Perhitungan Propeller MT AFDAL MAMMAR
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Transcript of Perhitungan Propeller MT AFDAL MAMMAR
8/16/2019 Perhitungan Propeller MT AFDAL MAMMAR
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Laporan Praktikum Propulsi KapalMT "HARIZ"
Perhitungan Perancangan V Propeller Menggunakan Dasar
Princhipal Naval Architechture II
I. UKURAN UTAMA DAN BEARAN
85.6884 m
B = 5.! m
H = #.!# m
T = 5 m
.!! kn = 6.# m$s
%.! kn = 6.#& m$s
!.6&
!.#
!.&8! 'mi(s)ip *o+,,i*i+nt-
!.85 'at+rplan+ *o+,,i*i+nt-
44#&.46 ton = 4%#!.!#
L/B = !.6%6% m
= !.%4
!5
R+,+r+nsi0
/ompan1 H. 2tam3Haarl+m &48
LL = m '=! P7A II p.&-L
PP =
s+ri*+
=
trial
=
δ = '9lo*k *o+,,i*i+nt / 9-
ϕ = 'prismati* *o+,,i*i+nt / p-
/m =
/ =
∆ = m%
'(ata3(ata0 TR II Kura Hi(rostatik : Bon;+an-
ρ = k<$m%
Haral( Resistance an" Propulsion o# hips o)n il+1 an( 2ons 7> &85.
L+is ?(ar( @. Principles o# Naval Architecture Volu$e II% Resistance& Propulsion& an"
Vi'ration T)+ 2o*i+t1 o, 7aal Ar*)it+*ts an( Marin+ ?n<in++rs 7 &88.
@an Lamm+r+n .P.A. Troost L. Konin< .. Resistance& Propulsion& an" teering o# hips%
A Manual #or Designing (ull )or$s& Propellers& an" Ru""ers T)+ T+*)ni*al Pu9lis)in<
F n=vt
√ g× LWL=
6.79
√9.81×85 ,68
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Laporan Praktikum Propulsi KapalMT "HARIZ"
= *.+,,E-/ N
). E##ective (orse Po0er& E(P
E(P 1 'P7A II p.5% Haral(&85C +D. E&.6.%F-
=
=
= 8#4#!.%5&%4# att #%5.4&&
1 **,2.+34 (P
2+suai (+n<an rut+ p+la1aran ?HP (itam9a) !G 'TR I@ R.. rut+ 2ura9a1aMakasar-
E(P 1
1 *4+5.**5 (P
6. ha#t (orse Po0er& (P
'Haral(&85C +D. E&.6.5F-
!.͠
total efficiency
=
+,isi+nsi 9a(an kapal
= .% 'Haral( &85C 9r. 6.4.6 (ata TR I@ R+n*ana mum-
+,isi+nsi 9alin<39alin< (i 9+lakan< kapal
= !.&# 'Haral( &85C 9r. 6.%. (ata TR I@ R+n*ana mum-
+,isi+nsi poros
= !.#!! 'Haral( &85C (ata TR I@ R+n*ana mum-
Maka0
= !.#%%
4#.#
= *243.+5* HP
65.6
(. Breake (orse Po0er 7B(P8K+ru<ian (a1a untuk posisi m+sin (i 9+lakan< = %G 'P7A II p. !-
B(P 1 (P 9 *&:
1 +4.3/2 (P 5#4#.#
&%!%.&# attC 4&55.6!&
I. Pe$ilihan Mesin Uta$a
M+sin utama 1an< (i<unakan a(ala)0
Tip+ 0 /at+rpillar %56 B
K+*+patan 0 6!! rpm
Ja1a 0 !!! HP 5
E. Tahanan Total& R T
R T@
R T x
trial
.%! x 6.#&
' HP metricC = ;att -
!&.5# x .
ηT =
ηH . η
B .η
2
ηH =
ηB =
η2 =
ηT = .% x !.&# x !.#!!
RT =1
2 ρV 2 Stot [C F (1+k )+C A ]+
RW
W W
SHP= EHP
ηT
SHP=1451. 432
0.733
8/16/2019 Perhitungan Propeller MT AFDAL MAMMAR
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Ko+,isi+n prop+l+r Ta1lor0
'P7A II p.&-
n = revolution per minute (rpm) of propeller
delivered power at propeller
= (a1a m+sin in(uk
= !!! HP
speed of advance
J = (iam+t+r prop+l+r
= %.!!
@ 3 C 'P7A II p.46-
'P7A II p.5& +D. 46
vertical prismatic coefficient
=
= !.6& $ !.85
= !.84#
prismatic coefficient
= !.#
B = ship's breadth
= 5.! m
L = ship's length
= 85.68
T = ship's draft
= 5 m
? =
=
K = the rake angle of propeller blades, radians
= != !.#5 ra(
k = ko+,isi+n
= !.%
= !.%%
Maka 0
1 6.#& 3 !.%% C
1 4.5%5 m$s1 ,.,*3 knots
6
III. PER(ITUN6AN DIAMETER PR<PE!ER& Bp= DIA6RAM
PJ =
@a =
m '(ata TR I R+n*ana aris J !.6 x T-
A. Perhitungan Va
@a =
/p
=
/ 9 $ /
/ p =
m 'LL
-
tin<<i poros prop+l+r (ari baseline
m '(ata TR I R+n*ana aris ? !.4 x T-
o
'(iran*an< s+n(iri-
'9+ntuk stern normal-
Va 1 @
t 3 C
B p=
n ( P D )0 .5
(V a )2. 5
δ =nD
V a
w=0.10+4.5C
vpC
pB / L
(7−6C vp ) (2. 8−1. 8C p)+1
2 ( ET −
D
B−k ' K )
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IV. U>I KAVITAI
Tip+ rpm Ja1a HPC
%56 B 6!! !!!
%56 B #!! 5!
%56 B 8!! 5!!
2+)in<<a (ipili) untuk putaran = #!! rpm
A . Tipe Propeler "an perhitungan tekanan
Tip+ = B4 3 4!
7 = #!! rpm
&#G 7 = 64& rpm
J = %.!## m
!.65!
P$J = .!!!
T = 5 m sarat kapalC
? = *.2 m tin<<i poros prop+l+r (ari 9as+lin+ (ata TR I R+n*ana arisC
T 3 ? = %. m
) = 'tin<<i <+lom9an<-
=
= !.6%! m
T 3 ? C N ) 'tin<<i p+rmukaan air (i atas sum9u poros prop+l+r-
= %. N !6%!
= %.#%! m
't+kanan )i(rostatik air laut pa(a sum9u poros prop+l+r-
=
= %8%.5
+ = !!! 't+kanan atmos,ir-
't+kanan )i(rostatik (i <aris sum9u prop+l+r-
= %8%.5 N !!!
= %&%.5
B. Angka Kavitasi Burril
an Lamm+r+n p. 66 i<.%9C
= 4.5%5
u =
= '&#G7 (alam rotation p+r s*on(-
== .565 m$s
2p+si,ikasi m+sin 1an< m+n(+kati k+9utu)an rp$ (an "a?a0
ηo = +,isi+nsi prop+l+r notasi pa(a P7A II =η
p pa(a an Lamm+r+nC
pit*) ratio =Ho$J pa(a an Lamm+r+nC
!.#5G x Lpp
!.#5G x 84
) =
P) =
) x γ
%#%! x !5
k<$m
k<$m
Po 3 + = P
) N +
k<$m
@ = + N u
+ = speed of advance in m$sC
m$s '=@a-
speed of rotation at 0.7R in m$sC
π x &#G7 $6! x !.8J
π O 64$6!C x !.8 x %!!C
σ o= P
o−e
2V 2
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= 4.5%5 N 4.6#
= 45!4.564 .565
= !4.485
Maka an<ka kaitasi Burril0
= !.!!6
Jari an<ka kaitasi Burril maka (i(apatkan0
!.!!6
!.&& 'li)at an Lamm+r+n i<. %9 <ra,ik untuk M+r*)ant prop.
All t1p+ s+*tions BurrilC-
= !%4.#% k<
= !.!4#
ntuk prop+l+r tip+0 B4 3 4!
i<. ! p. 8%F s+9a<ai 9+rikut0 maka nilai a$ (+n<an m+n<<unakan Ean Lamm+r+n
a $ = !.4! 'kar+na p+m9atasan kura i<. % (an ,ormula 8C
an Lamm+r+n p.%#-
+.42:
.45
Karena )p@)p $aka propeler ini $e$enuhi ui kavitasi
@ = + N u
ζ = !5 k<$m%C $ &.8 m$sC
k<.s.m34
C. Ui Kavitasi Per'an"ingan nilai )p "an )
p@
σo =
t+ =
m ' proected blade area-
'an Lamm+r+n p. ## Ho$J = pit*) ratio-
)p@ 1 $+
)p 1 $+
σ o= P
o−e
2V 2
=13 ,028 .938
104 . 485
2×34017 .286
! e=S / F
p
2V
2
F p=S
2V
2! e
S= DHP×75×η
o
×1.025
V a
=570×75×0 .635×1.025
8.389
F p=6447.328
104.485
234017.286×0.199
F p' =
F a
F
"
4 D2(1.067−0.229
H o
D )
F p ' =0.400 "
47.405
2 (1.067−0.229×0.815)
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V. U>I KEKUATAN DAUN PR<PE!ER
R+,+r+nsi 1an< (i<unakan a(ala) Ean Lamm+r+n pp. 6&#%F.
(i luar poton<an ini l+9i) k+*il s+*ara lini+r Ean Lamm+r+n p.#! para<rap) F.
'an Lamm+r+n p.#!-
= #!.!!! P$J = C
= %! $ 4
= 56.5 HP
7 = revolutions per minute
= #!! rpm
J == %5! $ !.%!48
= !.!&6 ,t
length of the blade element at 0.!R
!.8# J
=
= !.6#% m
#6.!8 O !# $ !%!48 'an Lamm+r+n Ta9l+ 8 p. !4-
= .68! ,t
= .##4 $ %5!
!.546
=
= !.!45
1 :32.://
s$l =
==
= !.%
A. Perhitungan $a9i$u$ co$pressive stress 7C8 "an tensile stress 7
T8
P+r)itun<an k+kuatan (aun prop+l+r )an1a (i)itun< pa(a !.R kar+na t+<an<an stressC 1an< t+r;a(i
2/ = compressive stress El9s$inF
/ = ko+,isi+n t+r<antun< (ari nilai pitch ratio (i(apat (ari Ean Lamm+r+n i<. 8!F.
P = horse power per screw blade
screw diameter in E,++tF
* x 9 = l!.R
$ J
l!.R
=
'(ili)at (ari Ean Lamm+r+n Ta9l+ 8 p.!4F s+9a<ai #ungsi "ari l.3R
-
l!.6R
= 'untuk a$ = !.4!-
!.8# x %5!
l!.R
=
* x 9 =
τ = si $ J 'the blade"thickness ratio at the center of the screw shaft -
si = !.!45 x J
!.!45 x J$J
l'sin+
2T = tensile stress in El9s$inF
blade thickness ratio at !.R
!.!%66x
J!.!%66 x %5!
SC =C 1⋅ P1
# ⋅ D3
1
$⋅%⋅! 2
SC =1270×142.5
1800×8.2713
1
(0.546)×0.0452
ST =SC (0.666+1.17 LC &
)
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L (an / =
P$J = '=nilai O )asil p+r)itun<an-
P$J = !.8!!
P$J = !.&!!
7ilai 1 =
=
Jari Ean Lamm+r+n Ta9l+ p. #!F (i(apatkan0
?
P$J !.&!! !.8!! *.
.#L$/ !.#54 !.#84 .5+4
.4!! .!! +.3
%.58! %.#4! :.4+
!.54 !.54 .*/4
Maka 0
1 +53.**
= 55.!!! 'an Lamm+r+n p.#-
J = !.!&6 ,t
7 = #!! rpm
!.54 'an Lamm+r+n Ta9+l p.#! )asil int+rpolasi-
i = rake ratio
=
=
= !.!88
!.!45.6!! 'an Lamm+r+n Ta9+l p.#! )asil int+rpolasi-
ko+,isi+n 1an< t+r<antun< (ari pitch ratio
P+r)itun<an ko+,isi+n L / ϕ4 ϕ
5 ϕ
i (ari Ean Lamm+r+n Ta9l+ p.#!F0
:untuk m+n(apatkan nilai antara (i<unakan m+to(+ int+rpolasi lini+r.
'=nilai O-
'=nilai O-
L / ϕ4 ϕ
5 atau ϕ
i
7ilai 1 = 'L / ϕ
4 ϕ
5 atau ϕ
i -pa(a P$J=!.8!!
7ilai 1 = 'L / ϕ
4 ϕ
5 atau ϕ
i -pa(a P$J=!.&!!
!.5! 131
C N 1
1
1
ϕ4
ϕ5
ϕi
T 1 4586# !.666N!.#4x!.&C
l'sin+
B. Perhitungan e9tra co$pressive stress 7C@
8 "an e9tra tensile stress 7T@8
δ = material specific weight El9s$,t%F
l9s$,t%
ϕi =
tan ε $
tan !o $ 'ε = su(ut rak+ = !o untuk a<+nin<+n s+ri B4-
τ =ϕ4 =
(− (1
(2− (
1
=
)− )1
)2− )
1
)=( (− (1 (2− (
1
( ) 2− )1))+ )1=(
0.815−0.8
0.9−0.8 ( )2− )
1))+ )1
SC ' =δ ⋅ D
2⋅ #
2
106
⋅ϕ*
(
*
! ⋅ϕ
4−1
)
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Maka 0
1 25/*.+45
%.4! 'an Lamm+r+n Ta9+l p.#! )asil int+rpolasi-
9 =
= !.6#% m
= .!8 ,t
9 = %% $ !66
= !.&
1 *:5/4+.//3
C. Pe$ilihan 'ahan propeler
Total *ompr+ssi+ str+ss0
= 4586# N 548!
1 25,52.3+
Total t+nsil+ str+ss0
= %4458&4 N #644#
1 *:5,*,.333
Maka 9a)an 1an< (i<unakan untuk prop+l+r a(ala) s99.0
+nis = man<an++ 9ron+
T+nsil+ str+ss =
>i+l( point =
?lon<ation = !5CG
Alloa9l+ str+ss =
'an Lamm+r+n Ta9l+ %a p.# p. #%-
l'sin+
ϕ5 =
lmaO
$J
lmaO
= l!.6R
l'sin+
C 1 2
/ N 2
/
l'sin+
T 1 2
T N 2
T
l'sin+
&!!!!!!!!!C l9s$in
%5!!!4%!!!C l9s$in
6!!!C l9s$in
' l9$in = !.!#!% k<$*m-
SC ' =525×8.271
2×1800
2
106
⋅0.154(0.0880.045⋅2.300−1)
ST ' =525×8.271
2×1800
2
106
⋅0.154( 23 0.088
0.045⋅2.300+
0.088
0.2193.660+1)
ST ' =δ ⋅ D
2⋅ #
2
106
⋅ϕ*( 23⋅*! ⋅ϕ4+ 1
% ' ⋅ϕ
5+1)
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VI. PERENCANAAN BENTUK DAUN PR<PE!ER
kuran3ukuran (aun prop+l+r m+rupakan ,un<si (ari pan;an< +l+m+n
maksimum 1aitu pa(a !.6R untuk a$ = !.4!C Ean Lamm+r+n p. !4 Ta9l+ 8F
J = %.!!! m
!.8# J
=
= !.656 m
= 656.!! mm
A. Ta'el panang ele$en "aun
r$R Pan;an< total
!. &.8 &.45 46.&! %!#.# #6.!8 4&&.6
!.% %%.% 8.6 5.64 %45.%# 85.&6 56%.&8
!.4 %#.%! 44.#% 56.% %6&.5 &%.6 64.4
!.5 4!.#8 6#.56 5#.6! %##.& &8.%8 645.4#
!.6 4%.& 88.6 56.!8 %6#.&4 !!.!! 656.!!.# 46.68 %!6.# 5.4! %%#.4 &8.!8 64%.5!
!.8 48.%5 %#. 4.65 #%.# &!.!! 5&!.4&
!.& 4#.!! %!8.%# 5.%5 66.% #.%5 4#4.6&
r$R T+9al (aun maksimum arak or(inat maksimum (ari L?
GJ arak mmC
!. %.66 !&.8! %5.!! #4.#
!.% %.4 &#.! %5.!! &#.%&!.4 .8 84.6! %5.!! 4.&8
!.5 .4! #.!! %5.5! &.4
!.6 .&8 5&.4! %8.&! 55.
!.# .56 46.8! 44.%! 85.!#
!.8 .4 %4.! 4#.&! 8.84
!.& !.# .6! 5!.!! %#.%4
C. Ta'el "istri'usi pitch
= %!!!.!!! mm
r$R Pit*) mmC
!. 8. 466.!! %&.48
!.% 88.# 66.!! 4%.5
!.4 &5.! 85!.!! 45%.5&
!.5 &&. .!! 4#%.65
!.6 !!.! %!!!.!! 4##.46
!.# !!.! %!!!.!! 4##.46
!.8 !!.! %!!!.!! 4##.46
!.& !!.! %!!!.!! 4##.46
l!.6R
=
!.8# x %5!
Jari ℄ k+ T? Jari ℄ k+ L?
Gl!.6R
LT?
mmC Gl!.6R
LL?
mmC Gl!.6R
LTQT
mmC
'Gl!.6R
li)at Ean Lamm+r+n Ta9l+ 8 p. !4F-
' ℄=*+nt+r lin+ T?=trailin< +(<+ L?=l+a(in< +(<+-
B. Ta'el kete'alan "aun F#ungsi7D8G H arak or"inat $aksi$u$ "ari !E F#ungsi7panang potongan8G
tmaO
mmC GLTQT
'GJ GLTQT
li)at Ean Lamm+r+n Ta9l+ 8 p. !4F-
Ho $ J =
Ho = x %5! O !!!
GHo Ho$π mmC
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D. Ra"ius "ari hi"ung F#ungsi7D8G
r$R GJ
!. !.5 !.!!%
!.% !.!5 !.!!%
!.4 !.!&5 !.!!%
!.5 !.!85 !.!!%
.3 !.!#! !.!!
!.# !.!55 !.!!
!.8 !.!4! !.!!
!.& !.!4! !.!!
!.&5 !.!4! !.!!
TIP !.!4! !.!!
E. Ta'el or"inat=or"inat "ari $aksi$u$ or"inat
r$R BACK
Trailin< ?(<+ L+a(in< ?(<+!!G 8!G 6!G 4!G !G !G 4!G 6!G 8!G &!G &5G !!G
!. 3 58.58 #&.## &5.4 !5.&! !8.6 !%.#6 &5.5% 8.6& #!.66 6.5% 3
!.% 3 4&.5 6&.6! 84.%# &4.!& &5.64 &.%# 8%.4! #!.4# 6!.&! 5%.%6 3
!.4 3 4!.%5 5&.4% #%. 8.!6 8%.!8 #8.8& #.% 5&.56 5!.8& 44.6 3
!.5 3 %.5 4&.5 6.&& 6&.8! #!.6% 66.5% 5&.6 48.#4 4!.&! %4.&& 3
!.6 3 %.88 %&.8& 5!.#% 5#.5! 58.# 54.! 4#.% %#.#8 %.! 5.#5 3
!.# 3 8.44 %.% %&.#% 45.% 45.68 4.56 %5.!5 6.68 !.6& 6.%8 3
!.8 3 4.!! %.& &.# %%.!# %%.# &.# %.5! 6.5! .8 8.#! 3
!.& 3 &.#5 5. 8.#& !.&5 !.&5 8.#& 5. &.#5 6.5! 4.#5 3
)ACE
Trailin< ?(<+ L+a(in< ?(<+!!G 8!G 6!G 4!G !G !G 4!G 6!G 8!G &!G &5G !!G
!. %.&4 &.&8 .&# 5.&8 .#! !.4& .5% 6.48 4.## .& 8.## 4%.&
!.% 4.64 .86 5.64 .65 3 !.!5 .6 4.4# !.55 6.!& .58 %6.5!
!.4 5.! 5.5 .# 3 3 3 !.5 .4 6.6! !.58 5.4 &.&
!.5 6.44 .6 3 3 3 3 3 !.5! %.! 6.!8 &.58 .8&
!.6 3 3 3 3 3 3 3 3 !.48 .64 4.&& 4.55
!.# 3 3 3 3 3 3 3 3 3 !.& .5 #.5
(ari masin<3masin< poton<an Ta9+l @I.BC satuan = mm-
R 7Q2?
mmC
'GJ li)at Ean Lamm+r+n Ta9l+ 8 p. !4F-
'or(inat (in1atakan (alam p+rs+ntas+ (ari k+t+9alan maksimum or(inat maksimumC
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VII. PERENCANAAN DIMENI B< PR<PE!ER
R+,+r+nsi0
: /o. Pu9lis)+rC Lt(. Lon(on &6&
EF +rmanis*)+r Llo1( Rul+s &&8
J = %.!!! mBa)an = man<an++ 9ron+
Maka 0
'P7A II p. 86-
=
= !.5! m
*&/ *&* 'QBri+n p. %! : i<. 8.6-
= .!
=
= !.55 m
.,/ .2
= !.85
=
= !.46 m
*., +.= .!!
= !.54% $
= !.5 m
*., +.4
= .8!
=
= !.&! m
.:
=
= !.# m !.%5#
.+5,
.5/
= !.!& m
EF QBri+n T.P. The Design o# Marine cre0 Propeller Hut*)inson
JB = !.6# x J
!.6# x %5!
DB)
DB 1
⇔JB = .! JB
.! x !.54%
DBA
DB 1
⇔JBA
= !.85 JB
!.85 x !.54%
DBD 1
⇔J2 = J
B $
!BD
1
⇔LB = .8! x J
B
.8! x !.54%
!N!
B 1
⇔L 7
= !.%! x LB
!.%! x !.&##
tR 1 $ '(iran*an< li)at <am9ar 9+sar-
tBtR 1
⇔tB = !.#5 x !.#8
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.5/
= !.!& m
.5/ 'rak+ = !
*. 'rak+ = 5
Maka untuk 'rak+ = !
O =
= !.&#
.2*5
= !.55 m
VIII. PER(ITUN6AN MUR PEN6IKAT
.:/ m !.#5 !.55
!.%5!" 1 !.! m
= +* $$
= !.!
= !.!6 m
1 +3.+/ $$
Panang $ur 1 (
= +* $$
Panang ulir 1 (
= !
= 4+ $$
r)t
R 1
⇔r = !.#5 x !.#8
rBt
R 1 o-
rBtR 1 o-
o- (+n<an int+rploasi (i(apatkan0
!$5C x 3!.#5C N !.#5
'O = r B$t
R -
rBt
R 1
⇔r B = !.&# x !.#8
Jiam+t+r ulir luar ≤ 6!G (iam+t+r konis
∅konis
=
6!G∅konis = 6!G x
∅
inti 1 (
x
x
(− (1
(2− (
1
=
)− )1
)2− )
1
(−0.75
1−0.75=10−0
15−0
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IJ. UKURAN PAAK
Pan;an< pasak pC0
p =
= !.5
= !.%% m
= %% mm
Luas 9i(an< <+s+r AC0
A =
= !.5
= !.!6
= 5688
L+9ar pasak 9C0
9 = A $ p
= 5688 $ %%
= 5!. mm 5.!5
ari3;ari u;un< pasak rC0
r =
= 5
= %.%#5 mm
T+9al pasak tC0
t =
= 5 $ 6
= 4.8%%%% mm 't+9al pasak 1an< masuk k+ (alam poros prop+l+r-
J. BAUT PEN6IKAT TUTUP B<
umla) 9aut p+nutup (ir+n*anakan0
Z = 8 9aut
Jiam+t+r 9aut0
( =
BHP = !!! HP 'li)at Ba9 I@. ;i Kaitasi-
7 = #!! rpm li)at Ba9 I@. ;i Kaitasi-
J =
= !.46 m 'li)at Ba9 @II-
= 46 mm
48!
Maka 0
( =
= 4 mm
.5 x J2
.5 x 'J2 li)at Ba9 @II-
!.5 J2
!.5 x
m
mm
!.!5 J2
!.!5 x
J2 $ 6
6 BHP z !6 $ 7 z Z z J z R mCC!.5
JBA
R m = 7$mm ',aktor k+kuatan 9a)an li)at L &&8 /)apt+r I Hull 2tru*tur+
2+*tion .B.. R m = 4!! 5! 7$mm-
6 !4! z !6 $ 8! z 6 z .% z 45!CCC!.5
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7ilai asli (ari Ean Lamm+r+n Ta9l+ 8 p.!4F0
r$R BACK
Trailin< ?(<+ L+a(in< ?(<+
!!G 8!G 6!G 4!G !G !G 4!G 6!G 8!G &!G &5G !!G
!. 3 5%.%5 #.65 86.&! &6.45 &8.6! &4.5! 8#.!! #4.4! 64.%5 56.&5 3
!.% 3 5!.&5 #.6! 86.8! &6.8! &8.4! &4.!! 85.8! #.5! 6.65 54.&! 3
!.4 3 4#.#! #!.5 86.55 &#.!! &8.! &%.5 84.%! #!.4! 6!.5 5.! 3
!.5 3 4%.4! 68.4! 86.! &6.&5 &8.! &.4! 8.%! 6#.#! 56.8! 48.6! 3!.6 3 4!.! 6#.5 85.4! &6.8! &8.! &.5 #&.%5 6%.6! 5.! 4%.%5 3
!.# 3 %&.4! 66.&! 84.&! &6.65 &#.6! 88.8! #4.&! 5#.!! 44.! %5.!! 3
!.8 3 4!.&5 6#.8! 85.%! &6.#! &#.!! 85.%! 68.#! 48.5 %4.55 5.45 3
!.& 3 45.5 #!.!! 8#.!! &#.!! &#.!! 8#.!! #!.!! 45.5 %!.! .!! 3
)ACE
Trailin< ?(<+ L+a(in< ?(<+
!!G 8!G 6!G 4!G !G !G 4!G 6!G 8!G &!G &5G !!G
!. %!.!! 8.! !.&! 5.45 .55 !.45 .%! 5.&! %.45 !.%! 6.! 4!.!!
!.% 5.%5 .! 5.8! .#! !.!5 .%! 4.6! !.85 6.55 .! %#.55
!.4 #.85 6.! .5! !.%! .65 #.8! .5! #.&! %4.5!
!.5 8.&5 .#5 !.#! 4.%! 8.45 %.%! %!.4!!.6 !.8! 4.45 8.4! 4.5!
!.# !.4! .45 6.!5
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VI. PERENCANAAN BENTUK DAUN PR<PE!ER
kuran3ukuran (aun prop+l+r m+rupakan ,un<si (ari pan;an< +l+m+n
maksimum 1aitu pa(a !.6R untuk a$ = !.4!C Ean Lamm+r+n p. !4 Ta9l+ 8F
J = %.6# m
!.8# J KA!A 1 * % ,
=
= !.8!% m KA!A 1 * % / 'Pit*) Jist-
= 8!.848 mm
A. Ta'el panang ele$en "aun
r$R Pan;an< total
!. &.8 +:.2: 46.8& :,.43 #6.!# 3+.4
!.% %%.% +5.:: 5.#5 4:.*5 86.!# 5./
!.4 %#.%! :./2 56.%4 43.*2 &%.64 53.5,
!.5 4!.#8 ::.44 5#.66 45.+4 &8.44 ,.3,
!.6 4%.& :3.+ 56.! 4/.22 !!.! ,+.*!.# 46.68 :,.+, 5.%# 4+.*/ &8.!5 ,.44
!.8 48.%5 :2.3/ 4.# :4.*3 &!.!6 5:.,*
!.& 4#.!! :,.// 5.%& +.52 #.%& /2.:4
r$R T+9al (aun maksimum arak or(inat maksimum (ari L?
GJ arak mmC
!. %.66 *:.5: %5.!! +*.,4
!.% %.4 *+.*/ %5.!! +4.35!.4 .8 *./, %5.!! +3.,5
!.5 .4! 2. %5.5! +,.34
!.6 .&8 5.4: %8.&! :*.2
!.# .56 /.,/ 44.%! :/.3:
!.8 .4 4.+, 4#.&! :/.:3
!.& !.# +.5 5!.!! +2.35
C. Ta'el "istri'usi pitch
= %6#.!!! mm
r$R Pit*) mmC
!. 8. 42:.+ 5,./ 4&.!6!
!.% 88.# /:+.+ ,4.5 5.&%&
!.4 &5.! /5. 2.5+ 56.6&&
!.5 &&. /2/.+ 24.5: 5&.!6
!.6 !!.! 3. 2/.42 5&.68%
!.# !!.! 3. 2/.42 5&.68%
!.8 !!.! 3. 2/.42 5&.68%
!.& !!.! 3. 2/.42 5&.68%
Fkala *%/G
Fkala *%*G
l!.6R
=
!.8# x .46!
Jari ℄ k+ T? Jari ℄ k+ L?
Gl!.6R
LT?
mmC Gl!.6R
LL?
mmC Gl!.6R
LTQT
mmC
'Gl!.6R
li)at Ean Lamm+r+n Ta9l+ 8 p. !4F-
' ℄=*+nt+r lin+ T?=trailin< +(<+ L?=l+a(in< +(<+-
B. Ta'el kete'alan "aun F#ungsi7D8G H arak or"inat $aksi$u$ "ari !E F#ungsi7panang potongan8G
tmaO
mmC GLTQT
'GJ GLTQT
li)at Ean Lamm+r+n Ta9l+ 8 p. !4F-
Ho $ J =
Ho = !.8!5 x .5
GHo Ho$π mmC
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D. Ra"ius "ari hi"ung F#ungsi7D8G
r$R GJ
!. !.5 !.!!4
!.% !.!5 !.!!4
!.4 !.!&5 !.!!%
!.5 !.!85 !.!!% FN<T scale"G
.3 !.!#! !.!!%
!.# !.!55 !.!!
!.8 !.!4! !.!!
!.& !.!4! !.!!
!.&5 !.!4! !.!!
TIP !.!4! !.!!
E. Ta'el or"inat=or"inat "ari $aksi$u$ or"inat
r$R BACK
Trailin< ?(<+ L+a(in< ?(<+!!G 8!G 6!G 4!G !G !G 4!G 6!G 8!G &!G &5G !!G
!. 3 5.:+ 2.25 **.2: *:.+4 *:./: *+.25 **.24 *.+* ,.,: 5.,+ 3
!.% 3 3.*2 ,.5 *.// **.53 **.23 **.4+ *.4+ ,.,* 5.3* 3.35 3
!.4 3 /.4 5.4: 2.*/ *.+3 *.:, 2.,3 ,.2* 5.44 3.:3 /./+ 3
!.5 3 :.2* 3.*3 5.5/ ,.5: ,.,: ,.:+ 5.4* 3.2 /.** 4.:5 3
!.6 3 +.2, 4.22 3.:4 5.*2 5.+, 3.5, /.,2 4.5+ :.,, :.++ 3
!.# 3 +.: :.2* 4.25 /.3/ /.5* /.*2 4.:, :.:: +./2 +./ 3
!.8 3 *.5/ +.2 :.3/ 4.*: 4.*/ :.3/ +.24 +.3 *.4, *.2 3
!.& 3 *.++ *.,2 +.:/ +.3+ +.3+ +.:/ *.,2 *.++ .,* ./2 3
)ACE
Trailin< ?(<+ L+a(in< ?(<+!!G 8!G 6!G 4!G !G !G 4!G 6!G 8!G &!G &5G !!G
!. 4.*+ +./ *./ .5/ .+* .3 .:+ .,* *.,/ +.52 :.3 /.42
!.% :., *.4, .5 .+* 3 .* .*3 ./3 *.:+ +.* +.5 4./3
!.4 *.,2 .33 .*3 3 3 3 .: .+, .,+ *.:+ *.,2 :.3/
!.5 .,* .*3 3 3 3 3 3 .3 .:2 .53 *.+ +.54
!.6 3 3 3 3 3 3 3 3 .3 .:: .3+ *.,+
!.# 3 3 3 3 3 3 3 3 3 .+ .*4 .24
(ari masin<3masin< poton<an Ta9+l @I.BC satuan = mm-
R 7Q2?
mmC
'GJ li)at Ean Lamm+r+n Ta9l+ 8 p. !4F-
'or(inat (in1atakan (alam p+rs+ntas+ (ari k+t+9alan maksimum or(inat maksimumC