2015_Kedah_Biologi.pdf

7/24/2019 2015_Kedah_Biologi.pdf

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SKEMA KERTAS 1 MODUL 2

1 D 26 B

2 A 27 A

3 D 28 B

4 D 29 C5 B 30 B

6 A 31 D

7 C 32 D

8 D 33 D

9 C 34 C

10 C 35 A

11 A 36 B

12 C 37 D

13 D 38 A

14 B 39 B

15 D 40 A

16 D 41 D

17 C 42 C

18 B 43 A

19 A 44 B

20 B 45 B

21 D 46 B

22 D 47 B

23 A 48 D

24 A 49 B

25 D 50 A


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SULIT 1 4551/2 ( MODUL 2 PERATURAN PEMARKAHAN 2015)

4551/2 2015 Hak Cipta terpelihara MPSM (Cawangan Kedah)

SKEMA PEMARKAHAN BAHAGIAN A KERTAS 2 MODUL 2 2015 MPSM KEDAH

QUESTIONNO.

MARKING CRITERIA SUBMARKS

TOTALMARKS

1 (a) (i) Contractile vacuole 1 1mark

(ii) P1: Pond water is hypotonicP2: Water diffuse into XP3: by osmosisP4: X cannot / fail to contractP5: X cannot expel excess waterP6: Amoeba sp will burstP7: Amoeba sp will die

Any three Ps

1111111

3marks

(b) (i)

Amoeba sp Multicellular organism

P1: TSA/V is high P1: TSA/V is lowP2: does not involve any organ P2: involve organ, ex: lungP3: diffusion of oxygen andcarbon dioxide directly acrossplasma membrane // directexchange

P3: diffusion of oxygen andcarbon dioxide involving bloodcapillaries and alveoli

P4: process involved is simplediffusion

P4: process involved isbreathing, involving inhalationand exhalation / breathingmechanism.

Note: Accept explanation of respiratory system in fish / frog/grasshopper.( Any suitable mark scheme )

11

1

1

3marks

(c) (I) P1: Location A has low light intensity compared to Location BP2: Amoeba response to adverse stimuli, which is high light intensityP3: More Amoeba live in dark/low light intensity area

[Any 2]

111

2marks

P1: The pH / temperature of the water will changeP2: lead to water pollutionP3: Habitat / River are unfavorable for growth of Amoeba sp.P4: Amoeba sp. will dieP5: Amoeba sp. population decrease

[Any 3]

11111 3

marks

TOTAL 12


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QUESTIONNO


TOTALMARKS

2 (a) (i) Able to state the type of transport

Answer :

P : simple diffusion

Q : facilitated diffusion

11

2

marks

(ii) Able to give one particle move through Q and R

Answer :Q : sodium / potassium ions / any suitable exampleR : glucose / amino acid / any suitable example

11

2

marks

(iii) Able to compare the transport process involving particles Q

and R

Answer :

Process at Q Process at R

Similarities

P1. Both process involving the structural protein / carrierprotein / channel proteinP2: Both process involving the movement of substances.

Differences

P3. (Molecule) move followthe concentration gradient

(Ion) move againstconcentration gradient

P4. Do not need energy /ATP

Need energy / ATP

P5. The process continueuntil equilibrium achieve

The process end with theaccumulation or secretionof particles

[ Any 3 Ps

11

1

1

1

Any 3marks

(b) Able to explain what happen to the uptake of potassium ion inthe presence of cyanide

Answer :P1 : cyanide halts/stops aerobic respirationP2 : glucose cannot be oxidizedP3 : No ATP/energy is producedP4 : Since active transport needs ATP/ energyP5 : the intake of potassium ion / substances by active

transport also stopped

[ Any 3 Ps]

1111

1

3

marks


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(c) Able to explain how food can last longer

Answer :P1 : Concentrated salt solution is hypertonic to the squid

cells//squid cell is hypotonic to the concentration of saltsolution

P2 : Water diffuse out of the cell into the solution by osmosisP3 : Microorganism cannot live / breed / dehydrated in the

squid, thus food is preserved[ Any 2 Ps]

1

1

1

2

marks

TOTAL 12


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QUESTIONNO


TOTALMARKS

3 (a) (i) P : alveolusQ : gills

11

2

(ii) F 1 : Human lung has many alveoli and the gills of a fish

composed filament and lamellaeP1 : to increase the surface area for gaseous

exchangeF2 : Alveoli and the gill filament have thin

membrane.P2: for rapid diffusion of respiratory gases

F3 : The gill filament and alveoli have rich supply ofblood capillaries

P3 : To transport the respiratory gases efficiently

1

1

1

1

11

Terima Pjika adaF yangsepadan.Terima Ftanpa P

4marks

(b) F1: The partial pressure of oxygen in the alveolus is higher

compared to the partial pressure in blood capillaries.P1: Therefore, oxygen diffuse into the blood capillariesP2: (by) simple diffusion

ORF2: The partial pressure of carbon dioxide in the blood

capillaries is higher compared to the partial pressure inalveolus

P3: Therefore, carbon dioxide diffuse into the alveolusby simple diffusion

[Any F1 + P1 or F2 + P2]

1

11

OR

1

12

marks

(c) P1: Breathing rate during vigorous activity is higherP2: to supply more oxygen to muscle cell .

P3: To carried out cellular respiration/oxidation of glucoseP4: To release more energy

Any 2 Ps

11

11

2marks

(d) Chemicalcompound

Effect

P1: Tar Deposits in lung and cause persistent coughand shortness of breath

P2: Nikotin Restricted the bood vessel cause highblood pressure

P3: 3,4benzo pyrena

Carcinogenic substances cause lung cancer

P4: Carbon

monoxide

Reduce oxygen supply in the body cell

P5: Oxide ofnitrogen

Inflammation in lung

P6: Any suitable example and effect.

1+1

1+1

1+1

1+1

1+1

2marks

Any pair of P ( 1+1 )

TOTAL: 12 Marks


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QUESTIONNO


TOTALMARKS

4 (a) (i) Able to name the tissues:X : ligamentY : tendon

11

2marks

(ii) Able to label tissue X and Y on diagram correctly

Any one Xand oneYlabelled correct

1

1

2

marks

(iii) Able to explain why possible to apply ice to reduce pain :P1:( ice ) decrease tissues temperatureP2: provides vasoconstriction //narrow the blood vesselsP3: decrease / slow down the blood flows to the affected areaP4: reduce fluid building in the affected areaP5:(ice) numbs the area (can reducing pain)P6: create a soothing feeling to the inflammation// heat

increase inflammationP7:low temperature reduce nerve conduction velocity

//lowering the speed of impulses

P8: low temperature reduce tissue metabolism // oedema[Any 2 Ps]

111111

1

1

2

marks

(b) (i) Able to identify the fracture boneFibula 1

1mark

(ii) Able to explain why the cast is use to treat fracture legP1: to immobilize / realign boneP2: prevent affected bone from moving / to prevent further

injury.P3: bone cells / tissues then build / grow new bone cells

/tissues // repair / connect the fracture / broken boneP4: artificial bone is used to replace severely damaged /

discard bone

[Any 3 Ps]

11

1

13

marks

(iii) Able to suggest the diet that should consumed by patientP1: food rich in calcium to increase bone mass.P2: calcium is important in the formation of bone mass.P3: high with Vitamin D to increase reabsorption of calcium

[Any two]

111

2 Marks

TOTAL : 12 Marks


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QUESTIONNO


TOTALMARKS

5 (a) (i) neurone X : afferent neurone//sensory neurone 1

2 marksNeurone Y : efferent neurone//motor neurone 1ii. P1: Reseptor detects the stimulus 1

3 marks

P2: Stimulated to trigger nerve impulse in afferent neurone 1

P3: The nerve impulses are carried by the afferent neuroneto the central nervous system/brain /send to interneurone

1

P4: Central nerves system integrate and interpret theinformation

1

P5: trigger / send new nerve impulses 1

P6: Carried by the efferent neurone to the effectors 1

[ Any 3 PS]

(b) (i) P1: gap T is synapse

3 marks

P2: A nerves impulses arrives at a synaptic knob of theaxon terminal

1

P3: The nerve impulse stimulates the vesicles to releaseneurotransmitters

1

P4: The neurotransmitter (molecules) diffuse across thesynapse to the dendrites of the subsequent / adjacentneurone.

1

P5: The dendrites is stimulated to then trigger the newimpulse

1

P5:The new impulses then travels along the neurone toanother neurone or effector

1

[ Any 3 PS](ii) P1: Suffer from Alzheimers disease 1

2 marks

P2: Lack of acetylcholine in the brain 1

P3: Caused loss of memory // lack of concentration/ 1

P4: Confusion / poor judgment / loss ability to speak / read /write

1

[ Any 2 PS]

(c) P1: Increase the heart beat 1

2 marks

P2: Increase breathing rate 1

P3: Increase blood pressure 1

P4: transport more glucose and oxygen to muscle. 1

P5: Increase the metabolic rate / rate of cellular respiration. 1

P6: produce more energy 1

[ Any 2 PS]

TOTAL 12 Marks


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SKEMA PEMARKAHAN BAHAGIAN BKERTAS 2 MODUL 2 2015

No Marking Criteria Marks TotalMarks

6 (a) Explanation:

F1 : Mr X has (no Hepatitis A antigen and) no antibodiesagainst Hepatitis B

E1 : Mr X is not infected by the virus / has never got infected by the disease

F2 : Mr Y has (no Hepatitis B antigen but has) antibodiesagainst Hepatitis B.

E2 : Mr Y had been infected with undergone the disease andrecovered / Mr Y has been vaccinated against Hepatitis B

E3 : Therefore, Mr Y s immune system has producedantibodies against the disease

Discussion:

F1 : Mr Ys levelof antibody against Hepatitis B in the bloodis above the immunity level

E1 : Mr Y does not need to be immunised because he has acquirednatural active immunity / artificial active immunity

E2 : Thus, Mr Y has immunity against future Hepatitis B infections

F2 : Mr X does not have any antibody, so need to beimmunised against the disease by vaccination.

F3 : The vaccine stimulates the immune system of Mr X toproduce antibodies against the Hepatitis B virus.

E3 : Mr X acquires artificial active immunity against Hepatitis B

[Any 10 ]

1

1

1

1

1

1

1

1

1

1

1

10Marks


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(b) P :

P1 - The second line of defence

P2 - The white blood cell in P is a phagocyte.

P3 - The two main types of a phagocyte are the neutrophils and

monocytes

P4 - Monocytes can enlarge and develop into microphages

P5 - Phagocytes carry out phagocytosis / a process of engulfing and

ingesting microorganisms or other substances such as cellular

debris

P6 -When a phagocyte encounters an invading pathogen, the

phagocyte engulfs the organism

P7 - After the organism is engulfed and drawn inside the phagocyte,

lysozyme digest the pathogen

Q :

P8 - The third line of defence

P9 - The white blood cells in Q are lymphocytes

P10 - The outer surface of an invading microorganism contains

antigens which the immune system recognizes as foreign or

non-self

P11 - The antigens induce the lymphocytes to produce specific

antibodiesP12 - Each antibody molecule has an antigen-binding site that is

highly specific and can only bind to a specific antigen

P13 - After binding to the antigen molecule, the antibody clumps the

pathogens together.

P14 - The clumping makes the pathogens easy targets for phagocytes

to capture and destroy

[ Any 10 ]

1

1

1

1

1

1

1

1

1

1

1

1

1

1

10marks

TOTAL 20 MARKS


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7(a) (i) P1 - Proses meiosis menyebabkan bilangan kromosomdalam gamet menjadi haploid

P2 - Pindah silang yang berlaku semasa profasa 1

meiosisP3 - Penyusunan rawak kromosom homolog pada

peringkat metafasa I meiosisP4 - Pemisahan kromatid semasa anafasa II meiosisP5 - Menghasilkan pelbagai jenis gamet dengan

kandungan genetik yang berbezaP6 - Persenyawaan secara rawak menghasilkan zigot

yang mempunyai maklumat genetik yang berbezadaripada induknya

P7 - Gen yang diturunkan dari induk kepada anak-anakterdiri daripada gen dominon dan gen resesif

P8 - Gen dominan akan menunjukkan ciri-cirinya, tetapi

gen resesif tidak ditonjolkanP9 - Hanya separuh daripada bilangan kromosom daripada ibu

akan diturunkan kepada anak dan separuh daripada bilangankromosom daripada bapa untuk menghasilkan individu baru

// persenyawaan secara rawak antara gamet menghasilkanindividu baru

P10 - Mutasi gen / mutasi kromosom boleh menghasilkanindividu dengan trait yang berbeza

[ mana-mana 6]

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1

1

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1

1

1

1

1 6markah

(ii)P1 Menggunakan cap jari, cap jari kembar seiras adalah

tidak samaP2 disebabkan oleh faktor persekitaranP3 menggunakan ujian geneticP4 melalui ujian DNAP5 99 % adalah tepat

[Mana-mana 4]

1

1111

4Markah

(b)F: Anemia sel sabitP1 Penyakit ini adalah penyakit pewarisan / diwarisi

dari ibu bapaP2 Mewarisi alel resesif daripada kedua-dua ibu dan

bapaP3 Penyakit ini berlaku disebabkan oleh mutasi genP4 Mutasi gen berlaku semasa pembentukan gamet

1

1

111


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SULIT 10 4551/2 ( MODUL 2 PERATURAN PEMARKAHAN2015)



P5 - Susunan DNA berubahP6 - Penyusunan amino asid, berubah Glutamic asid

telah diganti dengan ValineP7 - Menyebabkan bentuk sel darah merah berubahP8 - Sel darah merah berbentuk bulan sabit terhasilP9 - Mempunyai jumlah luas permukaan yang kecil.P10: Kadar pertukaran gas lebih rendah.P11: Kandungan haemoglobin juga kurang berbanding dengan sel

darah merah yang normal.P12: Keadaan ini menyebabkan pengangkutan oksigen

berkurang.P13- Menyebabkan pesakit mudah letih/pucat /lemah

[ Mana-mana 10]

1

111111

1

1

10Marks

Total: 20 Marks

8(a) (i)

P1only mature trees are removed.P2Reforestation // large scale replanting of trees.P3establishing forest reserveP4to maintain the equilibrium of the ecosystemP5law of forest enforcement continuouslyP6maximise recycle campaign.

P7plant quick growing and deep-rooted trees to prevent soilerosion.

[ Any 4]

111111

1

4

Marks

(ii)P1 to obtain timber for constructionP2 - to obtain wood for producing paper and other wood products.P3wood for cooking and heating purposesP4to clear land for agricultural, such as planting crops and

grazing livestock.P5for mining of mineral such as tin and iron.

P6for urbanisation // building of roads and buildings.P7to build dam for water reservoir.P8to build hydroelectric power station.P9to build recreation park.

[Any 6 ]

1111

1

1111

6Marks


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NoMarking Criteria Marks Total

Marks8 (b)

F1CFC Free is used to reduce ozone depletion.

P1the destruction of the ozone layer is mainly due to increasinglevels of CFC ( Chlorofluorocarbons) in the atmosphere.

P2ozone layer absorb ultraviolet (UV) radiationP4and shield organisms from its damaging effects // mutation // skin

cancer // reduce immune system of animals and humans.P5CFCs are used as coolants in air conditioners and refrigerator //

propellants in aerosol cans // foaming agents in the making ofStyrofoam packaging.

P6CFCs are currently being replaced by HFC.P7HFC do not break down ozone moleculeP8or replaced by HCFCs which has a low ozone breakdown.

F2hybrid car using both conventional petrol engine and electricgenerators.

P9it reduce emission of greenhouse gases / CO2.P10example: carbon dioxide (CO2)// nitrous oxide (N2O).P11an increase of carbon dioxide concentration in the atmosphere

leads to greenhouse effect.P12also cause global warming // the Earths average temperature

rises // melting of polar ice caps // causing sea levels to rise //flooded in low land area // drought // risk to human health suchas heat related illness.

P13use unleaded petrol is to reduce emission of lead from motorvehicles

P14lead is an air pollutant which may leads to brain damage //kidney and digestive problems.

[ Any 10]

1

1

1

1

1

111

1

11

1

1

1

1

To1al 20Marks


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9(a)(i) Able to explain the consequences of having obesity

Sample AnswersP1 : The blood may contains high cholesterol level / glucose

levelP2 : Leads to high blood pressure/ hypertension (in adulthood)P3 : High possibility to suffer from diabetes (in adulthood)P4 : Have low self-esteem/ inactive lifestyleP5 : (due to) negative body imageP6 : Leads to depressionP7 : high risk of getting cardiovascular disease/ heart attack/

anginaP8 : earlier death (in adulthood)

Any 4 Ps

1

111111

14

marks

9(a)(ii) Able to suggest how to avoid the problems caused by obesity.

Sample AnswersP1 : Practise healthy eating habitsP2 : Reduce high sugar/lipid level food

// any suitable example of P1P3 : Awareness / Education on the consequences of obesityP4 : Awareness campaign of ideal BMI among students

// any suitable example of P3P5 : exercise regularly jogging / jumping rope / swimming

// any other suitable example of P5

P6 : increase outdoor activitiesP7 : avoid watching TV / screening time for too long

// any other suitable example of P7

Any 6 Ps

11

11

1

1

1

6marks

9(b)(i) Able to explain the graph presented by Thomas RobertMalthus.

Sample AnswersP1 : The population increases by exponentiallyP2 : The food production increases by arithmetically

P3 : The food production fail to meet the demand from thepopulation

P4 : Leads to human conflict / drastic competition for food

Any 2 Ps

11

1

12

marks


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9(b)(ii) Able to explain why the prediction does not occur.

Sample AnswersP1 : controlled / decrease the growth rate of human population.P2 : any example of suitable technologies / approach in

controlling the birth rateP3 : Increase the production of foodP4 : Food technologies / any example 1P5 : Food technologies / any example 2P6 : Improve the irrigation systemP7 : Introduce high quality fertilizersP8 : Improve the quality/resistance of the plants / livestockP9 : the technique used / cloning / GMF / transgenicP10 : re-planning the plantation / farming schedule.P11 : use of physical capital / machineP12 : change the eating habits / reduce the amount of food

intake (for better health)

Any 8 Ps

11

1111111111

8marks

TOTAL: 20 Marks


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1

SULIT 4551/3

4551/3 2015 Hak Cipta Terpelihara MPSM(Caw Kedah)

PERATURAN PEMARKAHAN BIOLOGI KERTAS 3 MODUL 2 MPSM 2015No Explanation Score1(a) Able to record all 4 readings for the difference in mass of visking

tubing correctlySample answer:

Concentration ofsucrose solution (%)

Difference in mass ofvisking tubing after 30

minutes (g)10 0.6520 0.9030 1.4540 2.65

3

2 Able to record 3 readings for the difference in mass correctly 21 Able to record 1- 2 readings for the difference in mass correctly 1

0 No correct response 0

Explanation1(b)(i) Able to state two correct observations based on the following criteria

C1concentration of sucrose solutionC2difference in mass of visking tubing

Sample answer:Horizontal observations

1. In 10% concentration of sucrose solution, the difference inmass of the visking tubing after 30 minutes is 0.65 g.

2. In 40% sucrose solution, the difference in mass of the visking

tubing after 30 minutes is 2.65 g.Vertical observation

3. The difference in mass of visking tubing after 30 minutes in10% concentration of sucrose solution is lower than in 40%concentration of sucrose solution.

4. The higher the concentration of sucrose solution, the largerthe difference in mass of visking tubing after 30 minutes.

3

Able to state one correct observation and one inaccurate response ortwo inaccurate observationsSample answer:Inaccurate horizontal observation

1. At 10% concentration of sucrose solution, the difference in

mass of visking tubing after 30 minutes is lower2. At 40% concentration of sucrose solution, the difference in

mass of visking tubing after 30 minutes is higher.

2

Able to state two observations at idea level ( refer to summary ofscoring)Sample answer:

1. The final mass of visking tubing changes2. Concentration of sucrose solution is different.

1

No correct response . 0


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2

SULIT 4551/3


Summary of scoring for observation and inferenceScore Correct Inaccurate idea wrong

3 2 - - -2 1 1 - -

- 2

1 1 - 121 1

1 10 - 1 - 10 - - 1 1

No Explanation1(b)(ii) Able to state all correct inferences for the observation based on the

criteria:C1: lower/higher concentration of sucrose solutionC2 : less / more water molecules diffuse into the visking tubing

C3 : by osmosis

Sample answer:Horizontal observations

1. In lower concentration of sucrose solution// dilute solution,less water molecules diffuse into the visking tubing byosmosis

2. In higher concentration of sucrose solution// concentratedsolution, more water molecules diffuse into the visking tubingby osmosis.

Vertical observation3. Less water molecules diffuse into the visking tubing in lower

concentration of sucrose solution compared to higherconcentration of sucrose solution by osmosis.

4. The higher the concentration of sucrose solution, the morewater molecules diffuse into the visking tubing by osmosis.

3

Able to state two correct inference and one inaccurate inference orAble to make two inaccurate inferencesSample answer:Inaccurate horizontal inference

1. In lower concentration of sucrose solution, less watermolecules diffuse into the visking tubing

Inaccurate vertical inference2. More water molecules diffuse into the visking tubing in lower

concentration of sucrose solution compared to higherconcentration of sucrose solution.

2

Able to state two inferences at idea level ( refer to summary ofscoring)Sample answer:

1. Osmosis occurs2. Water molecules diffuse.

1

No response or wrong response. 0


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3

SULIT 4551/3


No Explanation1(c ) Able to state all the variables and the method to handle variable

correctly.

Variable Method to handle the variable

Manipulated variableConcentration of sucrosesolution

Use different concentration ofsucrose solutions 10%, 20%, 30%and 40% // Change theconcentration of 10% into 20%,30% and 40% of sucrose solution

Responding variableDifference in / final mass ofvisking tubing after 30minutes

Rate of osmosis

Measureand record the differencein / final mass of visking tubing after30 minutes by using electronicbalance /weighing balance

Calculatethe rate of osmosis by

using formula =Final massinitial mass ( gmin -1)Time taken

Controlled variableTime taken

Volume of sucrose solution

Fixthe time taken for 30 minutes

Fix the volume of sucrosesolutions at 10cm3

3

Able to get 4-5 ticks 2Able to get 2-3 ticks 1One tick or no response or wrong response. 0


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4

SULIT 4551/3


No Explanation Score1(d) Able to state the hypothesis correctly based on the following criteria:

R1concentration of sucrose solutionR2difference in / final mass of visking tubing (after 30 minutes) //rate of osmosis

H the relationshipSample answer:1. As the concentration of sucrose solution increases, the

difference in mass of visking tubing (after 30 minutes)// rate ofosmosis increases.

2. The higher the concentration of sucrose solution, the higherthe difference in mass of visking tubing(after 30 minutes) //rate of osmosis

3

Able to state the hypothesis but less accurateSample answer:

1. Concentration of sucrose solution affects the difference inmass of visking tubing (after 30 minutes)

2. As the sucrose solution increases, the difference in mass ofvisking tubing (after 30 minutes) increases

2

Able to state the idea of the hypothesisSample answer:

1. Difference in mass of visking tubing decrease.2. As the difference in mass of visking tubing decrease, the

concentration of sucrose solution increase. ( reversehypothesis)

1

No correct response 0

No Explanation Score

1(e)(i) Able to construct a table and record the result of the experiment withthe following criteriaC1: able to state the titles with units correctlyC2: able to record all the data correctlyC3: able to calculate the rate of osmosis correctlySample answer:

Concentrationof sucrose

solution (%)

mass of visking tubingafter 30 minutes (g)

Differencein mass of

viskingtubing

(g)

Rate ofosmosis(g min -1)Initial mass

(g)Final

mass (g)

10 10.64 11.29 0.65 0.022/0.02

20 10.80 11.70 0.9 0.030/0.03

30 10.25 11.70 1.45 0.048/0.0540 10.22 12.87 2.65 0.088/0.09

3

Able to construct a table and record any two criteria 2


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5

SULIT 4551/3


Able to construct a table and record any one criterion 1No correct response 0

No Explanation Score1(e)(ii) Able to draw the graph correctly with the following aspects:

Axes (A)both axis are labeled with units and uniform scalesPoint (P)all points are correctly plotted / transferred correctlyShape (S)able to join all the points to form a smooth curvegraph.(reject straight line)

3

Graph with any two criteria 2Graph with any one criteria 1No response or wrong response 0

No Explanation Score1(f) Able to interpret data correctly and explain the relationship based on

the following aspects

P1 : distilled water is hypotonic to the concentration ofsucrose solution( in visking tubing) // the concentration ofsucrose solution is higher / hypertonic compared todistilled water // vice-versa

P2 : increase the mass of visking tubingP3 : the rate of water molecules diffuse into the visking tubing

is higher compared to the rate of water diffuse out of thevisking tubing by osmosis

Sample answer:The mass of visking tubing increases (P2) as the distilled water (inthe beaker) is hypotonic to the concentration of sucrose solution (in

visking tubing) (P1). So the rate of water molecules diffuse into thevisking tubing is higher compared to the rate of water diffuse out ofthe visking tubing by osmosis (P3).

3

Able to interpret data correctly and explain the relationship based onany two criteria.

2

Able to interpret data correctly and explain the relationship based onany one criteria.

1

No response or wrong response 0

No Explanation Score1(g) Able to predict and explain the outcome of the experiment correctly

based on the following item:

P1: the difference in mass of visking tubing is less than 0.9 gR1: the hypertonic solution // the higher concentration of

solution in the beaker compared to the solution in the viskingtubing

R2: more water molecules diffuse out of the visking tubing into thebeaker by osmosis

3


80/86

6

SULIT 4551/3


Sample answer:The mass of visking tubing is less than 0.9 g because the solution inthe beaker is hypertonic// the higher concentration of solution in thebeaker compared to the solution in the visking tubing. So more waterdiffuse out of the visking tubing into the solution in the beaker byosmosis.Able to state predict and explain the outcome of the experiment withtwo aspects

2

Able to state predict and explain the outcome of the experiment withone aspect

1


No Explanation Score1(h) Able to define operationally based on the result of the experiment

with the following aspects:

C1: movement/diffusion of water molecules in / out across theviskingtubing

C2 :difference in mass /final mass of visking tubing (after 30 minutes)C3: different concentration of sucrose solution

Sample answer:Osmosis is the net movement / diffusion of water molecules in/ outof the visking tubing results in the difference in mass // final mass ofvisking tubing(after 30 minutes). It is affected by differentconcentration of sucrose solution .

3

Able to define operationally on the result of the experiment with twoaspects correctly 2

Able to define operationally on the result of the experiment with oneaspect correctly / theoretical definition.

1


No Explanation Score1(i) Able to classify all 3 solutions concentration and types of solution

correctly

Solution concentration (%) Types of solution compared tothe osmotic concentration of cell

sap0.25% Sodium chloride solution Hypotonic0.80 % Sodium chloride solution Isotonic1.10% Sodium chloride solution Hypertonic

3

Able to classify two solutions concentration and types of solutioncorrectly.

2

Able to classify one solutions concentration and types of solutioncorrectly.

1



81/86

7

SULIT 4551/3



82/86

8

SULIT 4551/3


Suggested answer for Question 2

KB061201 ( Problem statement)

Question Score Explanation Remarks

2 (i) 3 Able to state the problem statement correctly :P1 : Water samples Station A, B and CP2 : Time taken for decolourisation of Methylene blue

Solution // BOD value // Level of water pollutionH : Question form

Sample answer:Which of the Station of water samples will be more polluted //give the highest BOD value ?How do water sources /samples from Station A, B and C affect

the time taken for decolourisation of Methylene blue solution?

2 Able to state a problem statement less accurately.

Sample Answer:Which station will be the most polluted water ?/ have highestBOD value?How do water at station A,B and C affect the methylene bluesolution?

1 Able to state a problem statement at idea level

Sample Answer:

BOD value / water pollution is influenced by different station./water sources

0 No response or wrong response


83/86

9

SULIT 4551/3


KB061202 ( KB061203 Making Hypothesis )


2 (ii) 3 Able tostate the hypothesis based on the following aspects:P1 = Manipulated variable = Water sources / sample from

Station A, B and C.P2 = Responding variable = Time taken for decolourisation

of Methylene blue Solution// BOD value / Level of water

pollutionR = Relationship / Link

Sample answer :Station B are the mostpollutedwater sources/ samplecompare toStation A and C//.Station B have the highest BOD valuecompare to Station A and C

2 Able to write a hypothesis statement less accurately

Sample answer:Station B is the most polluted water / has higher BOD value.Station C is the least polluted water and low BOD Value.

1 Able to state a hypothesis at idea level

Sample answer:

1. Water sources/ samples from different station affects thetime taken / the decolourisation of Methylene blue

solution2.

0 No response or wrong response


84/86

10

SULIT 4551/3


KB061203 ( Variables)


2 (iii) 3 Able to state all the three variables correctly

Sample answers :1. Manipulated variableWater sources/ samples from Station A, B and C2 Responding variable

Time taken for decolourisation of Methylene blueSolution // BOD value /Level of water pollution

3 Constant variable1. Volume of water sources / samples2. Concentration of Methyleneblue solution3. Temperature

2 Able to state any two variables correctly

1 Able to state any one variable correctly

0 No response or incorrect response

KB061204 - ( Apparatus and materials)


2(iv) 3 Able to list out all the important apparatus and materialscorrectly.Sample answers:

Apparatus:Reagent bottles, syringe, cupboard / black paper, stopwatch, label paper / marker pen, measuring cylinder,beaker

Materials:Water sources / sample from Station A, B and C

Methylene blue solution2 Able to list 5-6 apparatus and 2 materials correctly

1 Able to list 2-4 apparatus and 2 materials correctly



85/86

11

SULIT 4551/3


KB061205 ( Experimental Procedure)


2(v) 3 Able to describe allthe steps of the experimentcorrectlySample answers:1. 150 ml of water sources from Station A, B and Cwere taken and brought back to the laboratory. (K2, K1)2. 100 ml of water sources from Station A weremeasured by using a measuring cylinder and thenpoured into the reagent bottle. (K2, K1)3. By using a syringe, 1 ml of 0.1% methylene solutionis added to the bottom of each water sources / samples.(K2/ K1)4. The reagent bottle is closed quickly with a glass

stopper and labeled as A(K5)5. And dont shake the bottle.(K5)6. Steps 1 to 4 were repeated by using water sources

/ samples from Station B and C and labeled as B and C.( K4)7. All the reagent bottles are kept in a dark cupboard /wrap with black or sugar paper.( K1)8. The time taken for decolourisation of ethylene blue

solution is recorded using stopwatch (K3)9. At intervals of one hour for a period of four hours,

each reagent bottle is examined.(K1)10.All data are recorded in a table. (K1)Note:

K1: Steps 1,2,3,7,9,10 ( Setting apparatus)K2: Step 1,2,3 (Operating fixed variable)K3: Step 8 (Operating responding variable)K4: Step 6 (Operating manipulated variable)K5: Step 4,5 (Precaution)

3 All the 5 Ks

2 Any 3-4 K

1 Any 2 K



86/86

12

SULIT 4551/3

KB061206 ( Presentation of Data)


2(vi) 2 Able to present all the data with units correctly

Sample answer:

Water sources

/ sample

Station

Time taken for

decolourisation

of methylene

blue solution /

(hours)

BOD value and

pollution level

A

B

C

1 Able to present at least one data without unit or

incorrect unit


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