SPM MATHS TRIAL PAPER 2 SPI 2013 (Marking Scheme)

7/29/2019 SPM MATHS TRIAL PAPER 2 SPI 2013 (Marking Scheme)

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PEPERIKSAAN PERCUBAAN

SIJIL PELAJARAN MALAYSIA 2013

MATHEMATICSMATHEMATICS

PAPER 2 1449/2PAPER 2 1449/2

ANSWERS


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Peraturan Pemarkahan Matematik Kertas 2 1449/2

PEPERIKSAAN PERCUBAAN SPM SPI 2013

MARKAH MAKSIMUM BAGI KERTAS INI : 100 MARKAH

No Peraturan Pemarkahan Markah

1

K1

N2

3

2 Identify UMP

PM= 22 65 +

tan UMP=8102.7

9

UMP= 49o 2

1

1

1

1 4

3 3x2 11x 4 = 0

(3x + 1)(x 4) = 0

x = 4,3

1

1

1

1, 14

4 6p + 4q = 6 or 12p 6q = 16 or

6

38 qp

+= or

3

86 =

pq or equivalent

7q = 14 or 21p = 7

1

1

2

Straight line y = 12 drawn

correctly

Region shaded correctly

Note:

Region satisfying any 2

inequalities award 1M

Deduct 1 markif y = 12 is a

solid line

x

y

0

y = 12


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q = 2 or3

1=p

1, 1 4

5 Vhemisphere =777

7

22

3

2

Vcube = 5 5 5

7777

22

3

2 5 5 5

593.67 or3

2593

1

1

1

1 4

6 (a)

6(b)

6(c)

(i) Some

(ii) All

Ifx > 4 then x > 7.

False

Premis 1 : The total of interior angle of rectangles is 360o

.

1

1

1

1

15

7(a)

7(b)(i)

(ii)

{(2,3), (2,4) (2,5), (2,6), (3,2), (3,4), (3,5),(3,6), (4,2), (4,3), (4,5), (4,6), (5,2),

(5,3), (5,4), (5,6), (6,2), (6,3), (6,4), (6,5)}

{(4,2), (4,3), (4,5), (4,6)}

20

4@

5

1

{(2,4), (2,6), (3,5), (4,2), (4,6), (5,3), (6,2), (6,4)}

208 @

52

2

1

1

11

5

8(a)

8(b)

)14()14.3()2(360

240 or )7()14.3()2(

2

1

14 + 14 + )14()14.3()2(360

240+ )7()14.3()2(2

1

94.59

)14)(14()14.3(360

240or )7)(7()14.3(

2

1

)14)(14()14.3(360

240 )7)(7()14.3(

2

1

333.36

1

1

1

1

1

1 6

9(a)

9(b) (i)

16

106

016

1

1

3


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9(b)(ii)

4

)3()16(2

1+u + 16(3)

u = 12

1

1

1 510 (a)

10(b)

(b)

y = 4

3

4

610

016=

=m

y =3

4 (6) + c

y =3

4 x + 12

y - intercept ofRS= 12

1

1

1

1

1 5

11(a)

(b)

m =71 (7 seen, 1 mark)

n = 1

=

77

3

1

1

2

q

p

21

1

1

1

1 7

4


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7

7

2

1

1

3

2

1

q

p

p = 2

q = 3

12 (a)

12(b)

12(c)

(i) ( 5, 7 )

(ii) ( 3, 0 )

(iii) ( 1, 4 )

(i) G Rotation180o centre ( 0, 5)

(ii) H Enlargement

Scale factor 3

Centre Q( 2, 1 )

32 area ABCDE

144 area ABCDE = 32 area ABCDE

Area ABCDE = 14.4

1

1

2

11,1

1

1

1

1

11

12

5


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13(a)

13(b)

13(c)

13(d)

x 2 0.5

y 6 24

Refer graph

Uniform scale and correct axes

All points correctly plotted

Smooth and continuous curve

Note : 1 or 2 points wrongly plotted, 1 mark - 0 mark for curve.

(i) y = 5.0 ------ 6.0

(ii) x = 0.65 ------ 0.75

Liney = 3 2xDraw liney = 3 2x

x = 3.0 ----- 3.5, 1.85 -------- 1.75

1, 1

12

1

1

1

1

1

1, 1 12

14(a)

14(b)

(c)

(d)

Time taken (secs) Frequency Mid point

30 - 39 2 34.5

40 49 4 44.5

50 59 10 54.5

60 69 6 64.5

70 79 12 74.5

80 89 6 84.5

(i) 70 - 79

(ii) 10

(iii)40

)6(5.84)12(5.74)6(5.64)10(5.54)4(5.44)2(5.34 +++++

40

2580

64.5

Refer graphUniform scale and correct axes

Midpoints or upper boundaries forx- axis

6 bars correctly drawn

1. Most students took 70 79 secs to finish the run. OR

2. 12 students took 70 79 secs to finish the run.

1, 1, 1

1

1

1

1

1

1

2

1 12

6


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15(a)

(b) (i)

b(ii)

70 50

Measurements according to actual size.

3

4

5

12

7


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16(a)

16(b)

16(c)

16(d)

70 50

20oS

cos 70o

180 (60) cos 70o3693.82 n.m.

= o70cos60

1026

49.99o

500

49.99o 30o

19.99o @ 20 o

20oE

30

1026

34.2 hrs

1

1

1

11

2

1

1

1

1

1

12

Nota :

JUMLAH MARKAH (100%) :

KERTAS 1(40%) + KERTAS 2 (100%)

Keseluruhan Markah = 100)140

2ker1ker(

+ tastas

Peraturan ini adalah untuk panduan guru sahaja. Jika terdapat kesilapan, sila semak semula dan betulkan

sendiri

Terima Kasih

8


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9

G, PE=PQ=SG

a ukuran betul 0.2 cm dan sudut dibucu segi empat tepat 90 1

25

20

10

5

15

5

4 10 312

X

X

X

X

23

X

X

X

X

x

10

15

y

X

X

X

6

8

10

12

4

2

69.5 79.549.5 59.539.529.5 89.5

Time (secs)

Frequency

0

Answer for Question 14

Answer for Question 13


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SPM MATHS TRIAL PAPER 2 SPI 2013 (Marking Scheme)

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