeatable monomers.

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    Weak acid is the acid whichhave a lower concentration ofH+ ion.

    Weak acid is the acid which ispartially ionised in water to

    produce a lower concentrationof H+ ion.

    The colour of acidified

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    potassium

    manganate (VII ) solutionbecomes colourless.

    Thepurplecolour of acidifiedpotassium manganate (VII )

    solution becomes colourless.

    Neutralisation is not a redox reaction

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    Neutralisation is not a redox reactionbecause it is not involves the oxidation

    and the reduction process.

    Netralisation is not a redox reactionbecause it is not involves the

    donation (releasing) and acception(receiving) of electron.

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    Salt is the product whenacid reacts with alkali

    Salt is the compound thatproduced when acid reacts with

    alkali

    Electrolysis is a decomposition

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    y pprocess

    of substances to theirelements.

    Electrolysis is a decompositionprocess of compounds to their

    elements with the presence ofelectricity.

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    Acid is a compound which

    decompose in water toproduce hydrogen ion

    Acid is a compound whichdiscociatesin water to

    produce hydrogen ion

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    Example of analgesic is

    panadol

    Example of analgesic isparacetamol

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    Dry the crystal on the filter

    paper / under the sun

    Dry the crystal by pressingit between two filter papers

    Molecular formulae is a

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    formula which shows the real

    number of atom of eachelement in a compound.

    Molecular formulae is the formulawhich shows the real numberof atom of each element in amolecule.

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    Electron Arrangement of

    Sodium :2:8:1

    Electron arrangement ofsodium atom : 2.8.1

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    In electrolysis,

    Observation: anode corrodes

    In electrolysis,Observation :anode becomesthinner

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    Rate or reaction is faster

    Rate of reaction ishigher

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    More collision occurs.

    More/higher frequencyof collision betweenparticles occur.

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    Factor that effect the rate of

    reaction;Size ofParticles (x)

    Size of substance/total

    surface area of substance (/)

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    Unsaturated Hydrocarbon is a

    hydrocarbon which havedouble bond carbon.

    Unsaturated Hydrocarbon is ahydrocarbon which have one or

    more double bond betweencarbon-carbon atoms.

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    The function of salt bridge isto complete the circuit.

    The function of salt bridge

    is to allow the flow of ionsto complete the circuit.

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    Catalyst is a substance

    which fastened the reaction.

    Catalyst is a substance thatincrease / reduce the rate

    of reaction.

    H lf ti t th d

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    Half equation at the anode

    Cu - 2e Cu2+

    Half equation at the anodeCu Cu2+ + 2e

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    Heat of combustion is :

    Heat released when 1 mol offuel/substance burnt in excess

    oxygen under a standard

    condition.

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    Observation when Magnesium

    mixed with hydrogen chloride inmethyl benzene

    No reaction (X)

    No changes (/)

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    Initial reading of burette :

    25 cm3 (x)

    25.00 cm3 (/)

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    Electron flows from zinc rode tocopper in the solution. (x)

    Electron flows from zinc tocopper through the outer circuit

    (/)

    To state the relationship between

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    . and(paper 3)

    Rate of reaction is directlyproportioned to the temperature (2marks)

    Rate of reaction is affected by thetemperature (1 mark)

    Rate of reaction higher when thetemperature increase (3 marks)

    HURAIAN EKSPERIMEN

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    HURAIAN EKSPERIMEN

    RADAS / apparatus

    BAHAN KIMIA / chemicals KAEDAH / procedure

    - CARA SPESIFIK / specific method- KUANTITI SESUAI / suitable quantity- NAMA BAHAN / name of substance

    - KEPEKATAN SESUAI /suitable concentration- RADAS / suitable apparatus- GAMBAR RAJAH berfungsi/ lablelled figure

    PEMERHATIAN/KEPUTUSAN/ observation

    PERBINCANGAN/ Explanation- PENGIRAAN/ calculation- GRAF/ graph (PSTL)- PERSAMAAN /equation

    KESIMPULAN/ conclusion

    Contoh jawapan esei

    1. Terangkan satu eksperimen untuk menukarkan ion Fe2+

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    kepada ion ion Fe3+ di makmal. Dalam jawapan anda sertakanjuga pemerhatian , ujian pengesahan dan persamaan ion yangterlibat. [10]

    - masukkan 5 cm3 1 moldm-3 ferum(II) sulfat kedalamtabung didih- Tambahkan 5 cm3 air bromin- Panaskan campuran dengan perlahan-lahan

    - Larutan hijau bertukar menjadi perang- Ion Fe2+ dioksidakan kepada ion Fe3+- Tambahkan larutan natrium hidroksida- Mendakan perang terbentuk- Persamaan ion bagi tindak balas pengosidaan

    Fe2+

    -->Fe3+

    + e- Persamaan ion bagi tindak balas penurunan

    Br2 + 2e --> 2Br-

    - Persamaan ion keseluruhan2Fe2+ + Br2 --> 2Fe

    3+ + 2Br -

    No. proton D, 6 dan no. proton E, 8. Terangkan dari segi

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    susunan elektron bagaimana ikatan antara A dan E berlaku

    Susunan elektron atom D 2.4 Susunan elektron atom E 2.6

    Susunanelektron ini tidak stabil, untuk mencapaisusunan elektron stabil

    Setiap atom D menyumbang 4 elektron untuk dikongsi

    Setiap atom E menyumbang 2 elektron untuk dikongsi

    2 atom E dan satu atom D berkongsi 4 pasang elektron

    membentuk sebatian kovalen dengan formula DE2 Ikatan ini dinamakan ikatan kovalen gandadua

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    No. proton A, 11 dan no. proton B, 8. Terangkan dari segisusunan elektron bagaimana ikatan antara A dan B

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    susunan elektron bagaimana ikatan antara A dan Bberlaku.

    Susunan elektron atom A 2.8.1 Susunan elektron atom B 2.6

    Susunan elektron ini tidak stabil ,untuk mencapaisusunan elektron stabil

    setiap atom A menderma satu elektron kepada atom Bmembentuk ion A+

    Setiap atom B menerima dua elektron membentuk

    ion B-2

    Dua ion A+ dan satu ion B-2 ditarik oleh dayaelektrostatik membentuk sebatian ionik dengan denganformula A2B

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    THANK YOU

  • 8/2/2019 Towards Excellence in Chemistry08 Latest

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    THANK YOU

    EXPECTING TO SEEYOUR BIG SMILE ON

    MAC 2009