Trial Penang SPM 2013 PHYSICS K1 K2 K3 SKEMA [SCAN]

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    MAJLIS PENGETUA SEKOLAH MALAYSIACAWANGAN PULAU PINANG

    MODUL LATIHAN BERFOKUS SPITII. 20134531/,1JAWAPAN KERTAS 1

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    I B 11 C 2t D 31 A 41 B2 C t2 C 22 D 32 D 42 B,rlJ A 13 C 23 B 33 D 43 B4 D 1,4 A 24 C 34 B 44 A5 B 15 B 25 C 35 A 45 C6 B t6 C 26 D 36 A 46 D7 C t7 A 27 A 37 C 47 B8 C l8 D 28 C 38 B 48 D9 C t9 A 29 B 39 B 49 C10 D 20 B 30 D 40 B 50 B

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    453112PHYSICSKERTAS 2MASA 2112 JAM

    MAJLIS PENGETUA SEKOLAH MENENGAH(CAWANGAN PULAU PINANG)MODUL LATIHAN BERFOKUS SPM 2013

    FIZIRKertas 2

    PERATURAN PEMARKA}IANUNTUK KEGUNAAN PEMERIKSA SAHAJA

    Nota :Skema pemarkahan ini dalam Bahasa lnggeris sahaja

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    NO. MARKING SCHEME MARKSUB TOTAL1(a) 0.10c 1

    4(b) o 1(c)(d)

    29.70C 1Scalar quantity 1

    ,SECTION A

    4s31(PP)

    2(al Product of mass and velocity 1

    5

    (b) mv = 10v=10/0.05

    = 200 ms-1 t11

    (c)(d)

    lmpulsive force // Resultant force 1(Show a line which is less steep)

    1

    3(a) sinc=11 2.42c = sin-1 2.42= 24.4'11

    6

    (b) . (Show 2 total intemal reflections in the diamond)IIt

    \

    400/

    o20I,lJ LI no" eoo

    2

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    NO" MARKING SCHEME MARKSUB TOTAL4(al 3Y x2=6V 11

    7

    (b) Period=Smsx4=20msFrequency = 1120 ms

    =50H211

    (c)(dxi)

    Rectiflcation ll half wave retification 1capasitor 1(dxii)

    t1

    4531(PP)

    5(a) Pressure is the (normal) force acting per unit area. 1

    8

    (bxi) The paper strip in Diagram 5.2 is higherthan that in Diagram 5.1ll 5.1 < 5.2 1

    (bxii)(bxiii)

    The speed of the air in Diagram 5.2Diagram 5.1 ll 5.1 < 5.2

    is higher than that in 1

    The air pressure above the paper is lower than that below theDaoer // vice-versa 1(b)(iv) When the speed of air increases, the air pressure decreases //vice-versa

    1

    (c) t, 1(d) Bernoulli's Principle 1(e) Bunsen bumer ll earburelor llvacuum pump(or any relevant application) 16(aXi) Potential difference across the cell 1

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    tNO. MARKING SCHEME MARKSUB TOTAL

    7(aXi) lncreases // becomes higher 1

    10

    (aXii) Pressure 1(b)(c)

    Pressure Law 1Tz = PtJ_= 230 x 300 = 345 K ll 72 "CPr 200Mk 1- Conversion of unit from "C to KelvinMk 2- SubstitutionMk 3- Answer with correct unit

    111

    (dxi) Widersurface area ll btgger surface area t 1(dxii) The pressure exerted on the road is reduced 1(dxiii) Thick tyre thread 1(dXiv) To have a better grip on the road ,l

    4s31(PP)

    NO. ANSWER MARKSUB TOTAL8(a) lsotopes that are not stable /l emit radioactive emissions 1

    12

    (b) DThe reading of the ratemeter is the highest 11(cXi) 1',f n, '??an + lH" 2

    (c)(ii) 100o/o + 50o/o + 25o/o -+ 12.5o/oSodium-24 : 3T1p = 45 hoursTrn = 15 hours,l

    1

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    1 5SECTION B

    4s31(PP)

    QUESTION MARKING SCHEME SUBMARK TOTALI (a) The quantity of heat needed to increase the temperature of 1kg ofsubstance by 1oC. 1

    1

    (b) i) The reading of thermometer in Diagram 9.1 is greater than inDiagram 9.2 ll 9.2 < 9.1 1

    5ii) The specific heat capacity of the metal block in Diagram 9.2 is

    greater than in Diagram 9.1 ll 9.1 < 9.2 1iii) The amount of heat supplied is the same

    1

    iv) The lower the specific heat capacity, the higher the reading of thethermometer ll vice-versa 1

    v) Different metals / materials have different specific heat capacities.1

    (c) The body temperature is higher than the temperature of the coolingpad 1

    4here is a net heat flow from the body to the cooling gel untilthermal equilibrium achieved. 1The body heat energy is decreased

    1

    ln thermal equilibrium, there is no net heat flow from the body to thecooling gel llthe temperatures are the same. 1

    (d)MODIFICATION EXPLANATION

    H:lA rarse number oron{ , lncrease the surface area I .treleases heat faster { I 2Big fan ,/ of air can be,/, 2

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    MARKING SCHEME10 (a) The maximum displacement from the equilibrium position.

    10 max

    Size of the tuning fork in Diagram 9.1 is greater / thicker than inDiagram 9.2 ll 9.2 < 9.1Amplitude of sound waves in Diagram 9.1 is greater than inDiagram 9.2 ll 9.2 < 9.1Frequency of sound waves are the same.Amplitude is directly proportional to the loudness // When theamplitude increases, the loudness of the sound increases.Amplitude is directly proportional to the size of the tuningfork llWhen the size of the tuning fork increases, the amplitudeincreases.

    aeroplane is equipped with a device / microphone thatcan detect soundthe sound is sent to the computercomputer generates waves thatproduce destructive interference

    1)2)3)4)

    1+1

    1+1

    1+1

    1+1

    2) sound waves will be heardclearly1) speakers must be placedfacing the audience4) allow interference tooccur ll able to produceloud sounds

    3) use a minimum of 2 loudspeakers6) interference occurs) sound output is loud8) able to absorb the sound/ the sound waves7) the floor is carpeted

    10) reduce reflection of sound9) use wooden floor

    4531(PP)

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    MARKING SCHEME11(a) Rate of change in momentum // lmpulsive force o I/(time ofimpact),Fs1ll

    (i) Helmet - to protect the head by increasing the time oi irnpact(ii) Jacket - to protect the body from injuries, cuts, burn due to fall(iii)Gloves - to protect the hand from injuries/force(iv) Helmet, jacket and gloves increase the time of impact andreduces impulsive force1 80 x1 000E0L6o-

    50.0 ms-1v-u=- t50-0=10

    = 5.0 ms-2F=ma= (200x5.0)= 1000 N

    Higher spring constant ll lower naturalewer / Lower no. ofWide / Bigger width oftyres Bigger surface area, bettersupport ll low pressureacts on the tyres / more frictionSmaller mass

    7SECTION C

    4531(PP)

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    MARKING SCHEME12 (a) The ratio of potential difference to current.

    Length // thickness/cross sectional area ll lype of materialb) (i)Wire P. Since I is constanl lsarne for wire P and wire Qo V = lR ll V is directly proportional to R //the higher the V, the higher the R

    M9 - Metal R is chosenMl0 - because it has low melting point, low specific heatcapacity, smal! wire diameter and high resistivity.

    1+1

    1+1

    1+1

    1+1

    Can rnelt easily.Needs a small amount of heat toincrease its temperature fi can beheated up easily

    Low specific heatcapacity

    lncrease the resistanceProduces a wire of high resistance//wire can convert electrical energy toheat easily.

    High resistivity

    Correction substitutionR = V2lP= Q4O)260Correct answer with unit= 960C)

    f=PA/ =601240R=Vll=240x240 160= 960Ct

    ChooseV= 120VP = V2lR l=V/R= 12A196O

    4531(PP)

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    MAJLIS PENGETUA SEKOLAH MATAYSIACAWANGAN PULAU PINANG

    MODUL LATIHAN BERFOI(US $PM 2,O13FIZIKKertas 3 4531t3

    PERATURAN PEMARKAHANKertas 3

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    t sEcroN A SKEMA FIZIK KERTAS 3Question Marking Scheme 5ubMark TotalMark

    1(aXi) State the manipulated variableMass of trolley // m 1 7

    (ii) State the responding variableAcceleration of lrolley ll a ! 7(i,,) State the fixed variable

    Weight of load ll Force ll F 7 L(b) (i) Calculate all values of tm

    f t*e'l1.000.500.330.250.20

    3 - 5 betul { tm (ignore consistency)

    1 L

    (ii) Measure all values of yYt Cfil

    13.2 (13.1 - 13.3)7.8 (7.7 -7.e)6.0 (5.e - 6.1)4.5 (4.4 - 4.6)3.6 (3.5 - 3.7)

    2

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    (iii) Calculate all values of aa, cm s-22.401.200.800.600.48

    Note: Calculate a for y in the range5 betul lZm3 - 4 betul {t m (ignore consistency)

    2t

    2

    (c) (iii) Tabulate the data

    /- Allphysical quantities or symbols, m ,L,x, y, and a aretabulated/- ettcorrect units given for m ,!-,x,y, and a

    m(w) * c,g''l x, cm -l'r Cm a, cm s''1.0 I.00 3.6 13.2 r 2.402.0 0.s0 3.0 7.8 1.203.0 0.33 2.8 6.0 0.804.0 0.25 2.1 4.5 0.605.0 0.20 1.7 3.6 0.48

    1

    1 2

    (d) Draw a Graphr' - State the correct physical quantities on each axisMenyatakan kuantitifizik yang betul pada setiap paksi/- State the correct unitMenyatakan unit yang betul/ - Using an even scaleMenggunakan skala genap:

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    tScore ( /') Mark

    75-63-4210

    543210

    (e) State the correct relationshipa is directly proportional ,o * // directly proportianala berkadar terus dengan *, ttberkadar terusI syarat - graf mesti lalu (0,0]- lain jawapan reject JI Note : Graf lurus tak lalu (0,0) tapi pelajar jawab,

    V increasing linearly to 0 - Reject I '

    1 1

    TOTAL 16

    2.(aXi) Decrease 1 1( ii) Show extrapolation line on graph

    1.00 vL7

    2(iii) Electromotive force (e.m.f) 1 1

    (b)(i)Show a big triangle on graphSubstitution :

    0.50-1.00IIL - 0.73-0.00m = -0.585 O@ -0.685 VA-l(Answer with correct unit )

    1

    7

    1

    3

    (ii) r = 0.585 O @ 0.685 \fl (Answer with correct unit) 1 1(c Xi)

    Substitution :1.00 = V+(0.90X0.58s) 1 2

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    3(a) State the correct lnference:The pressure in liquid depends on the density of liquid . 1 L3(b) State the correct Hypothesis:

    when the density of liquid increases , the pressure also increases ! 13(cXi) State the aim of the experirnent :

    To investigate the relationship between the density of the liquidand the pressure. 1 L(ii) State the variables in the experiment:

    Manipulated variable: density / mass of saltResponding variable: pressureFixed variable : depth

    1

    1

    2

    (iii) List the apparatus and material *Meter rule, manometer, measuring cylinder, water, sal! triplebeam balance, thistle funnel, mercury 1 7(iv) Arrangement of apparatus

    Meter rulePembaris meter Rubber tubeTiub getah Measuring cylinde

    Selinder penyukatManometer

    TvIThistlefunnel

    tisel

    1 1

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    manometer and record the data.Repeat the experimentRepeat the experiment with different mass of salt m = 20g, 30g,40g and 50g. tTabulating data

    mass,m /gor density/gcm-'

    Difference length ofmercury column ,y / cm

    1020304050

    Accept: without unit

    1 1

    Analysing dataY /cm// Pressure, Pa

    m/e l/ density, g cm-3Accept: without unit or reverse axis

    1 1

    TOTAL 124. lnference:

    The output voltage of the transformer depends on the number ofturns of the secondary coil.1 L

    Hypothesis:The output voltage of the transformer increases as the number ofturns of the secondary coil increases 7 t

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    tvoltmeter and connection wire"Arrangement of the apparatus:

    Low uolta r0n-c0repower,supply Clip

    Primary coilSecondary coil Vollmeter

    1 1

    Procedure:The number of turns of the primary coil No = 150'turns.The number of turns of the secondary coil N, = 20 turnsThe low voltage of a.c power supply is switched on.The reading of the voltmeter is measured , VThe experiment is repeated with N, = dg, 50, 80 and 100 turns(accept : step-down transformer)

    L

    !1

    3

    TabulatinB data

    1 1

    Number of turn of secondarycoil, N Outputvoltage, V lV

    20405080100

    Analysing data

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    PERSIDANGAN KEBANGSAAN PENGETUA.PENGETUA SEKOTAH MENENGAH MALAYSIACAWANGAN PUTAU PINANG

    PEPERIKSAAN PERCUBAAN SPM 2013JADUAL SpEStFtKASt UJTAN pHyStCS 453U1

    API.I'KASI CATATANKUALITATIF KUANTITATIF

    R 5 T R s T R S s Tl.INTRODUCflON OF

    PHYSICS1 1 1 3

    2. FORCE AND MOTION 1 1 2 1 1 1 73. FORCES ANDPRESSURE 1 1 1 1 1 1 1 1 I4. HEAT L 2 1 1 55. LIGHT 1, 1 1 1 1 56. WAVES L 1 2 1 1 1 77. ELECTRICITY 1 t 1 1 48. ELECTROMAGNTNSM 1 1 1 1 49. ELESTRONICS 1 1 7 1 410. RADIOACNVITY t 1 1 3

    IUMIAH 10 3 1 L2 4 4 5 3 4 4 50

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    JADUAL SPESTF|KASI UJTAN pHyStCS 4s31/2BAHAG|ATy A

    BAUAqnN B

    't .,,r,. : ,3 '.4', ' .-,i, '.r.;6 i,ASPEK P K A P K A P K A P K A P K S P K S P K A M P A R

    2 2 1 1 3 1 1 4 1 2 4 1 2 5 1 2 5 1 1 2 6 L 4 7JUM IAHMARKAH

    4 5 6 7 8 8 10 t2 50R s T R s T R s T R s T R s T R s T R s T R s T4 3 2 3 2 1 4 2 1 4 3 1 4 2 2 2 5 3 4 3 5 50

    JUMTAHMARKAH

    t 4 5 10R S T R s T R s T R s T

    SOAIAN 1 1 2 2 2 2 1 2 4 4SOAIAN 2 1 2 2 2 2 1 2 4 4

    a.._

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    BAHAGIAN C

    JUM IAHMARKAH

    1 4 5 10R s T R s T R s T R s T

    SOALAN 3 1 2 2 2 2 L 2 4 4SOATAN 4 1 z 2 2 2 1 2 4 4

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