MathematicsT STPM Baharu PERAK 2012
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Transcript of MathematicsT STPM Baharu PERAK 2012
2012 TRIAL STPM BAHARU MATHEMATICS T SMK ACS IPOH,PERAK
SectionSectionSectionSection AAAA[45 marks]Answer allallallall questions in this section.
1. The functions f and g are defined as
f : xx1
→ , x +ℜ∈ andandandand g : x xln→ , x +ℜ∈
(a) State the ranges of f and g . [2[2[2[2 marksmarksmarksmarks](b) If h is the composite function gof, find the function h. [2[2[2[2 marks]marks]marks]marks](c) Show that h(x) + g(x) = 0. [1[1[1[1 mark]mark]mark]mark]
2. (a) Given ∑∞
=⎟⎠⎞
⎜⎝⎛
0 31
i
i
p = ( )∑=
+10
3
31j
j where p is a constant.
Find the value of p. [3[3[3[3 marks]marks]marks]marks]
(b) Use the binomial theorem to expandxx
−+
11 as a series of ascending powers
of x up to and including the term in x2 , where x <1.
Hence, by substituting x =101 , show that
20066311 ≈ . [6[6[6[6 marks]marks]marks]marks]
3.3.3.3. Matrices PPPP, QQQQ and RRRR are⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
−−−322211210
,⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛−−−15228387
333414and
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
−−−−
−
262333666
respectively. Find121 PQRPQRPQRPQR and deduce RRRR-1-1-1-1 . [4[4[4[4 marks]marks]marks]marks]
Hence, solve the system of linear equations x + y – z = 8-4x +4 y +4 z = 0x + 3y +z =10 [5[5[5[5 marks]marks]marks]marks]
4. Given that the real numbers r and θ , where r > 0 , - πθπ << ,r cosθ + 2r2 cos2θ + 3r3 cos3θ =0 and r sinθ + 2r2sin 2θ + 3r3 sin3θ =0.By writing z = r (cosθ + i sinθ ) and using De Moivre’s Theorem, show that
z = )21(31 i±− . [5[5[5[5 marks]marks]marks]marks]
Determine the value of r and the two possible values of tanθ . [4[4[4[4 marks]marks]marks]marks]
5. A curve has the parametric equations x = 8 cosθ + 3 and y = 4 3 sinθwhere πθπ ≤<− . Show that the curve is an ellipse and find its vertices, centreand foci. Sketch the ellipse. [9[9[9[9 marks]marks]marks]marks]
6. Find the value of α for which the vectors aaaa ==== 3iiii ---- 4jjjj ++++ kkkk and bbbb = iiii ++++ 2jjjj + α kkkkare perpendicular. Hence, find aaaa ---- bbbb . [4[4[4[4 marks]marks]marks]marks]
2012 TRIAL STPM BAHARU MATHEMATICS T SMK ACS IPOH,PERAK
SectionSectionSectionSection BBBB [15 marks]Answer any oneoneoneone question in this section.
7. (a) Solve for x the equation sin 2x = 3 cos2x, giving all solutions between 0o and360o correct to the nearest 0.1o. [5[5[5[5 marks]marks]marks]marks](b) Express 2 cos x + 5 sin x in the form r cos ( x - )α , where r>0 and
0<α < π21 . Hence, find the maximum value of 2 cos x + 5 sin x and the
corresponding value of x in the interval π20 ≤≤ x . [6[6[6[6 marks]marks]marks]marks]
Sketch the curve y = 2 cos x + 5 sin x for π20 ≤≤ x . [2[2[2[2 marks]marks]marks]marks]By drawing an appropriate line on the graph, determine the number of rootsof the equation 2 cos x + 5 sin x = 1, in the interval π20 ≤≤ x . [2[2[2[2 marks]marks]marks]marks]
8. The line l has equation rrrr =⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛+
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
012
505
λ , ℜ∈λ .
(a) Show that l lies in the plane whose equation is
rrrr .... 5021
−=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛−. [3[3[3[3 marks]marks]marks]marks]
(b) Find the position vector of A, the foot of the perpendicular from the origin O to l.[4[4[4[4 marks]marks]marks]marks]
(c) Find an equation of the plane containing O and l. [4[4[4[4 marks]marks]marks]marks](d) Find the position vector of the point P where l meets the plane π whose
equation is rrrr .... .11221
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛[4[4[4[4 marks]marks]marks]marks]
MATHEMATICALMATHEMATICALMATHEMATICALMATHEMATICAL FORMULAEFORMULAEFORMULAEFORMULAEBinomial expansions
,......21
)( 221 nrrnnnnn bbarn
ban
ban
aba ++⎟⎟⎠
⎞⎜⎜⎝
⎛++⎟⎟
⎠
⎞⎜⎜⎝
⎛+⎟⎟
⎠
⎞⎜⎜⎝
⎛+=+ −−− where n∈ZZZZ++++
...,!
)1)...(1(...!2)1(1)1( 2 +
+−−++
−++=+ rn x
rrnnnxnnnxx where ∈n QQQQ ,,,, x <<<<1
ConicsParabola with vertex ( h, k ), focus ( a+h, k ) and directrix x = - a + h
( y – k )2 = 4 a ( x – h )Ellipse with centre ( h, k ) and foci (- c + h, k ) , ( c + h, k ), where c2= a2 – b2
1)()(2
2
2
2
=−
+−
bky
ahx
Hyperbola with centre ( h, k ) and foci (- c + h, k ), ( c + h, k ), where c2= a2+ b2
1)()(2
2
2
2
=−
−−
bky
ahx
2012 TRIAL STPM BAHARU MATHEMATICS T SMK ACS IPOH,PERAK
1. The functions f and g are defined as f : xx1
→ , x ∈ ℝ AND g : x xln→ , x ∈ ℝ+
(a) State the ranges of f and g . [2 marks](b) If h is the composite function gof, find the function h. [2 marks](c) Show that h(x) + g(x) = 0. [1 mark]
1(a) Rf = {y : y > 0}
Rg = {y : y ∈ }
B1
B1
(b) gof(x) = g
= ln or – ln xM1
h : x� – ln x , x > 0 A1(c) h (x) + g(x) = – ln x + ln x
= 0A1
[5]
2. (a) Given ∑∞
=⎟⎠⎞
⎜⎝⎛
0 31
i
i
p = ( )∑=
+10
3
31j
j where p is a constant.
Find the value of p. [3 marks]
(b) Use the binomial theorem to expandxx
−+
11 as a series of ascending powers of x up to
and including the term in x2 , where x <1.
Hence, by substituting x =101 , show that
20066311 ≈ . [6 marks]
2(a)= OR
= 8 + 3{3 + 4 + 5 + . . . + 9 + 10}
B1 Either one
= 164 M1
p = A1
(b) ×= ×
= ×M1M1 Correct binomial
expansion
≈ 1 + x + ½x2 A1
= B1
2012 TRIAL STPM BAHARU MATHEMATICS T SMK ACS IPOH,PERAK
≈ 1 + +½
≈ 3 ×
≈
M1
A1
Subst. x =
[9]
3 Matrices PPPP, QQQQ and RRRR are⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
−−−322211210
,⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛−−−15228387
333414and
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
−−−−
−
262333666
respectively. Find121PQRPQRPQRPQR and deduce RRRR-1-1-1-1 . [4 marks]
Hence, solve the system of linear equations x + y – z = 8-4x +4 y +4 z = 0x + 3y +z =10 [5 marks]
3PQRPQRPQRPQR =
= M1 Correct QR
=
orororor PQRPQRPQRPQR =
= M1 Correct PQ
=
∴ PQRPQRPQRPQR =A1
PQRPQRPQRPQR = - 9 IIII
RRRR-1 = - PQPQPQPQ
= -
=
M1
A1By adjusting the system of linear equations : B1 Able to rearrange the
system of equations
2012 TRIAL STPM BAHARU MATHEMATICS T SMK ACS IPOH,PERAK
B1
M1 Reject all othermethods.
= A1
∴ x = 1, y = 4, z = -3
A1 [9]
4 Given that the real numbers r and θ , where r > 0 , - πθπ << ,r cosθ + 2r2 cos2θ + 3r3 cos3θ = 0 and r sinθ + 2r2sin 2θ + 3r3 sin3θ = 0.
By writing z = r (cosθ + i sinθ ) and using De Moivre’s Theorem, show that z = )21(31 i±− .
[5 marks]Determine the value of r and the two possible values of tanθ . [4 marks]
4 r cosθ + 2r2 cos2θ + 3r3 cos3θ = 0 (1)r sinθ + 2r2sin 2θ + 3r3 sin3θ = 0. (2)By operating (1) + i(2),r (cosθ + isinθ ) + 2r2(cos2θ + isin 2θ ) + 3r3(cos3θ + isin3θ ) =0
M1
r (cosθ + isinθ ) + 2r2(cosθ + isinθ )2 + 3r3(cosθ + isinθ ) 3 = 0 M1 Using De Moivre’stheorem
∴ z + 2z2 + 3z3 = 0
A1
OR z = r (cos θ + i sin θ)z2 = r2(cos 2θ + i sin 2θ) and z3 = r 3(cos 3θ + i sin 3θ) M1 Using De Moivre’s
theorem2z2 = 2r2(cos 2θ + i sin 2θ) and 3z3 = 3r 3(cos 3θ + i sin 3θ) M1
∴ z + 2z2 + 3z3 = 0
A1
2012 TRIAL STPM BAHARU MATHEMATICS T SMK ACS IPOH,PERAK
z (3z2 + 2z + 1) = 0
z ≠ 0, z =
=
M1
A1
| z | = B1
tan θ = or tan θ = M1
tan θ = - tan θ = A1A1 [9]
5 A curve has the parametric equations x = 8 cosθ + 3 and y = 4 3 sinθ whereπθπ ≤<− .
Show that the curve is an ellipse and find its vertices, centre and foci. Sketch the ellipse.[9 marks]
5 By using cos θ = and sin θ = with sin2 θ + cos2 θ = 1, B1 Eliminatingparameter θ
+ = 1M1
Using trig. identity
+ = 1
∴ the curve is an ellipse.
A1
Centre is (3, 0) A1The vertices are (-5, 0) and (11, 0) A1A1The foci are (7, 0) and (-1, 0) A1
x
y
(3, 0)● ●● ●●
●
●
(7, 0) (11, 0)(-1, 0)(-5, 0)
(3, 4 )
(3, - 4 )
D1
D1
Ellipse shape(dependent on thecorrect equationabove)
All ‘his’ points shownand labeled.
[9]
2012 TRIAL STPM BAHARU MATHEMATICS T SMK ACS IPOH,PERAK
6 Find the value of α for which the vectors aaaa ==== 3iiii ---- 4jjjj ++++ kkkk and bbbb = iiii ++++ 2jjjj + α kkkk areperpendicular. Hence, find | aaaa ---- bbbb |. [4 marks]
6 By using aaaa • bbbb = 0,
• = 0
α = 5
M1
A1
aaaa - bbbb = - M1
=
|||| aaaa – bbbb | == A1 Accept 7.48
[4]7 (a) Solve for x the equation sin 2x = 3 cos2x, giving all solutions between 0o and 360o
correct to the nearest 0.1o. [5 marks]
(e) Express 2 cos x + 5 sin x in the form r cos ( x - )α , where r >0 and 0<α < π21 .
Hence, find the maximum value of 2 cos x + 5 sin x and the corresponding value ofx in the interval π20 ≤≤ x . [6 marks]Sketch the curve y = 2 cos x + 5 sin x for π20 ≤≤ x . [2 marks]By drawing an appropriate line on the graph, determine the number of roots of theequation 2 cos x + 5 sin x = 1, in the interval π20 ≤≤ x . [2 marks]
7(a) 2sin x cos x - 3cos2x = 0 B1cos x (2sin x - 3cos x) = 0 M1 Reject division by cos
x
cos x = 0 or tan x =M1
x = 90 °, 270 ° or x = 56.3° , 236.3 ° A1
∴ x = 56.3°, 90 °, 236.3 °, 270 °
A1 All correct
(b) 2cos x + sin x ≡ r cos x cos α + r sin x sin αr sin α =r cos α = 2
B1 Both
r = 3, tan α = M1
r = 3, α = 0.841 radians. A1 Both
2012 TRIAL STPM BAHARU MATHEMATICS T SMK ACS IPOH,PERAK
∴ 2cos x + sin x = 3 cos (x – 0.841)
A1
max value is 3 B1when cos (x – 0.841) = 1 � x = 0.841radians. B1
y
x
3
2
-3
y =1
● ●
●(0.841, 3)
(2π, 2)
D1
D1
M1
A cosine curve with amax. and a min.turning point.
Initial and final pointsand ‘his’ max. point.line y = 1
There are 2 roots. A1 Dependent oncorrect graph.[15]
8 The line l has equation rrrr =⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛+
⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
012
505
λ , λ ∈ ℝ.
(a) Show that l lies in the plane whose equation is rrrr .... 5021
−=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛−. [3 marks]
(b) Find the position vector of A, the foot of the perpendicular from the origin O to l. [4 marks](c) Find an equation of the plane containing O and l. [4 marks]
(d) Find the position vector of the point P where l meets the plane π whose equation is rrrr .... .11221
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
[4 marks]8(a)
rrrr = + λ and rrrr • = -5
By using rrrr • nnnn = d,
• = -5 B1
2012 TRIAL STPM BAHARU MATHEMATICS T SMK ACS IPOH,PERAK
-5 – 2λ + 2λ = - 5 for all values of λ ∈ ℝ.
M1
∴ line l lies on the plane.
A1
(b)
= + λ1 , λ1∈ ℝ
• = 0
• = 0 B1
10 + 4 λ1 + λ1 = 0� λ1 = -2
M1
= - 2
=
M1
A1
(c)nnnn = ×
=M1
= A1
∴ equation of plane is rrrr •••• = ••••
rrrr •••• = 0 or – 5x + 10y + 5z = 0
M1
A1 Accept rrrr •••• = 0
(d) Since P is on line l,
2012 TRIAL STPM BAHARU MATHEMATICS T SMK ACS IPOH,PERAK
= + λ2 , λ2∈ ℝ
Given that rrrr .... .11221
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
.... .11221
=⎟⎟⎟
⎠
⎞
⎜⎜⎜
⎝
⎛
B1
5 + 2 λ2 + 2 λ2 + 10 = 11 M1λ2 = - 1 A1
= - 1
=A1 [15]