Nama :..................................................................N P M :..................................................................Kelas :..................................................................

Created by Abdul Muiz., S.Pd.,

Matematika Dikrit STKIP PGRI Bangkalan

KUMPULAN SOAL FORMULA DISKRIT BAGIAN KETIGAOleh : ABDUL MUIZ., S.Pd., M.Pd.,

SOAL 01.

a. f ( x )= (1 + x )5

b. f ( x )= (1 − x )5

c. f ( x )= (−1 + x )5

d. f ( x )= (−1 − x )5

SOAL 02.

a. f ( x )= (1 + 2 x )5

b. f ( x )= (1 − 2 x )5

c. f ( x ) = (−1 + 2 x )5

d. f ( x )= (−1 − 2x )5

SOAL 03.

a. f ( x )= (2 + x )5

b. f ( x )= (2 − x )5

c. f ( x )= (−2 + x )5

d. f ( x )= (−2 − x )5

SOAL 04.

a. f ( x )= (2 + 3 x )5

b. f ( x )= (2 − 3 x )5

c. f ( x )= (−2 + 3 x )5

d. f ( x )= (−2 − 3x )5

SOAL 05.

a.f ( x )= (1 + 1

2x )5

b.f ( x )= (1 − 1

2x)5

c.f ( x )= (−1 + 1

2x)5

d.f ( x )= (−1 − 1

2x)5

Page | 2

Dosen Pembina – Abdul Muiz., S.Pd., M.Pd.,

SOAL 06.

a.f ( x ) = ( 12 + x)

5

b.f ( x )= ( 12 − x )

5

c.f ( x )= (− 12 + x)

5

d.f ( x )= (−12 − x )

5

SOAL 07.

a.f ( x ) = (3 + 1

2x)5

b.f ( x )= (3 − 1

2x)5

c.f ( x )= (−3 + 1

2x)5

d.f ( x )= (−3 − 1

2x )5

SOAL 08.

a.f ( x ) = ( 12 + 3 x)

5

b.f ( x )= ( 12 − 3 x)

5

c.f ( x )= (− 12 + 3 x)

5

d.f ( x )= (−12 − 3 x )

5

SOAL 09.

a.f ( x )= (3 + 1

2x)15

b.f ( x )= (3 − 1

2x)15

c.f ( x )= (−3 + 1

2x)15

d.f ( x )= (−3 − 1

2x )15

SOAL 10.

a.f ( x )= ( 12 + 3 x)

15

c.f ( x )= (−12 + 3 x)

15

3 | Page

Matematika Dikrit STKIP PGRI Bangkalan

b.f ( x )= (12 − 3 x)

15

d.f ( x )= (−12 − 3 x )

15

Page | 4

Dosen Pembina – Abdul Muiz., S.Pd., M.Pd.,

KUNCI JAWABAN SOAL FORMULA DISKRIT BAGIAN KETIGAOleh : ABDUL MUIZ., S.Pd., M.Pd.,

SOAL 01.

a. f ( x )= (1 + x )5

Jawaban:

f ( x )= (1 + x )5 P ( x ) = ∑k = 0

∞

(5k ) (x )k

= 1 + 5 x + 10 x2 + 10 x3 + ⋯

f ( x )= (1 + x )5 P ( x ) = 1 + 5 x + 10 x2 + 10 x3 + ⋯

b. f ( x )= (1 − x )5

Jawaban:

f ( x )= (1 − x )5 P ( x ) = ∑k = 0

∞

(5k ) (−x )k

= 1 − 5 x + 10 x2 − 10 x3 ± ⋯

f ( x )= (1 − x )5 P ( x ) = 1 − 5 x + 10 x2 − 10 x3 ± ⋯

c. f ( x )= (−1 + x )5

Jawaban:

f ( x )= (−1 + x )5 f ( x ) = (−1 )5 (1 − x )5

P ( x ) = (−1 )5 [ ∑k = 0

∞

(5k ) (−x )k ]= (−1 ) (1 − 5 x + 10 x2 − 10 x3± ⋯)

5 | Page

Matematika Dikrit STKIP PGRI Bangkalan

f ( x )= (−1 + x )5 P ( x ) = −1 + 5 x − 10 x2 + 10 x3 ∓ ⋯

d. f ( x )= (−1 − x )5

Jawaban:

f ( x )= (−1 − x )5 f ( x ) = (−1 )5 (1 + x )5

P ( x ) = (−1 )5 [ ∑k = 0

∞

(5k ) ( x )k ]= (−1 ) (1 + 5 x + 10 x2 + 10 x3 + ⋯)

f ( x )= (−1 − x )5 P ( x ) = −1 − 5 x − 10x2 − 10 x3 − ⋯

Page | 6

Dosen Pembina – Abdul Muiz., S.Pd., M.Pd.,

KUNCI JAWABAN SOAL FORMULA DISKRIT BAGIAN KETIGAOleh : ABDUL MUIZ., S.Pd., M.Pd.,

SOAL 02.

a. f ( x )= (1 + 2 x )5

Jawaban:

f ( x )= (1 + 2 x )5 P ( x ) = ∑k = 0

∞

(5k ) (2x )k

= 1 + 5 (2x ) + 10 (4 x2 ) + 10 (8 x3) + ⋯

f ( x ) = (1 + 2 x )5 P ( x ) = 1 + 10 x + 40 x2 + 80x3 + ⋯

b. f ( x )= (1 − 2 x )5

Jawaban:

f ( x )= (1 − 2 x )5 P ( x ) = ∑k = 0

∞

(5k ) (−2 x )k

= 1 − 5 (2 x ) + 10 (4 x2) − 10 (8 x3 ) ± ⋯

f ( x )= (1 − 2 x )5 P ( x ) = 1 − 10 x + 40 x2 − 80 x3 ± ⋯

c. f ( x )= (−1 + 2 x )5

Jawaban:

f ( x )= (−1 + 2 x )5 f ( x ) = (−1 )5 (1 − 2 x )5

P ( x ) = (−1 )5 [ ∑k = 0

∞

(5k ) (−2 x )k ]= (−1 ) (1 − 5 (2x ) + 10 (4 x2 ) − 10 (8 x3) ± ⋯)

7 | Page

Matematika Dikrit STKIP PGRI Bangkalan

f ( x ) = (−1 + 2 x )5 P ( x ) = −1 + 10 x − 40x2 + 80 x3 ∓ ⋯

d. f ( x )= (−1 − 2x )5

Jawaban:

f ( x )= (−1 − x )5 f ( x ) = (−1 )5 (1 + 2x )5

P ( x ) = (−1 )5 [ ∑k = 0

∞

(5k ) (2 x )k]= (−1 ) (1 + 5 (2 x ) + 10 (4 x2) + 10 (8 x3 ) + ⋯)

f ( x )= (−1 − x )5 P ( x ) = −1 − 10 x − 40 x2 − 80 x3 − ⋯

Page | 8