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Matematik Tambahan Kertas 1 2 jam Ogos 2011

BAHAGIAN PENGURUSAN SEKOLAH BERASRAMA PENUH DAN SEKOLAH KECEMERLANGAN

KEMENTERIAN PELAJARAN MALAYSIA

PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN MALAYSIA 2011

ADDITIONAL MATHEMATICS

Paper 1

Skema Pemarkahan ini mengandungi 6 halaman bercetak

MARKING SCHEME

2

PERATURAN PEMARKAHAN- KERTAS 1

No. Solution and Mark Scheme Sub

Marks

Total

Marks

1(a)

(b)

2

3

B1:

13

m

m

2

1

2

1

3

2(a)

2

3x

1

3

(b)

2

5

B1: k(3) = 2

2

3 a = 6 and b = -11

B2: a = 6 or b = -11

B1: bx

axfg

)2

5()(1

3 3

4

2

1,5 xx

B2:

(2 1)( 5) 0 orx x

B1: 0592 2 xx

3

3

5

1 11p

B2 : ( 1)( 11) 0p p

B1:

2( 1) 4(3)( 1) 0p p

3

3

6(a)

(b)

(c)

m = 1

x = 1

(1, 3)

1

1

1

3

5 1

2

1 11

3

7

2

5x

B2: 1

2( 2) 4( 1) or 2 4 42

x x x x

B1:

12( 2)

24( 1)

15

5

x

x

3 3

8

1

3x

B3: 3 23 9x

B2: 2

9log (3 ) 2x x

B1: 9

9

log 3

log 81

x (for change base)

4 4

9(a)

(b)

h = 1

B1: 5h 1 (2h – 4 ) = 6h + 4 – (5h – 1)

1460

B1: 20

202(16) 19(6)

2s

OR 23 3s s 23 3

2( 2) 22(6) 2( 2) 2(6)2 2

OR 20

2016 130

2s

2

2

4

10

1

3r and a = 4

B3 : 1

3r or a = 4

B2 : 8

3(1 )(1 )3

r r

B1 : 3

1

r

a

or 3

8 ara

4

4

11

42300

B2 : 36

362(300) 35(50)

2S

B1 : 36 or 300 or 300,350,400S a

3

3

4

12

2and 4

3q p

B2: 2

or 43

q p

B1: 21 3 0 3or

6 4 2

pxy x

q q

3 3

13(a)

(b)

t = 1

B1: 4

1

80

02

t

y = 4x + 2

B1: Using m1• m2 = -1 and m2 = 4

2

2

4

14 m = 1 and n = 3

12 :

3

( 4) (4) (2) (6)1: 2 or 3

mB

n

n m n mB

n m n m

3

3

15(a)

(b)

x3 + y6

2x + y2

2 1B1 : (3 6 ) or (6 3 ) or equivalent

3 3x y y x

1

2

3

16(a)

(b)

8 4i j

1 1

(8 4 ) or (2 )80 5

i j i j

B1:22 48 AB = 80

1

2

3

5

17(a)

(b)

r = k =10

B1: 21(0.8) 40

2r

72 cm

)8.0(30Sor 10(0.8) :1 CD ABSB

2

2

4

18

65

33

B1 : 5

3sin B OR

13

5cos A

2

2

19

2

13

B2 : )5(2

1

2

2

x

B1 : 1

2

1

2

)( dxxfdxx OR 2

2x OR

1

2

5)( dxxf

3 3

20 27

B2 : 2 2 3 2 3 3( 1) (9( 1) )(( 1) 4) (( 1) 4) (2( 1))

B1 : 2 2 3 2 3 3(9 )( 4) ( 4) (2 )x x x x x or equivalent

3

3

21(a)

(b)

5

B1 : 450 90 0h

1125

2

1

3

6

22(a)

(b)

p = 9

8

B1 : 2 2 2 2 2

2 23 7 9 5 1(5)

5

1

2

3

23(a)

(b)

20

240

B1 : 5! X 2!

1

2

3

24(a)

(b)

1

2

5

12

B1 : 1 2 3 1

4 3 4 3

1

2

3

25(a)

(b)

0.1515

58.09

B2 : 55

1.033

k

B1 : z = 1.03

1

3

4