Post on 26-Jan-2021
PEPERIKSAAN PERCUBAAN BERSAMA SPM NEGERI PERLIS 2012 ADDITIONAL MATHEMATICS PAPER 1
No. Answer Sub-mark Total marks
1. (a) 1 and 7 (b) {e, g, h}
1 1
2
2. (a) 1 B1 : 2π₯ + 3 = 5 or π!! π₯ = !!!
!
(b) 4π₯! + 2π₯ B1 : (2π₯ + 3)! β 5 2π₯ + 3 + 6
2 2
4
3.
473 βx
B2: ( ) 5324 β=+ xxg B1: ( )
25312 β=+ xxg
3 3
4. 5143 2 β+ xx B1 : 3π₯ β 1 π₯ + 5 = 0
2 2
5. 2or1 =β= hh B2 : β + 1 β β 2 = 0 B1 : 6β ! β 4 β + 2 9 = 0
3 3
6. (a) p = 3 (b) q = 47 (c) x = 5
1 1 1
3
7.
322 β€β€β x
B2: 3π₯ β 2 π₯ + 2 β€ 0 B1 : 3π₯2 + 4π₯ β 4 β€ 0
3
3
8. n = β2 B1: 32(2n + 1) = 33n or 4n + 2 = 3n or equivalent
2 2
9. x = 10 or x = β2 B3: x2 β 8x β 20 = 0
B2: 452
2
=+xx
B1: log252
2
+xx
= 2
3 3
10. y =
81
2x
B2: log3y β 2 log3x = β4 or equivalent
B1: xy
33
3 log29log
log=+
3 3
11. (a) 4 (b) 559 B2: π 18 - π 5 = 594 β 35 B1: π 18 =
182
[2(-1) + (17)(4)] or π 5 = 52 [2(-1) + (4)(4)]
1 3
4
12. n = 8 B2 :![ !!)
!!!!!! !
= β3280 B1: r = β3
3 3
13.
427,
43
=β= ba
B3 : either one correct B2 : baxxy += 2
B1 : gradient = 1563
β
β
4 4
14. ji 213 β B1 : jiji 5776 ++β
2 2
15.
(a) 3=p B1 : )2(64 jpiji +=+ Ξ»
(b) 13 B1 : ji 32 +
2 2
4
16. oooo 225,'26198,45,'2618 B3 : oo 45,'2618
B2 : 0)1)(tan1tan3( =ββ xx or 1tanor31tan == xx
B1 : xxx 22 tan1tan2tan4( +=β
4 4
17.
nm
38
=
B1 : 123
4β=β
β
βββ
βββ
βββ
β β nm
2 2
18. (a) 6.5 B1 : 1.084 radians (b) 22.9
B1 : )084.1)(5.6(21
2 2
4
19. β44 B3 : )92()32(4 22 +β xxx B2 : [ ] 4233 )32(12)2()32(44 βββ xxxx B1 : )2()32(4 3βx or 212x
4 4
20. 1cms1 βΟ
B2 : Use of chain rule :dtdrr Γ= Ο28 or equivalent
B1 : rdrdA
Ο2= or r = 4cm
3 3
21. 6
B3 : 523)1(
3)3( 33
=βpp
B2 : 603
83
1
3
=β₯β¦
β€β’β£
β‘+px
B1 : 3
3pxis seen
4 4
22. (a) 93 (b) 1296
1 1
2
23. (a) 720 B1 : 6! (b) 240 B1 : 5!Γ2!
2 2
4
24. (a)
151
(b) 6029
B1 : )43
51
31()
43
54
32()
41
51
32( ΓΓ+ΓΓ+ΓΓ
1 2
3
25. (a) 0.6915
B1 : )35.1817( β>zP
(b) 34 B1 : 50 Γ 0.6915
2 2
4