Ceramah Math Upsr

7/29/2019 Ceramah Math Upsr

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MATHEMATICS TEACHER

FED UP

DISLIKE

HATE

SCARED

BORING


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CANDIDATES WEAKNESSES

UPSR Candidates Face :

1. Weak of the 4 basic operations


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IMPORTANT KEY WORDS

ADDITIONS

Plus

TotalSum

More than

AmountAltogether

After

Bigger

Jumlah

Hasil TambahLebih banyak

Kesemuanya

Selepas

Lebih besar


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IMPORTANT KEY WORDS

SUBTRACTION

Balance

BeforeTake away

Remaining

Less than

SmallerLeft

The rest

Reduce

Difference

Baki

SebelumDikeluarkan

Baki

Kurang daripada

Lebih kecil

Yang tinggal/baki

Selebihnya/baki

KurangkanBeza


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IMPORTANT KEY WORDS

MULTIPLICATIONTambah berulang

Multiply

TimesProduct

Total

(give one/each theanswer is more than

one)

Darab

KaliHasil darab

Jumlah

(Diberi satuTetapi jwp

Lebih drp satu)


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IMPORTANT KEY WORDS

DIVISION

Tolak berulang

DivideQuotient

Remainder

Share equally

distribution(Give more but

The answer

Each)

BahagiHasil bahagi

Baki dari proses bahagi

Kongsi bersama

diagihkan(Beri lebih ttp jwp untuk

Satu)


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Basic Operations1 9 + 7 =2 5 X 6 =3 18 9 =4 4 X 5 =5 24 6 =6 0 X 8 =7 13 9 =8 16 4 =9 8 + 5 =10 9 5 =

16309

204044

134


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Basic Operations11 30 6 =12 6 X 0 =13 32

8 =

14 0 + 9 =15 16 9 =16 7 X 8 =17 49 7 =18 9 + 7 =19 8 X 9 =20 17 8 =

5049756716729


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Basic Operations21 56 7 =22 8 X 5 =23 16 4 =24 9 + 4 =25 12 7 =26 7 X 6 =27 36 6 =28 8 + 3 =29 9 X 3 =30 17 9 =

8404

13542611278


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Basic Operations31 5 + 4 =32 4 X 6 =33 10 7 =34 4 X 9 =35 30 6 =36 3 X 8 =37 14 9 =38 45 9 =39 3 + 8 =40 11 6 =

9243

3654

55

115


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CANDIDATES WEAKNESSESUPSR Candidates Face :


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1 marks-5 questions

- + , - , x ,

- mental

calculation- accurate

answer

2 marks- 10 question

- working.

- accurated

questions- complete

calculation

3 marks

- 5 questions

- working

- more than 2

operations

- marks forevery step.

- accurate

answer


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NUMBERs Write number

Digit value

Place value Round off

Write number in word


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Nyatakan nilai digit bagi 5 dalam

nombor 45 306 ?

4 5 3 0 6othThTTh

50001 mark

State the digit value of5 in 45 306?2


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Tuliskan dalam perkataan bagi nombor :

30 580

thousands

Thirty Five hundred and eighty

Thirty thousands five hundred

and eighty

Write 30 580 in words.3

f 49 012


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Bundarkan 495 012 kepadapuluh ribuyang

terdekat

hth tth th h t o4 9 5 0 1 25 0 0 0 0 0

+1

1 mark

Round of 495 012 to the nearestten thousand.4

5


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5 Write seventy-three thousand andfifty in numerals.

Tulis angka bagi tujuh puluh tiga ribulima puluh.

oththtth

05037

1 mark


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BASIC OPERATIONS Addition

Multiply

Subtract Divide

1


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700 thousands + 65 hundreds + 85 tens=

700 000

6 500085+

707 350

1 mark

1

2


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108 x 40 =

108X 40

000

1 mark

432

4320

2

3


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5068 + 547 + 1542 =5068

5475615

+

3

5615+ 1542

7157

4


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6003 x 23 =

6003X 23

18009

1 mark

12006

138069

4

5


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5

83 407

1 mark

945 1 826=

83 407 945

82 462 =82 4621 826

80 636


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MIXED operation

Subtract and divide

Add and Subtract

Divide and multiply

( Add ) and divide Add and multiply

48 96 12

1


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48 + 96 12 =

9612 968

0096

48

+ 856

1 mark1 mark

1

2


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321 + 64 x 12 =

64

12x128

64768

321

768+1089

1 mark

1 mark

2

J=1098


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1 735 689 + 974


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1 735689 + 97 =

1 mark

4

1 735

689

2 1

6

61

401

1 046

+ 973

1

411


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FRACTIONS

Write in words

Multiply

Subtract

fractions

Fractions to

decimal number

Fractions line Addition

fractions

Equivalentfractions Fractions to

percentage

Diagram and

write in

simplest form

2 41


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12

5

4

5

=

7

5

4

5

=3

5

1 mark 1 mark

1


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15

3


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Tukarkan kepada nombor bercampur15

7

1572

141 2

1

7

1 mark

Convert to a mixed number15

7

3

3


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15- 7

8- 7

1

= 2

1

7

3

4


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1

3

4

+

4

9 =

1 x 3

3 x 3 +

4

9 =

3

9 +

4

9 =

7

9

1 mark

1 mark

5


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5What is the fraction of the shaded region of the figure?

Berapakah pecahan kawasan berlorek daripada seluruh rajah ?

5

25=

1

5

1 mark 1 mark

6


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6

Write in word

3

8 =

Three over eight

Tiga per lapan

@1mark


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DECIMAL Subtract

Divide

Addition

Multiply

Decimal to % Decimal tofraction Mixed numberto decimal

1


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Tukarkan 0.057 kepada pecahan.

3 tempat perpuluhan

57

10001 mark

State 0.057 to fraction.1

2


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Tukarkan 0.04 kepada peratus.

2 tempat perpuluhan

1 mark

x 1004

100

= 4 %

Express 0.04 to percentage.2

3


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178 8273 =

1 7 8

- 8 2 7 3

0 07 9 10

725

10

9

1 mark1 mark

3

4


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4

0.427 7 =

04277

006

42

7

1

7000

1 mark

1 mark

6


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614

1

x 208802

41238

802

x+

2192

96 374 + 852 =7


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96374 + 852 =

1 mark

7

9 6

3 7 40

5 1

6

8 1

85

685

+ 58 2 060

1

1

1

9


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MONEY Money table

Diagram ofmoney and

problem solving

Addition Price listtable

Problemsolving andshopping list

1


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Money RM50 RM10 RM5 RM1 10 sen

Quantity 3 5 3 4 7

Total RM150 RM50 RM15 RM4 RM0.70

1 mark

atau

RM 219.70

RM 150.00RM 50.00RM 15.00RM 4.00

RM 0.70+1 mark

1


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3


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RM45.90

RM299

Berapakahperbezaanharga di antara dua

barangan di atas ?

RM 299.00- RM 45.90

RM 253 10

1 mark

1 mark

What is the difference in theprice of the two items ?

3

4


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RM855 sen + RM3.95 =

RM 8.00RM 0.55

RM 7.45

RM 7.45RM 3.95+

RM 11.40

1 markah 1 markah

4

5


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5Item Watch Hat

Price per unit RM59.60

Fuad bought a watch and 4

hats at the cost of RM93. What

is the cost of one hat?Fuad membeli seutas jam tangan dan

4 buah topi dengan jumlah harga RM93.

Berapakah harga bagi sebuah topi ?( RM 93.00 RM 59.60 ) 4 =

5


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( RM 93.00 RM 59.60 ) 4 =RM 93.00

RM 59.60RM 33.40

RM 33.40RM 8

32.

4

35

1

201 22 0

5

6


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6

RM50

1 mark

265 sen

RM50.00RM 2.65

549 9 0

3M4

7 Johan has RM84. Ahmads


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Johan has RM84. Ahmad s

money is of Johan money.4Calculate the total amount oftheir money.Johan ada RM84. Wang Ahmad adalah

daripada wang Johan.3

4Kirakan jumlah wang mereka.

7 Johan money RM84


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Johan money = RM84

Ahmad money

=

RM84

3

4Johan money

=3

4x

21

1

= RM63

TotalRM 84

+ RM 63RM147


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PERCENTAGE Value of percentage

Percentage to decimal Table and problem solving

Calculate percentage

1


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30% of 150 =30

100

150 = 45

1 mark1 mark

2


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Rajah terdir i daripada beberapa petak segi empat sama

yang sama besar. Berapakah bilangan petak yang

mewaki l i 40% dar ipada seluruh rajah itu ?

The diagram consits of squares of equalsize. How many of the squares represents40% of the whole diagram ?

2


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40 % = ?

40

100

X 15 =

5

2 3

1

6square

1 mark

1 mark

Shadedregion

Number of3


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village Perdana CarsX 6Y 14Z 5

Berapa peratuskah bilangan kereta perdana diKampung X, berbanding semua kereta perdana

di tiga kampung itu?

What is the percentage of the Perdanacars in the village X compared to all thePerdana cars in three villages ?

3


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6 x 100

6 + 14 + 5

=600

25 = 24%

1 mark1 mark


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5 Diagram 9 consists of several


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squares of equal size .Rajah 9 terdir i daripada beberapa segiempat

sama yang sama besar.Calculate the percentage of

the coloured region of the

whole diagram.

Hitung peratusan kawasan

berwarna daripada seluruhrajah itu.

5 Percentage coloured region.


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g g

6 x 10015= 600151

0= 40%

6 Diagram 16 shows the volume of a


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barrel petrol.

Rajah 16 menunjukkan isipadu setong petrol.

Chin Seng menjual 70%

daripada petrol itu.Berapakah isipadu, dalam ,

petrol yang masih ada?

45l

Chin Seng sells 70% of

the petrol.

How much of the volume,in l, of petrol is left?


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AVERAGE Divide by 3 Total Volume of

liquid & divide 4

Find the valueof X , averagegiven

1


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HostelsNo. of

residents

P 50

Q 40

R

Bilangan penghuniasrama R adalah sama

dengan bilangan

penghuni asrama P danQ. H itungkan purata

bilangan penghuni

sebuah asrama.

The number of resident for hostel R is

the same as P and Q. Calculate theaverage number of residents for each

hostel.

Averagenumber of hostels residents


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Puratabil penghuni asrama

Hostel No. ofresidents

P 50

Q 40

R

Total P + Q= 90

90

50

40+ 90

180

180 3 = 60

1 mark 1 mark

1 mark


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Number of bird in all the zoos =


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43 x 4 = 172 ekorNumber of bird X in Zoo P+Q+S =

7+93+13= 113

Number of bird X in zoo R =

172

113

59


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4


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Days Mondays Tuesday Wednesday

Numberof egg 78 125 91

Average

=78 + 125 + 91

3=

294

3

= 98


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35 i t3 hours

1


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30 minutes

4 hours 5 minutes

1 mark

3 hours

35 minutes3 hours

1 mark+

65 minutes

-60 minutes+ 1 hours


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4


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Convert 2235 hours tothe 12-hour system.Tukarkan Jam 2235 kepada

sistem 12 jam.

2235 1200

= 10.35 p.m.@

10 35 at nigh= 5

1


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Calculate 5 hours 15 minutes + hour.Write your answer in hours and minutes.

1

4

H itungkan 5 jam 15 minit + jam.

Ber ikan jawapan, dalam jam dan mini t.

1

4

1

4

hour

= 15 minutes

5 hours 15 minutes

+ 15 minutes30 minutes5 hours

3 Diagram 2 shows the time on aclock face in a morning.


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clock face in a morning.

Rajah 3 menunjukkan waktu pada sebuah muka jam

pada suatu pagi.

State the time shown on the clock face.

Nyatakan waktu yang ditunjukkan pada muka jam itu.

6

12

39

6.30 a.m.

@

0630 hours


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1812

Time training starts


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6

12

39

4.25 p.m.

Training takes90 minutes

Time training endhours minutes

4 25

+ 901154

- 60+ 1

555

5.55 p.m.

@

1755 hours


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1812

Time training starts


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6

12

39

4.25 p.m.

Training takes90 minutes

Time training endhours minutes

4 25

+ 901154

- 60+ 1

555

5.55 p.m.

@

1755 hours


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LENGTH Ruler (High of pupils)

Subtract(km m) Ruler(length of object)

Problem solving Addition

(km + m)


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of a piece of rope measur ing32


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dar ipada seutas tal i

yang panjangnya 20 meter

telah dipotong. Kirakan

panjang tali selepas dipotong.

3

5

ofa piece of rope measur ing

20 meter was cut. Calculate the length

of the rope after it was cut.

5


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24.6 km3


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P

Q

34

daripada PQ telah diturap.

Cari panjang jalan yangbelum diturap

dalam m ?

3

4

Of PQ had been paved.

Calculate the length, in m, of the

road that had not been paved

24.6 km = 24600 m

3


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24.6 km =24600 m

Unpaved =

x 24600m

1

6 1 5 0

= 6150 m

14

1

4

1 mark

1 mark

1 mark


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5 Calculate 2 m 7 cm 9 .


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72

3

7

Give the answer, in cm .Hitung 2 m 7 cm 9.

Ber ikan jawapan, dalam cm.

2 m= 200 cm

7 cm7 cm+

207 cm

207 cm92

182

00

cm


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MASS Weighing machine ( kg & g )

Subtract Problem solving Multiplication

Addition / Divide Diagram 1 shows the mass of a1


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Rajah 1 menunjukkan berat sebij i mangga.

Berapakah berat, dalam kg, mangga itu ?

mango. What is the mass, in kg, ofthe mango ?

Reading


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mass250 g

5=50 g

50 g

50 g 250 g50 g

+ 50 g350 g=0.350 kg

2


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H itungkan 305 kg500 g.

Nyatakan jawapan, dalam g.

Calculate 305 kg 500 g.State your answer, ing.

3.05 kg 500 g = ? g


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3050 g

500 g2550 g

1 mark

1 mark1 mark

3


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1

2

3

456

7

8

9 0

kg 1

23

4

0

kg

What is the difference of themass, in g, of the two fruits?Berapakah perbezaan berat, dalam g,

kedua-dua buah-buahan tersebut ?

3


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Mass of watermelon= 6.5 kg = 6 500 g

Mass of pineapple= 1.5 kg = 1 500 g

The difference6 500 g 1 500 g5 000 g

1 mark

1 mark

1 mark

4 Vijaya has 3.75 kg of flour.

Sh d 4 2 k f fl t


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She needs 4.2 kg of flour to

bake cakes.

Vijaya ada 3.75 kg tepung. Dia

memerlukan 4.2 kg tepung untuk

membuat kek.

How much more flour, in g,

does she need ?

Berapakah jisim tepung, dalam g, yang

diper lukan lagi?

4 Need flour = 4.2 kg


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Has flour= 3.75 kg

g

Need more flour in g4200 g

3750 g450 g @

4.2 kg 3.75 kg0

0.45 kg=450 g

VOLUME OF LIQUID


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Beaker problemsolving (ml)

Beaker ml / l Addition / Subtract Divide ml

Volume of water in a bottle is2


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Isipadu air dalam botol ialah 1.5 l.

daripadanya tumpah.

Berapakah baki isipadu air, dalam ml,dalam botol itu ?

2

5

1.5 l. of it split.

What is the volume, im ml, of

water left in the bottle ?

2

5

1


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1.5 ( l ) liter

1


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1.5 ( l ) liter

split = mlleft ?25

1500ml3

5

1500mlx

300= 900 ml

1 mark

1 mark

1 mark

8.4 lof water is poured2


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8 4 air dituang sama banyak ke

dalam 5 buah botol. Berapa isipaduair dalam , bagi setiap botol itu ?

equally into 5 bottles.

What is the volume, in l, of

a water in each bottle ?

2


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8.4 l51

53

.

4

6

3 0

4

0

0

8

40

l 1 mark

1 mark


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3

4


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4

5

x 1.85 l

= 1 850 ml

4

5

x 1 850 ml

=

370

1480 ml1

4 2 l


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1 l

The water in the beaker is poured

equally into 4 beakers.What is the volume of water, in ml, in

each beaker ?

Air di dalam bekas itu dituang samabanyak ke dalam 4 buah bekas lain.

Berapakah isi padu, dalam ml, setiap bekasitu ?


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SHAPE AND SPACE Draw

Naming

Characteristics of cuboid- number of vertices


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b)a)Namakan setiap bentuk berikut :


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b)a)

Piramid bertapak segiempat samaSegitiga bersudut tegak

1 markah1 markah

Right angled triangleSquarebased pyramid


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10 cm10 cm

10 cmEquilateral triangle

Segitiga sama sisi


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7 cm

squareSegiempat sama


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7 cm

rectangleSegiempat tepat

5 cm


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Berdasarkan gambarajah, namakan bahagian-

Base on the diagram, name the parts shown.


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Berdasarkan gambarajah, namakan bahagian

bahagian yang ditunjukkan.

Bulatan /Circle

Pusat Bulatan /Centerpoin t

Jejari /Radius

Diameter

PERIMETER


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Diagram Diagram

(composite shape)triangle and rectangle

P U

T

6 cm1


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Q R

T

S

5 cm

Dalam rajah 2, PQRU ialah segi empat sama. UTR

dan QRS ialah garislurus.Hitungkan perimeter

rajah itu ?

PQRU is a square. RST is an isosceles

triangle with sides, 3 cm. The perimeter of

the region is

P U6 cm

3 cm6 cm3 cm

1


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6 cm

Q R

T

S

3 cm

5 cm

3 cm

5 cm9 cm6 cm+

29 cm

1 mark1 mark

6 cm

3 cm

3 cm

P Q12 cmV

1


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9 cm

RS3 cm

TU

PQRS ialah segiempat tepat.

TUV segitiga sama sisi bersisi 8 cm.

Perimeter kawasan berwarna ialah

PQRS is a rectangle.

TUV is an equilateral triangle with sides 8 cm

The perimeter of the shaded region is ..


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3 Diagram 14 shows a combonition of atriangle PQU and a rectangle URST. PUTand UQR are straight line. PU = UT .


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Rajah 14 menunjukkan gabungan sebuah segitiga

PQU dan sebuah segiempat tepat URST. PUT dan

UQR ialah garis lurus. PU = UT.P

Q R

ST

5 cm3 cm

4 cm

U

10 cm

What is perimeter, in cm,of the whole diagram?

Berapakah

perimeter, dalam

cm, seluruh

rajah itu?

3 PU = TU


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P

Q R

ST

5 cm3 cm

4 cm

U

10 cm

3 cm 3 cm

6 cm

Perimeter =

3 cm3 cm

10 cm

3 cm6 cm5 cm+

30 cm


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A B10 cm1


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D7 cm

ABCE =(rectangle) Segiempat tepat

ADE =(right triangle) Segitiga bersuduttegak

Luas kawasan ber lorek ?

4 cm

CE

4 cm

Area of shaded region ?

Area of shadedregion = Area ABCD Area ADE


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= 10cmx 4 cm= 40 cm2Area ABCD

Area ADE=

7 cm x 4 cm

2 =

28 cm

2

= 14 cm2

Area ofshededregion

= 40 cm2 14 cm2

= 26 cm2


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MATEMATIK KERTAS 1


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MATEMATIK KERTAS 1

40 questions Time 1 hour (60 minutes) 90 second for 1question Questions are in English & Bahasa Melayu Objektive Answer options given A , B , C , D Covers all topics About 75% of the items are Creative andCritical Thinking Skills based


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IMPORTANT TOPICS


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2 & 3 Dimension Money Time & Duration Fractions Percentage Decimal An average 4questions for

every topic

1 50% = (in decimal)

21

5=X 60

0.512


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5

3 0.7 + 3 =4 0.25 kg = (in gram)

5 RM1.60 = (in sen)

6 4.30 p.m. = (24-hour system)

71

5= (in minutes)

8 0.6 l + 4 l =

9 1.4 x 10 =

10 180% =(pecahan

bercampur)

jam

3.7250160Jam 1630124.6 l @ 4600 ml141 80100@ 1

45


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Have targets and goals


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Be confident and proud

of yourself WHOLE NUMBERS


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Converting fraction or decimalsnumbers to whole numbers4operation

Problem solving / estimateNumber line

1. 305 million =3 05 j t


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305 juta =A 30 500

B 305 000C 3 050 000

D 30 500 000

Million7 digit

Answer 2 1.005 mil = 1 005 000

3


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A 3 465 000

B 3 355 000

C 2 785 000

D 2 676 000

3

4mil = 750 000

0.21 mil = 210 000

12

mil1 = 1 500 000 +

5 0006

A


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Nearest hundred thounsands7 400 000


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7 400 000

A 7 459 271

00 000

+ 1

7 5

X B 7 452 70400 000

+ 1

7 5

X

C 7 354 301

00 000

+ 1

7 4 C

6. From the followingmultiplication, which one

i th l b t


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gives the value between

50 000 and 55 000 ?

A 680 x 80B 700 x 70C 760 x 60D 800 x 50

680X 800

654A

7. 12


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6090380A 11280Remainder 8B 11280Remainder 38C 12180Remainder 8D 12180

50109100 xxD

8 + 705.38 = 1 02510


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A 319.62B 320.38C 324.62D 1 730.38

1025.00

705.38

x

4 9 10

2x 6.

10

9

Answer A


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MIXED OPERATION


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1. Mains skills

BODMAS RULE

a. If there is a ( ), solve the numbers inthe bracket first

b. ( + followed - @ - followed +, solve fromleft to right )

c. ( + followed x @ + followed , solve xorfirst )

d. ( - followed x @ - followed , solve xor first )

2. Problem solving follow the sentencesgiven

10 5 000 107 x 23 =


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A 2 539B 3 461C 112 539D 117 461

107

X 232114

5000

2461

- 2461XX 9

FRACTION


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Proper fractions Equivalent fractions and

state in simplest form

Find a commondenominator ( for + & -operations )

Convert to decimal orpercentage

Fraction with quantity


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12. 7 2 4 1 =7 4 4 7


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7 2

2 31421114

3 314311

14 14=3 414 714 =21814 714xx

=21114B


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Always bealert and thenwait. Perhaps

what you'relooking for,

will find you...

131

22

1

y

14

15

16 2 2

22

3


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12

3

21

6

2

1

6A

213

B

2

1

2C

223

D

14

6

15

6

16

6

2 22

6

23

6

236

= 212

C

14. 4180X Y 4210


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35 of the total ofXandYisY(4210 4180) 2= 30 2 = 15

= 4180 + 15= 4195

X

4180 (15 x 4 )=4180 60= 4120A 4120 C 4989x

1315


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Diagram 2 consists of several equailateral triangles ofequal size.Cikgu Azlan ask Maziana to shade of the wholediagram.

How many more equailateral triangles should she shade ?

A 7B 8C 9D 10

3

4

57

15


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Shade =34 x 16 = 12

Have shade = 512

57 A

DECIMALS


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Converting fractions or

percentage to decimal.

Place value in decimals.

Operations with decimals

numbers

Number up to 3 decimals

place.

Ex : 2.08 + 14 - 7.495 =

16


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11.200+ 17.075A 27.071B 23.415C 23.135

28.27528.275

5.1405xx

3

C

17 617

1000

4

1004 =


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1000 100

A 2.13

B 2.013C 1.977

D 1.617

6.0174.040X

7

X5 9 10

7


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2010

14

5.024 + 115

1000


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A 6.354

B 6 376

C 6.249

D 6.241

10.250

- 5.0245.226

5.226

+ 1.0151

D

21 903 %


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A 9.3B 9.03C 0.93D 0.903903100 = 9.03

B

TIME & DURATION

1. 24 hour system :


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- before ( - )- after ( + )2. Conversion of unit of time- hour minute second

( x 60 @ 60 )3. Calendar / age- Month week day- Year month4. Diagram analog clock5. Problem solving

22 hours + 3 hours 50 minutes =910


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jam + 3 jam 50 minit =910

A 3 jam 59 minit

B 4 jam 4 minit

C 4 jam 40 minitD 4 jam 44 minit

22 jam + 3 jam 50 minit =910


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A 3 jam 59 minitB 4 jam 4 minit

C 4 jam 40 minitD 4 jam 44 minit

j m

3 50

54+1043

x60 -+ 1

44

23. Diagram 3 shows the timeEncik Halim returned from


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the night market.

1 hour 25 minutes later,he watched television.

State the time, in the 24-

hour system, he started towatch television.

23. Returned from the night market.11.15 pm = 2315 hrs


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1 hour 25 minuteslater

watch tvhours minutes

23 15

+ 1 25 +4024

A 0040 hrsB 0950 hrsC 1240 hrsD 2150 hrs 24 00

00 40

A-


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Don't letthe situation

confuse you...


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25 4 l 75 ml1


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+ 195 ml

A 4270 mlB 4345 mlC 4750 mlD 6700 ml

4000 ml +

x0x 7

A

26 7 l 70 ml + 4 l140 ml =


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A 11.084 lB 11.11 lC 11.21 lD 11.84 l

7.070 l+ 4.140 l0

x1

x

1

2

25 ml +027l + 4l15ml +755ml= .... l27


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0.025 l0.270 l4.015 l0.755 l5.065 l C


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293

0.750 l=


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0.750 l3

8 750ml

Left

83

8

=5

8

3

8= 750ml

1

8= 250ml

= 250x5 = 1250ml

DA 1.25B 2.5

C 125

D 125O

XX

MASS


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Main Skills :

- Conversion of units ( multiply &divide )

kg g = x 1000

g kg = 1000

- Involving four operation

- Very good at reading graduation( senggat ) & weighing machine

30 Convert 6kg 25g to kg.6 kg = 6000 g


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6 kg

+ 25 g

= 6000 g

6000 g

6025 g

A 62.5

B 6.25

C 6.025

D 0.625

6025 g

= 6.025 kg

Cx


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Always look at where you'regoing...


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31. Which of the following is theheaviest ?Antara ber ikut, yang manakah paling


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Antara ber ikut, yang manakah paling

berat ?

A 5

1

2 kg

B 5

1

4 kg

C 5

3

5 kg

D 5

3

10kg

A 51

2kg = 5 500 g


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B 5 14

kg

C 5 35

kg

D 5 310

kg

= 5 250 g= 5 600 g

= 5 300 g Answer

321325 g = 1.325 kg


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0000

0.120

1.325+ 1.445

1.44520x

A 28.9

B 26.74

C 26.62

D 26.592

28900

28.900


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33. Mr. Rajesh sold 24 papayas toPuan Rohaya. The mass ofone papaya is between 340 g


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to 650 g.Estimate in kg, the mass of allthe papayas bought by PuanRohaya.

Encik Rajesh menjual 24 bij i buah betik kepada Puan

Rohaya. Berat sebij i buah betik adalah di antara 340 ghingga 650 g.

Anggarkan berat, dalam kg, semua buah betik yang dibeli

oleh Puan Rohaya.


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34 35 m 8 cm 4


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A 8.77 cmB 87.7 cmC 877 cmD 8770 cm

3500 35088323xx C

35. Ironrod Lenght Lengthcm


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K 3700 mmL 360 cmM 3.8 mN 3.09 mK B L

C M D N

Which rod is theshortest ?

370360380309

D


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37AX BX


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0.12 kg

= 120 g

2l24ml

= 2.024l

C

2000 cm

= 20m = 0.02km

C

38


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760 m = 0.760 km+ 4.990 km

A 5 650

B 5 750

C 5.65

D 5.75

x

50 km7D

47kmPerpustakaan

Rumah En. Mail39


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850m

195km3km 250 m

Hospital

Pejabat Pos

1.95 km3.25 km0.85 km4.70 km

10.75 kmB

MONEY


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Mains Skills- Value of RM and sen, andconversion of units- Involving quantity, number ofobjects and total- The four operations & quantity- Calculation involving fractions &percentage- Selling & buying concept & profitand loss


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Kuantiti Alat Tulis Harga

seunit RM

Harga

RM

10 biji Pemadam 12.00.2041


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Kuantiti Alat Tulis Hargaseunit RM

HargaRM

4 btg Pen 1.60

3 kotak Warna Air

5 kotak Pensil 3.00 15.00

Jumlah 46.90

10 kotak PensilWarna

Jumlah 97.00

6.4025.50.50

8.50 85.00

AX

X

2 & 3 DIMENSIONAL SHAPE


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Main Skills- Characteristics 2-D and 3-D.

- Able to use formula of area,perimeter & volume

- Calculation of area, perimeter &volume from diagram

- Conversion of units andmeasurements

42

B D


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A C

Diagram 1 is drawn on

squares of equal size.

Among triangles A, B, C, and D,which one has the same base ?

43Vertex /Bucu 5

Flat surface / Permukaan rata 5


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Flat surface /Permukaan rata 5

A Pyramid


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44 Perimeter shadedregion = 28 cm1 side 28= = 4 cm


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A 72B 68

C 64D 60

7Perimeterunshaded region= 4 cm x 18

= 72 cmA


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45. X 180 Y 255 175

Total X + Y


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A 610B 465 C 310D 155

= 215 x 5= 1075

= 1075 (180+255+175)= 1075 610 = 465

xx

Y = 2X Y = 465 3= 155

D

46.Ain 84

Ilyani


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Zuidayana

849

= 75

75 + 15= 90Average84 + 75 + 90

3= 83 B

47 Sabrie = 900Haziq = 900150 = 750


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q 750

3 = 800 x 3 = 2400

Average = 900+750+24005

= 40505

= 810 A

48 TAJ = 524


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TS = 524 48 = 476Total

524

+ 4761000

10000

x 2020000

C

DATA HANDLING


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Main Skills- Skilful reading information &

pictograph

- Skilful with the four operations- Skilful at making comparison

and adding

- Skilful at finding informationand average

49 Malay English Science


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Mathematics Represents 15 minutes

The school holiday was1 week.How much time did Mohamad Azim

spend to study during the holidays?

49

Malay 15 x 5 = 75m

A 40h 15mB 38h 15m C 28h 45mD 27h 25m A


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English Science

Math Represents 15 minutes

75m

15 x 7 =105m

15 x 5 = 75m

15 x 6 = 90m

345m

+Total

One week= 7 days

Total345 X 7= 60 =

241560

= 40 hrs

50 One pipe = 5.5mTotal pipes


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P = 16Q = 20

R = 10S = 22

To = 68

x

5.5m

680

4400

33000

374.00 =

0.374 km


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CITA-CITA ANDA


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14A!


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10 A!

17A!

18A!

18A!17A!


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10A! 17A!


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17A!

18A!

17A!

18A!

14A!

,2007


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NewS

traitsTimesTue

sday,March13

,

18A!

15A!


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MURID YANG ..


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Dreamwhat you want to dream;

Go where you want to go;

Be what you want to be,

Because you have only one lifeand one chance to do all the things

you want to do.


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55 69

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63 79

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79 99

Ceramah Math Upsr

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