ADDITIONAL MATHEMATICS PAPER 1 - My Class 2015...PEPERIKSAAN PERCUBAAN BERSAMA SPM NEGERI PERLIS...

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PEPERIKSAAN PERCUBAAN BERSAMA SPM NEGERI PERLIS 2012 ADDITIONAL MATHEMATICS PAPER 1 No. Answer Sub-mark Total marks 1. (a) 1 and 7 (b) {e, g, h} 1 1 2 2. (a) 1 B1 : 2 + 3 = 5 or !! = !!! ! (b) 4 ! + 2 B1 : (2 + 3) ! βˆ’ 5 2 + 3 + 6 2 2 4 3. 4 7 3 βˆ’ x B2: () 5 3 2 4 βˆ’ = + x x g B1: () 2 5 3 1 2 βˆ’ = + x x g 3 3 4. 5 14 3 2 βˆ’ + x x B1 : 3 βˆ’ 1 + 5 = 0 2 2 5. 2 or 1 = βˆ’ = h h B2 : β„Ž + 1 β„Ž βˆ’ 2 = 0 B1 : 6β„Ž ! βˆ’ 4 β„Ž + 2 9 = 0 3 3 6. (a) p = 3 (b) q = 47 (c) x = 5 1 1 1 3 7. 3 2 2 ≀ ≀ βˆ’ x B2: 3 βˆ’ 2 + 2 ≀ 0 B1 : 3 2 + 4 βˆ’ 4 ≀ 0 3 3 8. n = –2 B1: 3 2(2n + 1) = 3 3n or 4n + 2 = 3n or equivalent 2 2 9. x = 10 or x = –2 B3: x 2 – 8x – 20 = 0 B2: 4 5 2 2 = + x x B1: log 2 5 2 2 + x x = 2 3 3 10. y = 81 2 x B2: log 3 y – 2 log 3 x = –4 or equivalent B1: x y 3 3 3 log 2 9 log log = + 3 3

Transcript of ADDITIONAL MATHEMATICS PAPER 1 - My Class 2015...PEPERIKSAAN PERCUBAAN BERSAMA SPM NEGERI PERLIS...

  • PEPERIKSAAN PERCUBAAN BERSAMA SPM NEGERI PERLIS 2012 ADDITIONAL MATHEMATICS PAPER 1

    No. Answer Sub-mark Total marks

    1. (a) 1 and 7 (b) {e, g, h}

    1 1

    2

    2. (a) 1 B1 : 2π‘₯ + 3 = 5 or 𝑓!! π‘₯ = !!!

    !

    (b) 4π‘₯! + 2π‘₯ B1 : (2π‘₯ + 3)! βˆ’ 5 2π‘₯ + 3 + 6

    2 2

    4

    3.

    473 βˆ’x

    B2: ( ) 5324 βˆ’=+ xxg B1: ( )

    25312 βˆ’=+ xxg

    3 3

    4. 5143 2 βˆ’+ xx B1 : 3π‘₯ βˆ’ 1 π‘₯ + 5 = 0

    2 2

    5. 2or1 =βˆ’= hh B2 : β„Ž + 1 β„Ž βˆ’ 2 = 0 B1 : 6β„Ž ! βˆ’ 4 β„Ž + 2 9 = 0

    3 3

    6. (a) p = 3 (b) q = 47 (c) x = 5

    1 1 1

    3

    7.

    322 β‰€β‰€βˆ’ x

    B2: 3π‘₯ βˆ’ 2 π‘₯ + 2 ≀ 0 B1 : 3π‘₯2 + 4π‘₯ βˆ’ 4 ≀ 0

    3

    3

    8. n = –2 B1: 32(2n + 1) = 33n or 4n + 2 = 3n or equivalent

    2 2

    9. x = 10 or x = –2 B3: x2 – 8x – 20 = 0

    B2: 452

    2

    =+xx

    B1: log252

    2

    +xx

    = 2

    3 3

    10. y =

    81

    2x

    B2: log3y – 2 log3x = –4 or equivalent

    B1: xy

    33

    3 log29log

    log=+

    3 3

  • 11. (a) 4 (b) 559 B2: 𝑠18 - 𝑠5 = 594 βˆ’ 35 B1: 𝑠18 =

    182

    [2(-1) + (17)(4)] or 𝑠5 = 52 [2(-1) + (4)(4)]

    1 3

    4

    12. n = 8 B2 :![ !!)

    !!!!!!  !

    = βˆ’3280 B1: r = βˆ’3

    3 3

    13.

    427,

    43

    =βˆ’= ba

    B3 : either one correct B2 : baxxy += 2

    B1 : gradient = 1563

    βˆ’

    βˆ’

    4 4

    14. ji 213 βˆ’ B1 : jiji 5776 ++βˆ’

    2 2

    15.

    (a) 3=p B1 : )2(64 jpiji +=+ Ξ»

    (b) 13 B1 : ji 32 +

    2 2

    4

    16. oooo 225,'26198,45,'2618 B3 : oo 45,'2618

    B2 : 0)1)(tan1tan3( =βˆ’βˆ’ xx or 1tanor31tan == xx

    B1 : xxx 22 tan1tan2tan4( +=βˆ’

    4 4

    17.

    nm

    38

    =

    B1 : 123

    4βˆ’=⎟

    ⎠

    ⎞⎜⎝

    βŽ›βŽŸβŽ 

    ⎞⎜⎝

    βŽ› βˆ’ nm

    2 2

    18. (a) 6.5 B1 : 1.084 radians (b) 22.9

    B1  :   )084.1)(5.6(21

           

    2 2

    4

  • 19. βˆ’44 B3 : )92()32(4 22 +βˆ’ xxx B2 : [ ] 4233 )32(12)2()32(44 βˆ’βˆ’βˆ’ xxxx B1 : )2()32(4 3βˆ’x or 212x

    4 4

    20. 1cms1 βˆ’Ο€

    B2 : Use of chain rule :dtdrr Γ—= Ο€28 or equivalent

    B1 : rdrdA

    Ο€2= or r = 4cm

    3 3

    21. 6

    B3 : 523)1(

    3)3( 33

    =βˆ’pp

    B2 : 603

    83

    1

    3

    =βŽ₯⎦

    ⎀⎒⎣

    ⎑+px

    B1 : 3

    3pxis seen

    4 4

    22. (a) 93 (b) 1296

    1 1

    2

    23. (a) 720 B1 : 6! (b) 240 B1 : 5!Γ—2!

    2 2

    4

    24. (a)

    151

    (b) 6029

    B1 : )43

    51

    31()

    43

    54

    32()

    41

    51

    32( Γ—Γ—+Γ—Γ—+Γ—Γ—

    1 2

    3

    25. (a) 0.6915

    B1 : )35.1817( βˆ’>zP

    (b) 34 B1 : 50 Γ— 0.6915

    2 2

    4