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SMK. TAMAN PERUMAHAN BEDAUN Jawapan

SPM Matematik Tingkatan 4,5 - Untitled Kertas 21. (a) When x = –1,

h = 2(–1)2 – 5(–1) – 4

= 2 + 5 – 4

= 3

When x = 2,

k = 2(2)2 – 5(2) – 4

= 8 – 10 – 4

= –6 ∴ h = 3, k = –6

(b)

(c) (i) When x = –1.5,

y = 8

(ii) When y = 6,

x = –1.3, 3.8(d) 0 = 2x2 – 7x – 9 …… ①

y = 2x2 – 5x – 4 …… ②

② – ①: y = 2x + 5

(Draw the straight line y = 2x + 5.)

From the graph, x = –1, 4.5

2.

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3. (a) y = 3 + 2x – x2

When x = 1, y = 3 + 2(1) – 12 = 4 Thus, m = 4.

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When x = 4, y = 3 + 2(4) – 42 = –5

Thus, n = –5.(b)

(c) (i) y = –2.2 (ii) x = –0.4, 2.4

(d) y = 3 + 2x – x2 ... ➀

0 = 6 + 3x – x2 ... ➁

➀ – ➁: y = –3 – x y = –x – 3

By drawing the straight line y = –x – 3 on the graph;x = –1.4, 4.4

4.

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(b)

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(c) (i) y = 32

(ii) x = –1.7