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V. DATA PENGAMATAN

CaCO31 %

v Waktu / t (5) t/v P

1 927 927

-0,02 bar

2 1678 839

3 2189 729,67

4 2635 658,75

5 3066 613,2

CaCO33%

v Waktu / t (5) t/v P

1 1142 1142

-0,02 bar

2 1987 993,5

3 2458 819,333

4 3115 778,75

5 3349 669,8

CaCO35 %

v Waktu / t (5) t/v P

1 1707 1707

-0,02 bar

2 2895 1447,5

3 3731 1243,667

4 4822 1205,5

5 5367 1073,4

Tabel perba!"#a

, R m ,

pa!a ru 1$ ru !a ru3

&u

'etra

" CaCO3(

m

kg) &* /* (

kg

ms)

1 1 % 487,112181 424966,8982 0,3311

2 3 % 97,2933 218865,2876 0,7928

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3 5 % 62,008 260243,5105 0,9708

VI. PE&+,T-NGAN

1. aruta CaCO3 1 %

m CaCO3= 60 gram = 906 kg

A. Menghitng C!

Cs=m

v=

0,6kg

6.103

m3=10kg/m3

". Menghitng A

A=1

4 D

2

1

4(3,14 ) (0,3m)2=0,07065 m2

C. Menghitng P

P=0,02 0,2.104N/m2

#. Menghitng CaCO3

"erat $iknmeter k!ng &a' = 36,79 gram

"erat $iknmeter ( a)a*e!t &b' = 58,48 gram

"erat a)a*e!t &+' = b-a

= 58,48 gram 36,79 gram

= 21,69 gram

volume aquadest+volume piknometer=21,69gram

1gram /ml=21,69ml

"erat $iknmeter ( !am$e &*' = 58,46 gram

"erat !am$e = *- a

= 58,46 gram 36,79 gram

= 21,67 gram

CaC O3=

berat sampel

v piknometer=

21,67gram

21,69ml =0,9990gr /ml

. Menghitng /i!k!ita! & '

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bola=2,2 g

m3=2,2.103kg /m3

d bola=0,01 m

r bola=0,005m

! bola=

4

3 r

3

4

3(3,14 ) (0,005m)3

5,2333.107

m3

!=

s

t

0,272m

1,35 s =0,2015

m

s

mbola=bola " v bola

2,2.10

3kg

m3 .5,2333 "10

7

m3

1,1513.103 kg

mo= CaC O3" vbola

0,9990 gr10

3kg

m3 .5,2333 "10

7m

3

5,2281#104 kg

=

(mmo )g6rv

=

(1,1513.103 kg5,2281.104 kg) .10ms2

6.3,14 (0,005 m )(0,2015 ms)0,3311kg /ms

#ari graik *i$ereh $er!amaan

= -80,78 ( 995,8 2= 0,979

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$e = -180,78

nter!e$t = 995,8

$ = 2 !$e

= 2 &-80,78'

= -161,56

" = inter!e$t = 995,8

. Menentkan harga tahanan +ake & '

=kp A

2( P) Cs

161,56 (0,07065m2 )2(0,2.104 Nm2 )0,3311

kg

ms.100

kg

m3

487,1121831m /kg

. Menentkan tahanan me*im iter &m'

$= " R m

A ( P)

Rm=$ " A ( P)

995,8(0,07065m2 )2

(0,2.10

4 N

m2

)0,3311kgms

424966,8982 /m

. aruta CaCO3 3 %

m CaCO3= 180 gram = 0,18 kg

A. Menghitng C!

Cs=m

v=

0,18 kg

6.103

m3=30kg/m3

". Menghitng A

A=1

4 D

2

1

4(3,14 ) (0,3m)2=0,07065 m2

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C. Menghitng P

P=0,02 0,2.104N/m2

#. Menghitng

CaCO3

"erat $iknmeter k!ng &a' = 36,79 gram

"erat $iknmeter ( a)a*e!t &b' = 58,48 gram

"erat a)a*e!t &+' = b-a

= 58,48 gram 36,79 gram

= 21,69 gram

volume aquadest+volume piknometer=21,69gram

1gram /ml=21,69ml

"erat $iknmeter ( !am$e &*' = 58,91 gram"erat !am$e = *- a

= 58,91 gram 36,79 gram

= 22,12 gram

CaCO3=

berat sampel

v piknometer=

22,12 gram

21,69ml =1,0198 gr /ml

. Menghitng /i!k!ita! & '

bola=2,2 gm

3=2,2.103kg /m3

d bola=0,01m

r bola=0,005m

! bola=

4

3 r

3

4

3 (3,14 ) (0,005m)

3

5,2333.107 m3

!=

s

t

0,272m

3,29 s =0,0827

m

s

mbola=bola " v bola

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2,2.10

3kg

m3 .5,2333 "10

7m

3

1,1513.103 kg

mo= CaC O

3" vbola

1,0198 gr10

3kg

m3 .5,2333 "10

7m

3

5,3369#104 kg

=(mmo )g

6rv =

(1,1513.103 kg5,3369.104 kg) .10ms2

6.3,14 (0,005 m )(0,0827ms)

0,7928 kg /ms

#ari graik *i$ereh $er!amaan

= -115,9 ( 1228

2= 0,962

$e = -115,9nter!e$t = 1228

$ = 2 !$e

= 2 &-115,9'

= -231,8

" = inter!e$t = 1228

. Menentkan harga tahanan +ake & '

=kp A

2( P) Cs

231,8 (0,07065m2 )2(0,2.104 Nm

2)

0,7928kgms

.30kg /m3=97,2933m /kg

. Menentkan tahanan me*im iter &m'

$= " R m

A ( P)

Rm=$ " A ( P)

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1228 (0,07065 m2 )2(0,2.104 Nm2 )0,7928

kg

ms

218865,2876 m

3. aruta CaCO3 5 %

m CaCO3= 300 gram = 0,3 kg

A. Menghitng C!

Cs=m

v=

0,3kg

6.103

m3=50 kg/m3

". Menghitng A

A=1

4 D

2

1

4(3,14 ) (0,3m)2=0,07065 m2

C. Menghitng P

P=0,02 2.104

N/m2

#. Menghitng CaCO3

"erat $iknmeter k!ng &a' = 52,84 gram

"erat $iknmeter ( a)a*e!t &b' = 142,45 gram

"erat a)a*e!t &+' = b-a

= 142,45 gram 52,84 gram

= 89,61 gram

volume aquadest+volume piknometer=

89,61gram

1gram /ml=89,61ml

"erat $iknmeter ( !am$e &*' = 145,06 gram

"erat !am$e = *- a

= 145,06 gram 52,84 gram

= 92,22 gram

CaCO3=

berat sampel

v piknometer=

92,22 gram

89,61ml =1,0291gr /ml

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. Menghitng /i!k!ita! & '

bola=2,2 g

m3=2,2.103kg /m3

d bola=0,01m

r bola=0,005m

! bola=

4

3 r

3

4

3(3,14) (0,005m)3

5,2333.107

m3

!=

s

t

0,272m

4,05 s =0,067

m

s

mbola=bola " v bola

2,2. 103 k g

m3 .5,2333 "10

7m

3

1,1513.103 kg

mo= CaC O3" vbola

1,0291 gr10

3kg

m3 .5,2333 "10

7m

3

5,3856 #104

kg

=

(mmo )g6rv

=

(1,1513.103 kg5,3856 "104 kg) .10ms2

6.3,14 (0,005m )(0,067ms)0,9708 kg /ms

#ari graik *i$ereh $er!amaan

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= -150,9 ( 1788

2= 0,931

$e = -150,9

nter!e$t = 1788

$ = 2 !$e

= 2 &-150,9'

= -301,8

" = inter!e$t = 1788

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