BAB III 2.Perancanaan Gel Melintang & Memanjang (Ok)
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Transcript of BAB III 2.Perancanaan Gel Melintang & Memanjang (Ok)
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8/19/2019 BAB III 2.Perancanaan Gel Melintang & Memanjang (Ok)
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Perencanaan gelagar melintang
Perencanaan : Mu= 100% x Mu tot = 2549,133 KNm = 2549133000 Nmm
Vu = 100% x Dmax tot= 1132948 N
Koefiien !enam!an" !#ati untu$ & = 1,12
' = 0,9()arat )an" *aru +i!enu*i
Mu ' Mn
Mn = 1,12 - (x - &)
.!er#u =&)1,12' ××
Mu =
2401,120,9
2549133000
××= 1053/090,// mm3 = 1053/,090// cm3
Coba WF 900.300.34.18
(x = 10900 cm3
() = 1040 cm3
x = 498000 cm4
) = 15/00 cm
4
ix = 3/,0 cm
i) = ,5 cm
r = 28 mm = 2,8 cm= 34,0 cm2
* = 912 mm = 91,2 cm
= 302 mm = 30,2 cmtf = 34 mm = 3,4 cm
t = 18 mm = 1,8 cm
Kontro# $e$uatan ter*a+a! $a!aita !enam!an" a#o$ ti+a$ tero$on"6
λf = tf 2×
b = 3,42
2,30
×= 4,44
λ =t
22 r tf h −−=
1,8
8,2-24,3-22,91 −−= 43,//
λP = &)
1/0=
240
1/0= 10,9/3 !e#at a)a!6 λP = Fy
180=
240
180=108,4435 !e#at a+an6
λf = 4,44 λP = 10,9/3------77-$ !enam!an" $om!a$6
λ = 43,// λP =108,4435 77-$ !enam!an" $om!a$6
Pemeri$aan !en"aru* !anan" entan"
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= = 150 cm
! = 1,/ - i) - Fy
E = 1,/ - 11,1 -
240
200000= 333,292 cm
! ≥ a#o$ !a+a ;ona 1 +a#am $on+ii !#ati6
Ma$a Mn = M!
M! = 1,12 - (x - &) = 1,12-10900000-240 = 29299200000 NmmMu Mn Ø
2549133000 - 29299200000- 0,92549133000 23910000
Ma$a IWF 900.300.34.18------ $ Penam!an" untu$ "e#a"ar me#intan"6
Pemeri$aan ter*a+a! "eer
Vu=1132948 N=1132,948 KN = 113,2948 K"
Kn= 5 aumi ti+a$ a+a !en"a$u6
()aratt
h=50,/ < 1,1-
Fy
E Kn--= /1,004$
Vn = 0,-240-912-18 = 233904 N = 23390,4 K"()arat Vu < Ø Vn
1132948 < 0,9- 233904 1132948 < 212/513,77
Perencanaan gelagar memanjang
Vu = 325490 N
Mu = 4080000 N = 4080 KN
Mutu aa > 41 = &) = 240 MPa = 2400 KN?m2
&u = 3/0 M!a = 3/00 KN?m2 ' = 0,9
Syarat yang haru !i"enuhiKoefiien !enam!an" !#ati untu$ & = 1,12 $*uu untu$ !rofi# &6Mu ' Mn
Mn 1,12 - (x - &)
.!er#u =&)1,12'
1000
××
× Mu=
2401,120,9
10004080
××
×
= 181,/95 cm3
Coba WF 900.300.34.18
(x = 10900 cm3 r = 28 mm = 2,8 cm() = 1040 cm3 = 340 cm2
x = 498000 cm4 * = 912 mm = 91,2 cm
) = 15/00 cm4 = 302 mm = 30,2 cmix = 3/,0 cm tf = 34 mm = 3,4 cm
i) = ,5 cm t = 18 mm = 1,8 cm
#ontrol #e#uatan terha!a" #a"aita "enam"ang $balo# ti!a# tero#ong%
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λf =tf 2×
b =
342
302
×
= 4,44 !e#at a)a!6
λ =t
22 r tf h −−=
1,8
8,2-24,3-22,91 −−= 43,// !e#at a+an6
λP = &)
1/0=
240
1/0= 10,9/3 !e#at a)a!6 λP = Fy
180=
240
180= 108,4435 !e#at a+an6
λf = 4,44 λP =10,9/3 ------------$ !enam!an" $om!a$6
λ = 3,// λP =108,4435 777-$ !enam!an" $om!a$6
Mn = M!
M! = 1,12 - (x - &) = 1,12 - 10900 - 240 = 2929920 KNm
Mn @ Mu = M! Ae+u$i @ Mu 2929920- 0,9 @ 4080
23928 @ 4080 ------ $
Pemeri$aan ter*a+a! "eer
Vu= 325490 N= 325,49 KN = 32,549 K"
Kn= 5 aumi ti+a$ a+a !en"a$u6
()aratt
h=50,/ < 1,1-
Fy
E Kn--= /1,004 $
Vn = 0,-240-912-18 = 233904 N = 23390,4 K"
()arat Vu < Ø Vn
325490 < 0,9- 233904
325490 < 212/513,77 $
