Pembahasan-statistika i Kelas Xi
6
PEMBAHASAN STATISTIKA KELAS XI 1. Rata-rata = 7+5+ 8+6 +7+8 +7+7 +7+9 +5+ 8 +6+8 14 = 98 14 = 7 2. Median = 7+7 2 = 7 3. Modus = 7 4. Jangkauan = 9 – 5 = 4 5. Mean = 5+6+ 9+6 +5+8 +6+9 +6+10 10 = 7 Median = 6 Modus = 6 6. Mean = 6+4 +5+8 +8+4 +7+6 9 = 6 Median = 6+6 2 =6 Modus = 6 7. Rata-rata = 4( 52 )+6 ( 57)+8 ( 62 )+ 10 ( 67 )+ 8( 72 )+4 ( 77) 40 = 2.600 40 = 65 kg 8. Mo = 64,5+ ( 2 2 +2 ) 5 = 64,5 + 2,5 = 67 9. Kuartil atas = 3 4 x 40 = 30 Q 3 = L 3 + ( 3 4 ∑ f−fK 3 f Q 3 ) i = 69,5+ ( 3 4 .40−28 8 ) 5 = 69,5 + 1,25 1
-
Upload
dilla-naharul -
Category
Documents
-
view
247 -
download
0
description
Pembahasan-statistika i Kelas Xi
Transcript of Pembahasan-statistika i Kelas Xi
PEMBAHASAN STATISTIKA KELAS XI
1. Rata-rata = = = 72. Median = = 73. Modus = 74. Jangkauan = 9 5 = 45. Mean = = 7Median = 6Modus = 66. Mean = = 6Median = Modus = 67. Rata-rata = = = 65 kg8. Mo = = 64,5 + 2,5 = 679. Kuartil atas = x 40 = 30 = = = 69,5 + 1,25= 70,7510. = = 63,2511. a = 1012. = 481.326 + 43 x = 48 ( 27 + x )1.326 + 43 x = 1.296 + 48 x5x = 30x = 613. Data setelah diurutkan:567789101214
Kuartil bawah = = 6,514. Kuartil atas = = 1115. = = 5816. Nilai rata-rata = = = 3217. Modus Mo = = = = 26,218. Media = = = = 2919. Kuartil atas = = = 34,5 + 4,5= 3920. Kuartil bawah = = = 24,5 + 0,75= 25,2521. Simpangan kuartil = ) = ) = 6,87522. Rata-rata data tersebut adalah 7sehingga diperoleh ragam S2, yaitu S2 = = (9 + 1 + 4 + 4 + 9 + 1)= 4,67S = = 2,1623. = 7121 + 8 M = 7 ( 19 + M)121 + 8 M = 133 + 7MM = 1224. = 243x + 9 = 24 . 33x = 72 9x = 2125. = = 7.42026. 240 = 156 + . 1212 = 84 = 727. 6,6 + 6,6 = 0,1 = 2,5 = 2528. Rata-rata = = = = = 6,3Siswa dinyatakan lulus ujian matematika jika nilainya lebih besar dari 6,3.Jadi, jumlah siswa yang lulus adalah 11 + 4 = 15 siswa29. Nilai total kelompok = 50 x 64 = 3.200Nilai rata-rata 49 siswa = = 63,530. Misal:Jumlah siswa laki-laki = aJumlah siswa perempuan = b 65a + 54 b = 58a + 58b7a = 4bb : a = 7 : 4
2
