Skema Sains Trial PMR 2011 MRSM

8/4/2019 Skema Sains Trial PMR 2011 MRSM

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SULIT

55/1 & 55/2

Sains

Kertas 1& 2

Ogos 2011

Peraturan

Pemarkahan

MAKT AB RENDAH SAINS MARA

PEPERIKSAANPERCUBAAN

PEl\lLA.IAt~ MENENGAH RENDAH 2011

:::51 & 55/2

SAINS

Kertas 1 & Kertas 2

PERATURANPEMARKAHAN

UNTUK KEGUNAAN PEMERIKSA SAHAJA

AMARAN

Peraturan Pemarkahan ini SULIT dan Hak Cipta BP~ _lARA.

Kegunaannaya khusus untuk pemeriksa yang berkenaan sahaja.

Sebarang maklumat dalam peraturan pemarkahan ini tidak boleh

dimaklumkan kepada sesiapa. Peraturan pemarkahan ini tidak boleh

dikeluarkan dalam apa-apa juga bentuk media. .

~ _ 11 Hak Cipta Bahagian Pendidikan Menengah MARA SULIT



1 B

2. A

3. B

4. B

5. D

6. e

7. A

8. A

9. e

10. D

A: 10

B: 10

c. 10

S D: 100

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SCIENCE PMR 2011TRIAL PAPER 1

ANSWER SCHEME

1 1 . A

12. B

1 3 . e

14. B

15. B

16. C

17. D

18. B

19. D

20. D

21. A

22. D

23. e

24. B

25. A

26. D

27. B

28. e

29. e

30. e

31. A

32. A

33. e

34. D

35. D

36. e

37. A

38. D

-39. B

40. A



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Science PMR 2011

Trial Paper 2

Answer Scheme55i2(PP)

Question Mark Scheme Sub

Mark Mark

Total

Ia) Able to label J, K and L using the word given.

Answer

b 3

LK J

system Organ tissue

Sistem Organ Tisu

l(b) Able to draw line to match the type of cells with its function

Answer

Allows movement

Membenarkan pergerakan

Sends information in the body

Menghantar maklumat didalam badan

Covers the body surface

Melindungi permukaan badan

5512(PP) ©2011 Hak Cipta BPM

TOTAL 6

SUUT

3



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Total

Mark

Question Mark Scheme Sub

Mark

2(a) Able to mark ( . . . j j correctly for the arrangement of particles in iron nail.

2(b)(i)

2(b)(ii)

2b(iii)

Able to answer what happen to the bulb.

Answer

(The bulb will) lights up.

(Mentol akan) menyala.

Able to give a reason for the answer in 2 (a)(i).

Sample answer

1. (Iron nail! metal) can conduct electricity.

(Paku besi/logam) boleh mengalirkan elektrik.

2. (The electric) circuit is completed.

Litar (elektrik)lengkap

[accept anyone reasonable answer)

Able to give reason what will happen to the bulb if the circuit is

completed.

Answer

(The bulb) does not lights up.

(Mento I) tidak menyala.

2(c) Able to suggest a method to separate a mixture of iron fillings and saud.

Answer

(8y using) magnet

(Den an men unakan) ma net

TOTAL 5

3

55/2(PP) ©20J J Hak Cipta BPM 2 SULIT



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~ Question Mark Scheme Sub

Mark Mark

Total

3(a)(i)

3(a)(ii)

3 (b )

3(c)(i)

3(d)(i)

3(d)(ii)

Able to label the structure of choroid.

Answer

:"==-:";:;~=~~----choroid

Able to state the function of choroid.

Sample answer

1. To prevent reflection / absorb light (in the eye).Untukmenghalangpantulan I menyerap cahaya ( dalam mata)

2. To supply nutrients / oxygen (to the cells of eye)

Untuk membekalkan nutrien loksigen (kepada sel-sel dalam mata)

(accept anyone reasonable answer]

Note: answer for 3(a)(ii) independent with 3(a)(i)

Able to explain what happens to structure K when a person view distant

object.

Answer

(The structure Kbecome) thinner

(Struktur K menjadi) nipis.

Able to state one characteristic of the image formed on the retina.

Answer

(The image formed) is inverted / real/small.

(Imej yang terbentuk) tertonggeng / sahih / kecil

Able to draw stereoscopic field of animal Q

Answer

Noted :must show overlapping area

Able to state the reason

Answer

(The wide field of vision enable the animal) to detect their enemies from all

direction

(Medan penglihatan yang luas) membolehkan haiwan tersebut mengesan

musuhnya dari semua arah

TOTAL 6

2

2

35/2(PP) ©2011 Hak Cipta BPM SULIT



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Question Mark Scheme Sub Total

Mark Mark

4(a) Able to state liquid P correctly

Answer

1. Acidified potassium manganate (VII) solution

Larutan Kalium manganat (VJJ) berasid

2. Acidified potassium dichromate (VI) solution

Larutan Kalium dikromat (VI) berasid

[accept anyone reasonable answer}

4(b)(i)

4(b)(ii)

4(b)(iii)

Able to state the changes of colour P

Answer

1. Purple to colourless/decolourizes

Ungu kepada tidak berwarna

2. Orange to greenJinggaloren kepada hijau


Able to give reason

Answer

1. (The presence of) sulphur dioxide gas

(Kehadiran) gas sulfur dioksida

2. Sulphur dioxide gas (is released)

Gas sulfur dioksida (dibebaskan)


Reject: jernih Iputih

Reject: yellow

Note: answer for 4(b)(ii) dependent with 4(b)(i)

Able to state the conclusion

Answer

Lead sulphide decomposes (upon heating produce metal oxide and sulphur 1 3

dioxide gas)

Plumbum sulfida terurai (ketika pemanasan menghasilkan logam oksida dan

gas sulfur dioksida)

4(c) Able to write the word equation

Answer

4(d)

Lead oxide

Plumbum

oksida

Lead sulphide + oxygen ___.

Plumbum sulfida + oksigen

Able to state the changes

Answer

The colour remains/lunchanged

Warna kekailitidak berubah

5512(PP) ©2011 flak Cipta BPM 4

+ Sulphur dioxide

Sulfur dioksida

1 1

TOTAL 6

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Mark Mark

5(a)(i) Able to state one function of potassium hydroxide pellets.

Answer

To absorb carbon dioxide gas 1

Untuk menyerap gas karbon dioksida

5(a)(ii) Able to state the purpose of keeping the plant in the dark.

Answer

To destarch// to remove starch from the plant I

Untuk menyahkanji II untuk menyingkirkan kanji dari tumbuhan

5( a)(iii) Able to name the solution used to test for the presence of starch

Answer

Iodine 1

Iodin

5(a)(iv) Able to complete Table 6.1

Answer

Leaf in Observation

conical flask

A Colour of iodine solution remains yellowlbrownish

Wama larutan iodin kekal kuning I keperangan 1

B Colour of iodine solution turns to dark bluelblue black

Warna larutan iodine bertukar ke biru gelap I biru 1 5

kehitaman

5(b)(i) Able to name the gas that is collected.

Answer

Oxygen gas 1

Gas oksigen

5(b)(ii) Able to state the how to test the gas in b(i)

Answer

Fact: Use wooden glowing splinter//Insert a glowing wooden. splinter into 1

the test tube

Gunakan kayu uji berbarallMasukkan kayu uj berbara ke dalam m

tabung uji

Explain :. Ignites a glowing wooden splinter.

Kayu uji berbara menyala

5(b)(iii)

Note: Fact .+ Explain

Able to give the disadvantages of the gas correctly

Answer

(Cause) rusting / rust 1 3

(Menyebabkan) pengaratanl karat

TOTAL 8

55/2(PP) ©20I I Hak Cipta BPM 5 SULIT



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Mark Mark

6(a)(i) Able to name component R 1

Answer

Voltmeter

6(a)(ii) Able to state the value of current

Answer

1IR=1/2 + 1 1 3 =5/6 1

R=6/5

1

1=3/6 x 5 =2.5A

6(a)(iii) Able to state what happen when Rand S interchangedAnswer

(The bulbs) do not light up. 1 4

(Mental) tidak menyala.

6(b)(i) Able to compare ammeter reading.

Answer

The ammeter reading in 6.2(a) is smaller than in 6.2(b). (vice versa) 1

Bacaan ammeter di 6.2 (a) lebih kecil dari di 6.2(b). (sebaliknya)

Note: must have comparison

6(b)(ii) Able to explain answer correctly

Answer 1

The wire in diagram 6.2(b) is thicker than wire in diagram 6.2(a) 1Wayar dalam rajah 6.2(b) lebih tebal daripada wayar dalam rajah6.2(a)

Because resistance is lower

Kerana rintangan lebih rendah

6(b)(iii) Able to explain answer correctly

Answer 1

The ammeter reading is higher 1 5

Bacaan ammeter menjadi lebih besar

Copper wire has lower 1 less resistance

Dawai kuprum mempunyai rintangan rendah

TOTAL 9

55/2(PP) ©2011 Hak Cipta BPM 6 SULIT



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Mark Mark

7(a) Able to state the properties of P, Q, Rand S.Answer

Solution Properties

Larutan Sifat

PAcidic

Berasid 1

QAlkaline/ /neutral

Beralkalillneutral I

RAcidic

Berasid I

SAcidic

Berasid 1 4

7(b) Able to classify the solution into two groupsAnswer

Classification Solution

Blue litmus paper turns red P,R,S1

Blue litmus paper remains blue Q1 2

7(c) Able to state the operational defmition for acid

Answer

Acid is shown by the change the substance that change the blue litmus paper 1 1

to red

Asid ialah bahan yang menukarkan kertas litmus biru kepada merah

7(d)(i) Able to compare the difference volume of gas in diagram 7.2(a) and &

7.2(b)

Answer

Volume of gas collected in 7.2(b) is moreihigher/greater than in 7.2(a). 1(vice versa)

lsipadu gas yang terkumpul di 7.2(b) lebih dari 7.2(a).(sebaliknya)


Note: Must compare the volume

7(d)(ii)

Able to state the inference correctly

Answer

1. The volume of gas collected in 7.2(b) is greater than 7.2(a) because acid is 1

added / To increase the conductivity of electricity in distilled water/ To make

water a better conductor of electricity

7(d)(iii) Able to predict the volume gas P

Answer

4 crrr' 1 3

TOTAL 10

55!2(PP) ©2011 Hak Cipta BPM 7 SULIT



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SULIT 55/2(Pt


Mark Mark

8(a)(i) Able to state the difference between sitnation J and K correctly

Answer

Effort insituation J is lower /less than effort ineffort in situation K (or vice 1

versa)

Daya dalam situasi J lebih rendahlkurang daripada daya dalam situasi K

(atau sebaliknya)

8(a)(ii) Able to state the inference correctly

Answer

The effort insituation J is smaller because the effort distance to the fulcrum 1

is further/longer

Daya dalam situasi J lebih kecil kerana jarak daya kefulkrum lebih jauh.

8(a)(iii) Able to state the relationship between the distance and the effort

Answer

The longer / further the distance from the fulcrum, the smaller the effort (or 1 3

vise versa)

Lebih jauh jarak dari fulkrum, lagi kecil daya( atau sebaliknya)

Notes: manipulated variable followed by responding variable

8(b)(i) Able to state the value of force.

Answer

50N 1

5512(PP) ©2011 Hak Cipta BPM 8 SULIT



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8(b)(ii)

8(c)(i)

8(C ) (ii)

8 (c )(iii)

Able to draw the graph

Answer

' 1 p h tor

r ' t i o n s

rri)

- r - - - - - ,Gtal~ S( 'If.if) II .J

I II !

r-lOOI~--4r--~I---r---r--_+---+--~

I I

f Fo~l~, &;a:_Y

f--90 t--.-.~---+--I---l' .1..Transfer. all po int correctly

. 2. smooth curve shape

\ If - - - 5 0 .. . p - - + - - - - - - ¥ - - - i \ ---+---+--+---t---l

~0'-+--+--~\~-4--~-r~.

f--JO~---r--_+--_4~~--r_-+_-+_-~

~K~O~~I--~--4--4~~--~~

s o Dil,tmc. offor"" (em)

I .J.~4m(-)3 0

I i0

j: : 0

Able to state the hyphotesis correctly

Answer

The longer / further the distance of force, the smaller the force (vise versa)

Lebih jauh jarak darifulkrum, lagi kecil daya ( sebaliknya)

Able to state the manipulated and responding variable

Answer

Manipulated variable :distance offorcejarak daya)

Responding variable :Reading of spring balance/force

bacaan neraca spring/daya)

Able to state the defmition operationally

Answer:

Force is shown by the reading of spring balance (when the distance of effort

is difference)

Daya adalah bacaan neraca spring (apabila jarak daya berbeza digunakan)

55/2(PP) ©2011 Hak Cipta BPM 9

1 4

TOTAL 10

SULIT

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Skema Sains Trial PMR 2011 MRSM

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